An Introduction to Physical Science
An Introduction to Physical Science
14th Edition
ISBN: 9781305079137
Author: James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher: Cengage Learning
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Textbook Question
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Chapter 13, Problem 2E

Balance these chemical equations.

  1. (a) SO 2 +  O 2 SO 3
  2. (b) NH 3 + O 2 N 2 + H 2 O
  3. (c) C 4 H 10 + O 2 CO 2 +  H 2 O
  4. (d) Pb(NO 3 ) 2 PbO  +  NO 2 +  O 2
  5. (e) Al + Fe 3 O 4 Al 2 O 3 + Fe
  6. (f) Sr + H 2 O Sr(OH) 2 + H 2

(a)

Expert Solution
Check Mark
To determine
Balance the given chemical equation: SO2+O2SO3

Answer to Problem 2E

The balanced chemical equation is written as,

2SO2+O22SO3

Explanation of Solution

Given info: The chemical equation is given as,

SO2+O2SO3

Explanation:

In the balanced chemical equation, the number of same atom in the product and reactant side should be equal.

The given chemical equation is written as,

SO2+O2SO3

In the above reaction, there are four oxygen atoms on the reactant side and there are three oxygen atoms on the product side. If O2 is multiplied by 12 then the above equation will be balanced. But the coefficient in the balanced equation should be a whole number not a fraction.

Therefore, multiply SO2 with 2 and SO3 with 2 . The balanced chemical equation is written as,

2SO2+O22SO3

Conclusion:

Therefore, the balanced chemical equation is written as,

2SO2+O22SO3

(b)

Expert Solution
Check Mark
To determine
Balance the given chemical equation: NH3+O2N2+H2O

Answer to Problem 2E

The balanced chemical equation is written as,

4NH3+3O22N2+6H2O

Explanation of Solution

Given info: The chemical equation is given as,

NH3+O2N2+H2O

Explanation:

In the balanced chemical equation, the number of same atom in the product and reactant side should be equal.

The given chemical equation is written as,

NH3+O2N2+H2O

In the above reaction, there is one nitrogen atom on the reactant side and two nitrogen atoms on the product side. Therefore multiply NH3 with 2 . The chemical equation is written as,

2NH3+O2N2+H2O

In the above reaction, there are six hydrogen atoms on the reactant side and two hydrogen atoms on the product side. Therefore multiply H2O with 3 . The chemical equation is written as,

2NH3+O2N2+3H2O

In the above reaction, there are two oxygen atoms on the reactant side and three oxygen atoms on the product side. Therefore, multiply O2 with 32 . The chemical equation is written as,

2NH3+32O2N2+3H2O

In the balanced equation, the coefficients should be a whole number not a fraction. Therefore, multiply the above equation with 2 . The balanced chemical equation is written as,

4NH3+3O22N2+6H2O

Conclusion:

Therefore, the balanced chemical equation is written as,

4NH3+3O22N2+6H2O

(c)

Expert Solution
Check Mark
To determine
Balance the given chemical equation: C4H10+O2CO2+H2O

Answer to Problem 2E

The balanced chemical equation is written as,

2C4H10+13O28CO2+10H2O

Explanation of Solution

Given info: The chemical equation is given as,

C4H10+O2CO2+H2O

Explanation:

In the balanced chemical equation, the number of same atom in the product and reactant side should be equal.

The given chemical equation is written as,

C4H10+O2CO2+H2O

In the above reaction, there are four carbon atoms on the reactant side and one carbon atom on the product side. Therefore multiply CO2 with 4 . The chemical equation is written as,

C4H10+O24CO2+H2O

In the above reaction, there are ten hydrogen atoms on the reactant side and two hydrogen atoms on the product side. Therefore multiply H2O with 5 . The chemical equation is written as,

C4H10+O24CO2+5H2O

In the above reaction, there are two oxygen atoms on the reactant side and thirteen oxygen atoms on the product side. Therefore, multiply O2 with 132 . The chemical equation is written as,

C4H10+132O24CO2+5H2O

In the balanced equation, the coefficients should be a whole number not a fraction. Therefore, multiply the above equation with 2 . The balanced chemical equation is written as,

2C4H10+13O28CO2+10H2O

Conclusion:

Therefore, the balanced chemical equation is written as,

2C4H10+13O28CO2+10H2O

(d)

Expert Solution
Check Mark
To determine
Balance the given chemical equation: Pb(NO3)2PbO+NO2+O2

Answer to Problem 2E

The balanced chemical equation is written as,

2Pb(NO3)22PbO+4NO2+O2

Explanation of Solution

Given info: The chemical equation is given as,

Pb(NO3)2PbO+NO2+O2

Explanation:

In the balanced chemical equation, the number of same atom in the product and reactant side should be equal.

