To show that K c = K p RT Concept introduction: Equilibrium constant ( K c ) : A system is said to be in equilibrium when all the measurable properties of the system remains unchanged with the time. Equilibrium constant is the ratio of the rate constants of the forward and reverse reactions at a given temperature. In other words it is the ratio of the concentrations of the products to concentrations of the reactants. Each concentration term is raised to a power, which is same as the coefficients in the chemical reaction . Consider the reaction where the reactant A is giving product B. A ⇌ B Rate of forward reaction = Rate of reverse reaction k f [ A ] =k r [ B ] On rearranging, [ A ] [ B ] = k f k r = K c Where, k f is the rate constant of the forward reaction. k r is the rate constant of the reverse reaction. K c is the equilibrium constant. Ideal gas equation is an equation that is describing the state of a imaginary ideal gas. PV =n RT Where, P is the pressure of the gas V is the volume n is the number of moles of gas R is the universal gas constant (R=0 .0821LatmK -1 mol -1 ) T is the temperature
To show that K c = K p RT Concept introduction: Equilibrium constant ( K c ) : A system is said to be in equilibrium when all the measurable properties of the system remains unchanged with the time. Equilibrium constant is the ratio of the rate constants of the forward and reverse reactions at a given temperature. In other words it is the ratio of the concentrations of the products to concentrations of the reactants. Each concentration term is raised to a power, which is same as the coefficients in the chemical reaction . Consider the reaction where the reactant A is giving product B. A ⇌ B Rate of forward reaction = Rate of reverse reaction k f [ A ] =k r [ B ] On rearranging, [ A ] [ B ] = k f k r = K c Where, k f is the rate constant of the forward reaction. k r is the rate constant of the reverse reaction. K c is the equilibrium constant. Ideal gas equation is an equation that is describing the state of a imaginary ideal gas. PV =n RT Where, P is the pressure of the gas V is the volume n is the number of moles of gas R is the universal gas constant (R=0 .0821LatmK -1 mol -1 ) T is the temperature
Solution Summary: The author explains that equilibrium is the ratio of the rate constants of forward and reverse reactions at a given temperature.
Definition Definition Study of the speed of chemical reactions and other factors that affect the rate of reaction. It also extends toward the mechanism involved in the reaction.
Chapter 14, Problem 14.100QP
Interpretation Introduction
Interpretation:
To show that Kc=KpRT
Concept introduction:
Equilibrium constant(Kc): A system is said to be in equilibrium when all the measurable properties of the system remains unchanged with the time. Equilibrium constant is the ratio of the rate constants of the forward and reverse reactions at a given temperature. In other words it is the ratio of the concentrations of the products to concentrations of the reactants. Each concentration term is raised to a power, which is same as the coefficients in the chemical reaction.
Consider the reaction where the reactant A is giving product B.
A⇌B
Rate of forward reaction = Rate of reverse reactionkf[A]=kr[B]
On rearranging,
[A][B]=kfkr=Kc
Where,
kf is the rate constant of the forward reaction.
kr is the rate constant of the reverse reaction.
Kc is the equilibrium constant.
Ideal gas equation is an equation that is describing the state of a imaginary ideal gas.
PV=n RT
Where,
P is the pressure of the gas
V is the volume
n is the number of moles of gas
R is the universal gas constant (R=0.0821LatmK-1mol-1)
In the solid state, oxalic acid occurs as
a dihydrate with the formula H2C2O4
C+2H2O. Use this formula to
calculate the formula weight of oxalic
acid. Use the calculated formula
weight and the number of moles
(0.00504mol)
of oxalic acid in each titrated
unknown sample recorded in Table
6.4 to calculate the number of grams
of pure oxalic acid dihydrate
contained in each titrated unknown
sample.
1.
Consider a pair of elements with 2p and 4p valence orbitals (e.g., N and Se). Draw their
(2p and 4p AO's) radial probability plots, and sketch their angular profiles. Then, consider these
orbitals from the two atoms forming a homonuclear л-bond. Which element would have a
stronger bond, and why?
(4 points)
Write the reaction and show the mechanism of the reaction. Include the mechanism
for formation of the NO2+
2. Explain, using resonance structures, why the meta isomer is formed. Draw possible
resonance structures for ortho, meta and para.
Chapter 14 Solutions
OWLv2 for Ebbing/Gammon's General Chemistry, 11th Edition, [Instant Access], 1 term (6 months)
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell