Campbell Biology (10th Edition)
10th Edition
ISBN: 9780321775658
Author: Jane B. Reece, Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Robert B. Jackson
Publisher: PEARSON
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Chapter 14, Problem 14.3CR
Inheritance patterns are often more complex than predicted by simple
Extensions of Mendelian genetics for a single gene:
Which genetic relationships listed h the first column of the two tables above are demonstrated by the inheritance pattern of the ABO blood group alleles? For each genetic relationship, explain why this inheritance pattern is or is not an example.
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In addition to the allelic pair determining pattern baldness in man (B,b), consider early baldness to be due to another autosomal allele (E) on a different pair of chromosomes and also dominant in males but recessive in females. The phenotype for ee may be late or nonbaldness depending on sex and the genotype for B, b alleles. Two doubly heterozygous persons marry.
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Chapter 14 Solutions
Campbell Biology (10th Edition)
Ch. 14.1 - DRAW IT Pea plants heterozygous for flower...Ch. 14.1 - WHAT IF? List all gametes that could be made by a...Ch. 14.1 - MAKE CONNECTIONS In some pea plant crosses, the...Ch. 14.2 - Prob. 1CCCh. 14.2 - Two organisms, with genotypcs BbDD and BBDd, are...Ch. 14.2 - WHAT IF? Three characters (flower color, seed...Ch. 14.3 - What two properties, one structural and one...Ch. 14.3 - If a man with type AB blood marries a woman with...Ch. 14.3 - WHAT IF? A rooster with gray feathers and a hen...Ch. 14.4 - Beth and Tom each have a sibling with cystic...
Ch. 14.4 - Prob. 2CCCh. 14.4 - Prob. 3CCCh. 14.4 - MAKE CONNECTIONS In Table 14.1, note the...Ch. 14 - When Mendel did crosses of true-breeding purple-...Ch. 14 - DRAW IT Redraw the Punnett Square on The right...Ch. 14 - Inheritance patterns are often more complex than...Ch. 14 - Both members of a couple know that they are...Ch. 14 - DRAW IT Two pea plants heterozygous for the...Ch. 14 - A man with type A blood marries a woman with type...Ch. 14 - A man has six fingers on each hand and six toes on...Ch. 14 - DRAW IT A pea plant heterozygous for inflated pods...Ch. 14 - Flower position, stem length, and seed shape are...Ch. 14 - Prob. 6TYUCh. 14 - The genotype of F1, individuals in a tetrahybrid...Ch. 14 - What is the probability that each of thc following...Ch. 14 - Prob. 9TYUCh. 14 - Prob. 10TYUCh. 14 - In tigers, a recessive allele of a particular gene...Ch. 14 - In maize (com) plants,a dominant allele I inhibits...Ch. 14 - The pedigree belowtraces the inheritance of...Ch. 14 - Imagine that you are a genetic counselor, and a...Ch. 14 - EVOLUTION CONNECTION Over the past half century,...Ch. 14 - SCIENTIFIC INQUIRY You are handed a mystery pea...Ch. 14 - Prob. 17TYUCh. 14 - SYNTHESIZE YOUR KNOWLEDGE Just for fun, imagine...