The given chemical equation is written as,

Pb(NO3)2PbO+NO2+O2

In the above equation there are two nitrogen atoms on the reactant side and one nitrogen atom on the product side. Therefore, multiply NO2 with 2 . The chemical equation after balancing nitrogen atoms is written as,

Pb(NO3)2PbO+2NO2+O2

In the above reaction, there are six oxygen atoms on the reactant side and there are seven oxygen atoms on the product side. Therefore, multiply O2 with 12 . The chemical equation is written as,

Pb(NO3)2PbO+2NO2+12O2

In the balanced equation, the coefficients should be a whole number not a fraction. Therefore, multiply the above equation with 2 . The balanced chemical equation is written as,

2Pb(NO3)22PbO+4NO2+O2

Conclusion:

Therefore, the balanced chemical equation is written as,

2Pb(NO3)22PbO+4NO2+O2

(e)

Expert Solution
Check Mark
To determine
Balance the given chemical equation: Al+Fe3O4Al2O3+Fe

Answer to Problem 2E

The balanced chemical equation is written as,

8Al+3Fe3O44Al2O3+9Fe

Explanation of Solution

Given info: The chemical equation is given as,

Al+Fe3O4Al2O3+Fe

Explanation:

In the balanced chemical equation, the number of same atom in the product and reactant side should be equal.

The given chemical equation is written as,

Al+Fe3O4Al2O3+Fe

In the above equation, there are four oxygen atoms on the reactant side and three oxygen atoms on product side. Therefore, multiply Fe3O4 with 3 and Al2O3 with 4 . The chemical equation after balancing the oxygen atoms on each side is written as,

Al+3Fe3O44Al2O3+Fe

In the above equation, there is one aluminium atom on the reactant side and eight aluminium atoms on the product side. Therefore, multiply Al with 8 . The chemical equation after balancing aluminium atom on each side is written as,

8Al+3Fe3O44Al2O3+Fe

In the above equation, there are nine iron atoms on the reactant side and one iron atom on the product side. Therefore, multiply Fe with 9 . The balanced chemical equation is written as,

8Al+3Fe3O44Al2O3+9Fe

Conclusion:

Therefore, the balanced chemical equation is written as,

8Al+3Fe3O44Al2O3+9Fe

(f)

Expert Solution
Check Mark
To determine
Balance the given chemical equation: Sr+H2OSr(OH)2+H2

Answer to Problem 2E

The balanced chemical equation is written as,

Sr+2H2OSr(OH)2+H2

Explanation of Solution

Given info: The chemical equation is given as,

Sr+H2OSr(OH)2+H2

Explanation:

In the balanced chemical equation, the number of same atom in the product and reactant side should be equal.

The given chemical equation is written as,

Sr+H2OSr(OH)2+H2

In the above reaction, there are two hydrogen atoms and one oxygen atom on the reactant side and there are four hydrogen atoms and two oxygen atoms on the product side. Therefore, multiply H2O with 2 on the reactant side. The balanced chemical equation is written as,

Sr+2H2OSr(OH)2+H2

Conclusion:

