Chapter 13.10, Problem 40SR

a.

To determine

The length of the median of day for the planets.

  

Answer to Problem 40SR

The length of the median is $M_d=20.5$

Explanation of Solution

Given:

  

Calculation:

Observe that the length of the days on every single planet.

First arrange the data in the ascending way as follows and then divided into two equal parts. So the average of the middle two numbers is the median.

  $10,11,16,17,24,25,1416,5832$

So based on this median is,

  $\begin{array}{l}{M}_d=\frac{17+24}{2}\\ M_d=\frac{41}{2}\\ M_d=20.5\end{array}$

Conclusion:

Hence the median is $M_d=20.5$

b.

To determine

The outliners of the data and name of them.

Answer to Problem 40SR

There are two outliers in the data as Mercury and Venus.

Explanation of Solution

Given:

  

From the data observe that there are two outliers in the data.

They are Mercury and Venus.

Conclusion:

Hence there are two outliers as Mercury and Venus.

c.

To determine

The sentence to describe the length and include the statement.

Answer to Problem 40SR

The lengths of the days are varied from Earth to Neptune is a little change but the Mercury and Venus are varying a big amount of the days

Explanation of Solution

Given:

  

The lengths of the days are varied from Earth to Neptune is a little change but the Mercury and Venus are varying a big amount of the days.

These two planets are affects more on the remaining planets.

Conclusion:

Hence The lengths of the days are varied from Earth to Neptune is a little change but the Mercury and Venus are varying a big amount of the days.