Chapter 13.10, Problem 14PPS

To determine

The probability ofoutcome of candies.

P (a blue and then green candy)

Answer to Problem 14PPS

The probability of outcome of candiesis P (a blue and then green candy)= $\frac{1}{8}$

Explanation of Solution

Given:

Blue: $6$

Red: $3$

Green: $5$

Yellow: $2$

Total Candies: $6+3+5+2=16$

Calculation:

Fraction Form:

So getting the probability of the blue candy first and then green candy in this form is as,

P (First candy is blue) = $\frac{6}{16}=\frac{3}{8}$

P (Second candy is blue) = $\frac{5}{15}=\frac{1}{3}$

This is the probability after removing the $1$ blue candy is removed.

P (Blue and then Green candy) = P (Blue) * P (Green)

  $\begin{array}{l}=\frac{3}{8}\times \frac{1}{3}\\ =\left(\frac{3.1}{8.3}\right)\\ =\frac{3}{24}\\ =\frac{1}{8}\end{array}$

Conclusion:

Hence, P (a blue and then green candy)= $\frac{1}{8}$