Chapter 13, Problem 7PS

Interpretation Introduction

Interpretation: The mass and molality of glycerol to be identified.

Concept introduction:

Mole fraction: Amount of that component divided by the total amount of all of the components of the mixture $\left({\text{ n}}_{\text{A}}{\text{ + n}}_{\text{B}}{\text{ + n}}_{\text{C }}\text{+ }\mathrm{...}\right)$.

${\text{Mole fraction of A (χ}}_{\text{A}}\text{)= }\frac{{\text{n}}_{\text{A}}}{{\text{ n}}_{\text{A}}{\text{ + n}}_{\text{B}}{\text{ + n}}_{\text{C }}\text{+ }\mathrm{...}}$

Molality: The amount of solute (mol) per kilogram of solvent.

$\text{Concentration (C, mol/kg) = molality of solute = }\frac{\text{Amount of solute (mol)}}{\text{Mass of solvent (Kg)}}$

Weight percent: The mass of one component divided by the total mass of the mixture, multiplied by $100\%$

$\text{weight \% A = }\frac{\text{Mass of A}}{\text{ Mass of A + Mass of B + Mass of C + }\mathrm{...}}\text{×100\%}$