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Concept explainers
To find: The measure of variation and any outliers for the given set of data
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Answer to Problem 1CYU
Range is 145
Median is 110
Lower quartile is 83.5
Upper quartile is 145
Interquartile range is 61.5
No outliers
Explanation of Solution
Given:
The number of minutes spent bike ridings are
Calculation:
The given data is
Arrange this set of the data in numeric order
Hence, the range is given by
The median is 110
The lower quartile is the median of the left half of the data.
So, lower quartile is given by
The upper quartile is the median of the right half of the data.
So, upper quartile is given by
Therefore, the interquartile range is given by
Now, outliers are the data which is below
So, find the value for these expressions
And
So, the outliers are the value which is below
There is no value in the given set of data in this interval.
So, there are no outliers.
Chapter 13 Solutions
Pre-Algebra Student Edition
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