Chapter 13.3, Problem 3CYU

(a)

To determine

To Compare:Range of the fruits to the range of the vegetables.

Answer to Problem 3CYU

The range of the fruits is greater than range of the vegetable

Explanation of Solution

Given: The number of calories in a serving of a certain fruits and vegetables in shown below.

  

Compare the fruits range with the vegetables range.

For fruits:

Highest vale = $80$

Lowest value = $50$

Range = Highest value − lowest value

  $\begin{array}{l}=80-50\\ =30\end{array}$

For vegetables:

Highest vale = $50$

Lowest value = $30$

Range = Highest value − lowest value

  $\begin{array}{l}=50-30\\ =20\end{array}$

Thus

The range of the fruits is greater than range of the vegetable.

(b)

To determine

To Find:The outliers in the data

Answer to Problem 3CYU

No outliers

Explanation of Solution

Given: The number of calories in a serving of a certain fruits and vegetables in shown below.

  

Determine any outliers. How do the outlier affect the measures of central tendency for the number of calories in fruits?

For median:

Arranging the data in ascending order.

  $\begin{array}{l}30,35,35,\underset{\_}{40,40},40,45,50\\ median=\frac{40+40}{2}=40\end{array}$

Median $40$

Then

Lower quartile = $35$

Upper quartile = $45$

Interquartile= Upper quartile − lower quartile

  $\begin{array}{l}=45-35\\ =10\end{array}$

Multiply the interquartile range by $1.5$

  $10\times 1.5=15$

Subtract $15$ from the lower quartile and $15$ to the upper quartile

  $\begin{array}{l}35-15=20\\ 45+15=60\end{array}$

Hence there is no outliers.