The correct IUPAC name for the given compound has to be chosen from the given options. Concept Introduction: IUPAC nomenclature for alkene : There are about eight rules to be followed in giving IUPAC name for alkene. The suffix –ane has to be replaced with the suffix –ene. This is used to indicate the presence of double bond. The longest continuous chain of carbon atoms has to be chosen that contains both carbon atoms of the double bond. The parent carbon chain has to be numbered in a way so that the numbering begins at the end near to the double bond. In case if the double bond is equidistant from both ends, then numbering has to be done from the end that is closer to substituents. The position of the double bond has to be given a single number which is lower‑numbered carbon atom that is present in the double bond. Suffixes like –diene, -triene, -tetrene, and so on are used when the compound contains more than one double bond. In case of cycloalkenes which do not have any substitution, the numbering is not needed to locate the double bond because the bond is assumed to be between the carbons 1 and 2. In case if substituents are present in cycloalkene, then the double‑bonded carbon atoms are numbered 1 and 2 in a direction where the substituent gets the lower number. If the cycloalkenes contain more than one double bond, then one double bond is assigned the numbers 1 and 2 followed by the other double bond so that the lowest number possible is given.

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option choice: Isoleucine Histidine Threonine Alanine Lysine Aspartate Tryptophan Tyrosine Leucine Arginine Cysteine Asparagine Valine Glutamine Glycine Methionine Serine Proline Phenylalanine Glutamate

Answer 1

Question

Chapter 13.3, Problem 1QQ

Interpretation Introduction

Interpretation:

The correct IUPAC name for the given compound has to be chosen from the given options.

Concept Introduction:

IUPAC nomenclature for alkene: There are about eight rules to be followed in giving IUPAC name for alkene.

The suffix –ane has to be replaced with the suffix –ene. This is used to indicate the presence of double bond.

The longest continuous chain of carbon atoms has to be chosen that contains both carbon atoms of the double bond.

The parent carbon chain has to be numbered in a way so that the numbering begins at the end near to the double bond. In case if the double bond is equidistant from both ends, then numbering has to be done from the end that is closer to substituents.

The position of the double bond has to be given a single number which is lower‑numbered carbon atom that is present in the double bond.

Suffixes like –diene, -triene, -tetrene, and so on are used when the compound contains more than one double bond.

In case of cycloalkenes which do not have any substitution, the numbering is not needed to locate the double bond because the bond is assumed to be between the carbons 1 and 2.

In case if substituents are present in cycloalkene, then the double‑bonded carbon atoms are numbered 1 and 2 in a direction where the substituent gets the lower number.

If the cycloalkenes contain more than one double bond, then one double bond is assigned the numbers 1 and 2 followed by the other double bond so that the lowest number possible is given.

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option choice: Isoleucine Histidine Threonine Alanine Lysine Aspartate Tryptophan Tyrosine Leucine Arginine Cysteine Asparagine Valine Glutamine Glycine Methionine Serine Proline Phenylalanine Glutamate

sketch the nature of the metal-alkylidene bonding interactions.

Part C The perspective formula of isoleucine, an amino acid, is provided below. HOOC H₂NIC H 川 CH3 CH,CH3 Draw the Newman projection in staggered conformation for isoleucine by viewing the molecule along the C-2-C-3 bond. 1. Edit the Newman projection on the canvas. 2. Replace the appropriate hydrogens with the appropriate -CH3 or other groups. 3. If you need to start over, Undo or choose a Newman projection from the Templates toolbar (bottom). Important: Never delete the hydrogen atoms or bonds directly attached to the template, and do not move them by dragging or dropping them. That will break the projections structures. Only replace them! ▸ View Available Hint(s) 0 2 H± 3D EXP. L ד י CONT. 2 H 0 N о