Chapter 14, Problem 14.130MP

Interpretation Introduction

(a)

Interpretation:

The time required for 99.999% of the 2.0 M HCl by 2.0 M NaOH with equal volume needs to be determined. The second order rate constant is $\text{1}\text{.3}\times {\text{10}}^{\text{11}}{\text{ M}}^{\text{-1}}{\text{ s}}^{\text{-1}}$ at 25 °C.

Concept introduction:

The rate of reaction expresses the change in the concentration of reactant or product molecules with per unit time. There are different ways to express the rate of reaction such as instantaneous rate or average rate.

On the basis of different orders, reactions can be classified as first order, second order and third order reaction. For a second order reaction the relation between the concentration and rate constant can be written as:

$\frac{\text{1}}{\text{C}}\text{ = }\frac{\text{1}}{{\text{C}}_{\text{0}}}\text{+kt}$

Interpretation Introduction

(b)

Interpretation:

Whether the rate of the acid-base neutralization to be limited by the rate of reaction and speed of mixing needs to be determined.

Concept introduction:

The rate of reaction expresses the change in the concentration of reactant or product molecules with per unit time. There are different ways to express the rate of reaction such as instantaneous rate or average rate.

On the basis of different orders, reactions can be classified as first order, second order and third order reaction. For a second order reaction the relation between the concentration and rate constant can be written as:

$\frac{\text{1}}{\text{C}}\text{ = }\frac{\text{1}}{{\text{C}}_{\text{0}}}\text{+kt}$