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- 3:48 1 Drive Multiple genes or polygenic inheritance: An additive effect of two or more genes on a single phenotypic character. 16. Skin color appears to be controlled by several genes. This creates a continuum of variation) also seen in height, hair color, etc.) If this polygenic explanation of the inheritance of human skin pigmentation is correct, how do the skin colors of the following four individuals compare? Which of the couples could have children with the widest range of skin colors? Why? Couple 1: aaBbCC and aaBbCC Couple 2: AaBbCc and AaBbCc Lethal Genes: An allele that if present, results in premature death. Lethal genes can be either dominant (heterozygotes or homozygous dominant will be affected) or recessive (only homozygous recessive will die). 17. When Mexican Hairless dogs are crossed with normal-haired dogs, about half of the puppies are normal (have hair) and half are hairless. When two Mexican hairless dogs are crossed, about 1/2 of the puppies are hairless, 1/4…arrow_forwardExplain, at the molecular level, why human genetic diseases oftenfollow a simple Mendelian pattern of inheritance, whereas mostnormal traits, such as the shape of your nose or the size of yourhead, are governed by multiple gene interactions.arrow_forwardIn his famous paper, Mendel writes that he set out to“determine the number of different forms in whichhybrid progeny appear” and to “ascertain their numericalinterrelationships.” How did his close attention tonumbers lead him to discover segregation and independentassortment?arrow_forward
- There is an autosomal gene in cats that controls whether or not they also have white patches of fur (W = white spots, w= no white spots). Considering this along with the Orange gene (O0 and OB) from the previous question, and how it works, how many possible genotypes (using these 4 alleles) are there for cats that are orange, black, and white (in other words, calico)?arrow_forwardWhat does Mendel’s law ofsegregation tell us about chromosomalinheritance?arrow_forwardWhy do unrelated children with a disorder such as Down syndrome resemble each other more closely than they do their siblings?arrow_forward
- A pedigree analysis was performed on the family of a man with schizophrenia. Based on the known concordance statistics, would his MZ twin be at high risk for the disease? Would the twins risk decrease if he were raised in an environment different from that of his schizophrenic brother?arrow_forwardFor Mendelian inheritance, the nuclear genotype (i.e., the allelesfound on chromosomes in the cell nucleus) directly influences anoffspring’s traits. In contrast, for non-Mendelian inheritance patterns, the offspring’s phenotype cannot be reliably predicted solelyfrom its genotype. For the following traits, what do you need toknow to predict the phenotypic outcome?A. Dwarfism due to a mutant Igf2 alleleB. Snail coiling directionC. Leber hereditary optic neuropathyarrow_forwardIn the 1800s, a man with dwarfism who lived in Utah produced a large number of descendants: 22 children, 49 grandchildren, and 250 greatgrandchildren (see the illustration of a family pedigree to the right), many of whom also exhibited dwarfism (F. F. Stephens. 1943. Journal of Heredity 34:229–235). The type of dwarfism found in this family is called Schmid-type metaphyseal chondrodysplasia, although it was originally thought to be achondroplastic dwarfism. Among the families of this kindred, dwarfism appeared only in members who had one parent with dwarfism. When one parent exhibited dwarfism, the following numbers of children were produced. Q. Use chi-square tests to determine if the numbers of children with each phenotype in family C (1 with normal stature, 6 with dwarfism) and in family D (6 with normal stature, 2 with dwarfism) are significantlydifferent from the numbers expected on the basis of your proposed mode of inheritance. How would you explain these deviations from the…arrow_forward
- Assuming brown eyes (B) are dominant over blue eyes (b), determine the genotypes of all the following individuals. The blue-eyed son of two brown-eyed parents marries a brown-eyed woman whose mother was brown eyed and whose father was blue eyed. Their child is blue eyed.arrow_forwardLabrador retrievers may be black, brown, or golden in color (seethe chapter opening photograph on p. 53). Although each colormay breed true, many different outcomes occur if numerous littersare examined from a variety of matings, where the parentsare not necessarily true-breeding. The following results showsome of the possibilities. Propose a mode of inheritance that isconsistent with these data, and indicate the corresponding genotypesof the parents in each mating. Indicate as well the genotypesof dogs that breed true for each color.(a) black * brown ¡ all black(b) black * brown ¡ 1/2 black1/2 brown(c) black * brown ¡ 3/4 black1/4 golden(d) black * golden ¡ all black(e) black * golden ¡ 4/8 golden3/8 black1/8 brown(f) black * golden ¡ 2/4 golden1/4 black1/4 brown(g) brown * brown ¡ 3/4 brown1/4 golden(h) black * black ¡ 9/16 black4/16 golden3/16 brownarrow_forwardWhat is the mode of inheritance of this pedigree and why?arrow_forward
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