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Practice ProblemATTEMPT
Calculate the vapor pressure of a solution made by dissolving 115 g of urea
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Chemistry
- 3) Calculate the freezing point (oC) of a solution of 15.46 g of acetone (CH3COCH3, MM = 58.08 g/mol) in 85.0 g of CCl4, whose normal freezing point is –23.0 oC. Given: P = 1 atmKf CCl4 = 29.8 oC/m a) –55.6 b) –93.3 c) 35.7 d) –76.4 e) 70.3 f) –116arrow_forwardSubmit Answer If 22.2 grams of an aqueous solution of calcium acetate, Ca(CH3COO)2, contains 4.73 grams of calcium acetate, what is the percentage by mass of calcium acetate in the solution? % Ca(CH3COO)2 282 F4 % 5 T G F5 B Retry Entire Group Cengage Learning Cengage Technical Support Y H [Review Topics) [References] Use the References to access important values if needed for this question. S & 6 i 7 MacBook Air F6 N 9 more group attempts remaining U F7 J 8 M I DII K ( 9 DD F9 O L ) O A F10 P : ; command option 4 F11 { [ ? 1 Previous + 1 Save and Exit 4) Next> F12 } ] S Relaunch to update delete + return shift Ⓒarrow_forwardWhat is the total vapor pressure of a solution containing 35.8 g benzene (C6H6, molar mass = 78.11 g/mol) and 56.7 g toluene (C7H8, molar mass = 92.14 g/mol) at 25.0 °C? (Given: P°benzene = 95.1 mm Hg, P°toluene = 28.5 mm Hg) Select one: a. 17.2 mm Hg b. 41.3 mm Hg c. 56.9 mm Hg d. 25.7 mm Hgarrow_forward
- What is the total vapor pressure of a solution containing 35.8 g benzene (C6H6, molar mass = 78.11 g/mol) and 56.7 g toluene (C7H8, molar mass = 92.14 g/mol) at 25.0 °C? (Given: P°benzene = 95.1 mm Hg, P°toluene = 28.5 mm Hg) Select one: a.17.2 mm Hg b.25.7 mm Hg c.56.9 mm Hg d.41.3 mm Hgarrow_forwardA solution is prepared by mixing 50.0 mL of ethanol (C2H5OH; molar mass = 46.068 g/mol) in 100.0 mL of water at 20oC. The density of water and ethanol at 20oC are 1.00 g/mL and 0.789 g/mL, respectively. What is the molality of ethanol? (A) 0.086 m (B) 0.094 m (C) 1.24 m (D) 8.56 marrow_forwardA solution is composed of 0.431 mole of glycerin (C3H5(OH)3), which is a nonvolatile solute, in 50.0 g of water (molar mass = 18.02 g/mol). What is the freezing point of the solution? (The freezing point depression constant for water, Kf = 1.86 °C/m) (A) 0.80 °C (B) -8.62 °C (C) -16.0 °C (D) 8.62 °Carrow_forward
- a2 18. If 0.1 M H2SO4(aq.) solution shows freezing point -0.3906°C then what is the K₁₂ for H2SO4? (Assume m = M and Kƒ(H₂O) =1.86 K kg mol-¹) siqob (a) 0.122 (c) 1.11x 10-3 -3 1.0-8.0 (b) 0.0122 (d) None of these luppo colution What osmoticarrow_forward٩arrow_forwardCalculate the freezing points of 0.17 m glycerol in ethanol and 1.92 mol of naphthalene, C10H8, in 16.8 mol of chloroform, CHCl3. (Kf(ethanol)=1.99, Kf(CHCl3)=4.68) (A) -114.3oC and -59.0oC(B) -114.3oC and -63.5oC(C) -114.9oC and -68.0oC(D) -114.9oC and -64.0oC(E) -114.3oC and -64.0oCarrow_forward
- 4Aarrow_forwardCalculate the molality of each of the following solutions:(a) 0.710 kg of sodium carbonate (washing soda), Na2CO3, in 10.0 kg of water—a saturated solution at 0°C(b) 125 g of NH4NO3 in 275 g of water—a mixture used to make an instant ice pack(c) 25 g of Cl2 in 125 g of dichloromethane, CH2Cl2(d) 0.372 g of histamine, C5H9N, in 125 g of chloroform, CHCl3arrow_forwardExplain the following :(i) Henry’s law about dissolution of a gas in a liquid(ii) Boiling point elevation constant for a solvent(b) A solution of glycerol (C3H8O3) in water was prepared by dissolving some glycerol in 500 g of water. This solution has a boiling point of 100.42°C. What mass of glycerol was dissolved to make this solution?(Kb for water = 0.512 K kg mol-1)arrow_forward
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning