Explanation Given information: The weight of the ball ( m ) is 5 oz or 5 16 lb . The average speed ( v a v ) is 30 ft / s . The velocity of the ball ( v ) is 90 mi / h . The distance where he pulls his hand back ( d ) is 6 in . or 0.5 ft . The acceleration due to gravity ( g ) is 32.2 ft / s 2 . Calculation: Show the free body diagram of the ball as in Figure (1). Calculate the mass of the ball ( m ) using the relation: W = m g m = W g Substitute 5 16 lb for W and 32.2 ft / s 2 for g . m = 5 16 lb 32.2 = 0.009705 lb ⋅ ft / s 2 Convert the unit of velocity of the ball ( v ) from mph to ft / s : v = ( v ) mph × ( 5280 ft mi ) × ( 1 3600 hr sec ) Here, ( v ) mph is the velocity of the ball in mph . Substitute 90 mi / h for ( v ) mph . v = 90 × ( 5280 ft mi ) × ( 1 3600 hr sec ) = 132 ft / sec Calculate the time ( t ) to reach his hand using the relation: t = d v a v Substitute 0.5 ft for d and 30 ft / s for v a v . t = 0

12th Edition

ISBN: 9781265566296

Author: BEER

Publisher: MCG

See similar textbooks

Concept explainers

Conservation of Energy

In physics, the rule of the conservation of energy states that energy doesn’t disappear from the atmosphere; instead, it changes its form from one type to another. Energy is one of the most important physical quantities in nature, and it cannot be create…

Videos

Question

Chapter 13.3, Problem 13.139P

To determine

Find the average impulsive (Fav) force exerted on the player’s hand.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 13.3, Problem 13.138P

Chapter 13.3, Problem 13.140P

Students have asked these similar questions

applied mechanics 2

A baseball player catching a ball can soften the impact by pulling his hand back. Assuming that a 5-oz ball reaches his glove at 90 mih and that the player pulls his hand back during the impact at an average speed of 30 ft/s over a distance of 6 in., bringing the ball to a stop, detemine the average impulsive force exerted on the player's hand. 6 in. 90 mi

Two identical 1350-kg automobiles A and B are at rest with their brakes released when B is struck by a 5400-kg truck C that is moving to the left at 8 km/h. A second collision then occurs when B strikes A. Assuming the first collision is perfectly plastic and the second collision is perfectly elastic, determine the velocities of the three vehicles just after the second collision.

Chapter 13 Solutions

<LCPO> VECTOR MECH,STAT+DYNAMICS

Ch. 13.1 - Block A is traveling with a speed v0 on a smooth...Ch. 13.1 - A 400-kg satellite is placed in a circular orbit...Ch. 13.1 - A 0.5-lb stone is dropped down the bottomless pit...Ch. 13.1 - A baseball player hits a 5.1-oz baseball with an...Ch. 13.1 - A 500-kg communications satellite is in a circular...Ch. 13.1 - Prob. 13.5P Ch. 13.1 - In an ore-mixing operation, a bucket full of ore...Ch. 13.1 - Determine the maximum theoretical speed that may...Ch. 13.1 - A 2000-kg automobile starts from rest at point A...Ch. 13.1 - An athlete is holding 30 lb of weights at a height...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Find the average impulsive ( F a v ) force exerted on the player’s hand.

Solution Summary: The author shows the free body diagram of the ball as in Figure (1).

Concept explainers

Videos

Find the average impulsive (Fav) force exerted on the player’s hand.

Want to see the full answer?

Chapter 13 Solutions