The expected freezing point of L i F solution has to be determined. Concept introduction: Colligative properties: Properties of solutions which having influence on the concentration of the solute in it. Colligative properties are, Decrease in the vapor pressure Increase in the boiling point Decline in the freezing point Osmotic pressure Decline in the freezing point is huge when solute is an electrolyte than when solute is nonelectrolyte. Therefore, change in freezing point is calculated by using the equation, Δ T f p = K f p m s o l u t e i where, K f p is the molal freezing point depression constant. i is van’t Hoff factor van’t Hoff factor, i : it is the relation between change in in freezing point measured and change in in freezing point calculated. It indicates the total number of ions that are produced. Molality (m): Molality is the number of moles of solute present in one kilogram of solvent. Molality (m) = Number of moles of solute 1kg of solvent
The expected freezing point of L i F solution has to be determined. Concept introduction: Colligative properties: Properties of solutions which having influence on the concentration of the solute in it. Colligative properties are, Decrease in the vapor pressure Increase in the boiling point Decline in the freezing point Osmotic pressure Decline in the freezing point is huge when solute is an electrolyte than when solute is nonelectrolyte. Therefore, change in freezing point is calculated by using the equation, Δ T f p = K f p m s o l u t e i where, K f p is the molal freezing point depression constant. i is van’t Hoff factor van’t Hoff factor, i : it is the relation between change in in freezing point measured and change in in freezing point calculated. It indicates the total number of ions that are produced. Molality (m): Molality is the number of moles of solute present in one kilogram of solvent. Molality (m) = Number of moles of solute 1kg of solvent
Solution Summary: The author explains that the expected freezing point of LiF solution has to be determined.
Interpretation: The expected freezing point of LiFsolution has to be determined.
Concept introduction:
Colligative properties: Properties of solutions which having influence on the concentration of the solute in it. Colligative properties are,
Decrease in the vapor pressure
Increase in the boiling point
Decline in the freezing point
Osmotic pressure
Decline in the freezing point is huge when solute is an electrolyte than when solute is nonelectrolyte. Therefore, change in freezing point is calculated by using the equation,
ΔTfp=Kfpmsolutei
where,
Kfp is the molal freezing point depression constant.
i is van’t Hoff factor
van’t Hoff factor, i: it is the relation between change in in freezing point measured and change in in freezing point calculated. It indicates the total number of ions that are produced.
Molality (m): Molality is the number of moles of solute present in one kilogram of solvent.
9. OA. Rank the expected boiling points of the compounds shown below from highest to lowest. Place your answer
appropriately in the box. Only the answer in the box will be graded. (3) points)
OH
OH
بر بد بدید
2
3
There is an instrument in Johnson 334 that measures total-reflectance x-ray fluorescence (TXRF) to do elemental analysis (i.e., determine what elements are present in a sample). A researcher is preparing a to measure calcium content in a series of well water samples by TXRF with an internal standard of vanadium (atomic symbol: V). She has prepared a series of standard solutions to ensure a linear instrument response over the expected Ca concentration range of 40-80 ppm. The concentrations of Ca and V (ppm) and the instrument response (peak area, arbitrary units) are shown below. Also included is a sample spectrum. Equation 1 describes the response factor, K, relating the analyte signal (SA) and the standard signal (SIS) to their respective concentrations (CA and CIS).
Ca, ppm
V, ppm
SCa, arb. units
SV, arb. units
20.0
10.0
14375.11
14261.02
40.0
10.0
36182.15
17997.10
60.0
10.0
39275.74
12988.01
80.0
10.0
57530.75
14268.54
100.0…
A mixture of 0.568 M H₂O, 0.438 M Cl₂O, and 0.710 M HClO are enclosed in a vessel at 25 °C.
H₂O(g) + C₁₂O(g) = 2 HOCl(g)
K = 0.0900 at 25°C
с
Calculate the equilibrium concentrations of each gas at 25 °C.
[H₂O]=
[C₁₂O]=
[HOCI]=
M
Σ
M