Therefore, the balanced chemical equation is written as,

Sr+2H2OSr(OH)2+H2

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Chapter 13 Solutions

An Introduction to Physical Science

Ch. 13.3 - Prob. 13.5CECh. 13.4 - What is oxidation?Ch. 13.4 - Prob. 2PQCh. 13.4 - Prob. 13.6CECh. 13.5 - Prob. 1PQCh. 13.5 - Prob. 2PQCh. 13.5 - How many grams are in 1.70 moles of potassium...Ch. 13.5 - What is the molarity of a salt (NaCl) solution in...Ch. 13 - Prob. AMCh. 13 - Prob. BMCh. 13 - Prob. CMCh. 13 - Prob. DMCh. 13 - Prob. EMCh. 13 - Prob. FMCh. 13 - Prob. GMCh. 13 - Prob. HMCh. 13 - Prob. IMCh. 13 - Prob. JMCh. 13 - Prob. KMCh. 13 - Prob. LMCh. 13 - Prob. MMCh. 13 - Prob. NMCh. 13 - Prob. OMCh. 13 - Prob. PMCh. 13 - Prob. QMCh. 13 - Prob. RMCh. 13 - Prob. SMCh. 13 - Prob. TMCh. 13 - Prob. UMCh. 13 - Prob. VMCh. 13 - Prob. WMCh. 13 - Prob. XMCh. 13 - Prob. YMCh. 13 - Prob. ZMCh. 13 - When iron rusts in the presence of oxygen and...Ch. 13 - How many hydrogen atoms are indicated by 2...Ch. 13 - Prob. 3MCCh. 13 - Prob. 4MCCh. 13 - Consider the complete combustion of octane, C8H18....Ch. 13 - Prob. 6MCCh. 13 - Prob. 7MCCh. 13 - What is the pH of a solution ten times as acidic...Ch. 13 - Prob. 9MCCh. 13 - Prob. 10MCCh. 13 - One mole of hydrogen peroxide, H2O2, would consist...Ch. 13 - One mole of hydrogen peroxide, H2O2, would consist...Ch. 13 - Prob. 1FIBCh. 13 - Prob. 2FIBCh. 13 - Prob. 3FIBCh. 13 - Prob. 4FIBCh. 13 - Prob. 5FIBCh. 13 - Prob. 6FIBCh. 13 - Prob. 7FIBCh. 13 - Prob. 8FIBCh. 13 - Prob. 9FIBCh. 13 - Prob. 10FIBCh. 13 - Prob. 11FIBCh. 13 - Prob. 12FIBCh. 13 - Prob. 13FIBCh. 13 - Prob. 14FIBCh. 13 - Prob. 1SACh. 13 - Iodine is (a) blue-black, (b) crystalline, and (c)...Ch. 13 - Prob. 3SACh. 13 - Prob. 4SACh. 13 - Prob. 5SACh. 13 - Prob. 6SACh. 13 - Prob. 7SACh. 13 - Prob. 8SACh. 13 - Prob. 9SACh. 13 - Prob. 10SACh. 13 - Why does a reaction vessel feel warm during an...Ch. 13 - What is absorbed during bond breaking but...Ch. 13 - Prob. 13SACh. 13 - Prob. 14SACh. 13 - Prob. 15SACh. 13 - Prob. 16SACh. 13 - Prob. 17SACh. 13 - Prob. 18SACh. 13 - Prob. 19SACh. 13 - Prob. 20SACh. 13 - What is the pH of a neutral aqueous solution? How...Ch. 13 - What color will litmus be in a solution of pH 9? A...Ch. 13 - Prob. 23SACh. 13 - Prob. 24SACh. 13 - Prob. 25SACh. 13 - Prob. 26SACh. 13 - The reaction of an acid with a hydroxide base...Ch. 13 - Prob. 28SACh. 13 - Prob. 29SACh. 13 - Prob. 30SACh. 13 - Prob. 31SACh. 13 - Prob. 32SACh. 13 - Prob. 33SACh. 13 - Prob. 34SACh. 13 - Prob. 35SACh. 13 - Prob. 36SACh. 13 - Prob. 37SACh. 13 - Suppose you are given the volume (in liters) of a...Ch. 13 - Prob. 1VCCh. 13 - Prob. 1AYKCh. 13 - Prob. 2AYKCh. 13 - Explain why a bag of charcoal briquettes contains...Ch. 13 - An Alka-Seltzer tablet contains solid citric acid...Ch. 13 - The human body converts sugar into carbon dioxide...Ch. 13 - Prob. 6AYKCh. 13 - Prob. 7AYKCh. 13 - Prob. 8AYKCh. 13 - Prob. 9AYKCh. 13 - Prob. 10AYKCh. 13 - Prob. 1ECh. 13 - Balance these chemical equations. (a) SO2+O2SO3...Ch. 13 - Prob. 3ECh. 13 - Prob. 4ECh. 13 - Prob. 5ECh. 13 - Prob. 6ECh. 13 - Prob. 7ECh. 13 - Prob. 8ECh. 13 - Prob. 9ECh. 13 - Prob. 10ECh. 13 - Prob. 11ECh. 13 - Prob. 12ECh. 13 - Prob. 13ECh. 13 - Prob. 14ECh. 13 - Prob. 15ECh. 13 - Prob. 16ECh. 13 - Two moles of hydrogen sulfide, H2S, would consist...Ch. 13 - Four moles of sulfur dioxide, SO2, would consist...Ch. 13 - Prob. 19ECh. 13 - Prob. 20ECh. 13 - Prob. 21ECh. 13 - How many moles are in 15.0 g of copper sulfate...Ch. 13 - Prob. 23ECh. 13 - How many molecules are in 2.49 103 g of CuSO4?Ch. 13 - Prob. 25ECh. 13 - Prob. 26ECh. 13 - Prob. 27ECh. 13 - Prob. 28E
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