Loose Leaf For Introduction To Chemical Engineering Thermodynamics
8th Edition
ISBN: 9781259878084
Author: Smith Termodinamica En Ingenieria Quimica, J.m.; Van Ness, Hendrick C; Abbott, Michael; Swihart, Mark
Publisher: McGraw-Hill Education
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Chapter 13, Problem 13.56P
Possible correlating equations for In
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6. In a process design, the following process streams must be cooled or heated:
Stream
No
mCp
Temperature In Temperature Out
°C
°C
kW/°C
1
5
350
270
2
9
270
120
3
3
100
320
4
5
120
288
Use the MUMNE algorithm for heat exchanger networks with a minimum approach
temperature of 20°C.
(5)
a. Determine the temperature interval diagram.
(3)
(2)
(10)
(10)
b. Determine the cascade diagram, the pinch temperatures, and the minimum hot and
cold utilities.
c. Determine the minimum number of heat exchangers above and below the pinch.
d. Determine a valid heat exchange network above the pinch.
e. Determine a valid heat exchange network below the pinch.
Use this equation to solve it.
Q1: Consider the following transfer function
G(s)
5e-s
15s +1
1. What is the study state gain
2. What is the time constant
3. What is the value of the output at the end if the input is a unit step
4. What is the output value if the input is an impulse function with amplitude equals
to 3, at t=7
5. When the output will be 3.5 if the input is a unit step
Chapter 13 Solutions
Loose Leaf For Introduction To Chemical Engineering Thermodynamics
Ch. 13 - Prob. 13.1PCh. 13 - Assuming Raoult’s law to be valid, prepare a Pxy...Ch. 13 - Assuming Raoult’s law to apply to the system...Ch. 13 - Prob. 13.4PCh. 13 - Prove: An equilibrium liquid/vapor system...Ch. 13 - Of the following binary liquid/vapor systems,...Ch. 13 - A single-stage liquid/vapor separation for the...Ch. 13 - Do all four parts of Prob. 13.7, and compare the...Ch. 13 - A mixture containing equimolar amounts of...Ch. 13 - Do all four parts of Prob. 13.9. and compare the...
Ch. 13 - A binary mixture of mole fraction z1is flashed to...Ch. 13 - Humidity, relating to the quantity of moisture in...Ch. 13 - A concentrated binary solution containing mostly...Ch. 13 - Air, even more than carbon dioxide, is inexpensive...Ch. 13 - Helium-laced gases are used as breathing media for...Ch. 13 - A binary system of species 1 and 2 consists of...Ch. 13 - For the system ethyl ethanoate(l)/n-heptane(2) at...Ch. 13 - A liquid mixture of cyclohexanone(1)/phenol(2) for...Ch. 13 - A binary system of species 1 and 2 consists of...Ch. 13 - For the acetone(l)/methanol(2) system, a vapor...Ch. 13 - The following is a rule of thumb: For a binary...Ch. 13 - A process stream contains light species 1 and...Ch. 13 - If a system exhibits VLE, at least one of the...Ch. 13 - Flash calculations are simpler for binary systems...Ch. 13 - Prob. 13.25PCh. 13 - (a) A feed containing equimolar amounts of...Ch. 13 - A binary mixture of benzene(1) and toluene(2) is...Ch. 13 - Ten (10) kmolhr-1 of hydrogen sulfide gas is...Ch. 13 - Physiological studies show the neutral comfort...Ch. 13 - Prob. 13.30PCh. 13 - Prob. 13.31PCh. 13 - Prob. 13.32PCh. 13 - If Eq. (13.24) is valid for isothermal VLE in a...Ch. 13 - Prob. 13.34PCh. 13 - The excess Gibbs energy for binary systems...Ch. 13 - For the ethanol(l )/chloroform(2) system at 50°C,...Ch. 13 - VLE data for methyl tert-butyl...Ch. 13 - Prob. 13.38PCh. 13 - Prob. 13.39PCh. 13 - Following are VLE data for the system...Ch. 13 - Prob. 13.41PCh. 13 - Prob. 13.42PCh. 13 - Problems 13.43 through 13.54 require parameter...Ch. 13 - Problems 13.43 through 13.54 require parameter...Ch. 13 - Prob. 13.45PCh. 13 - Problems 13.43 through 13.54 require parameter...Ch. 13 - Prob. 13.47PCh. 13 - Prob. 13.48PCh. 13 - Prob. 13.49PCh. 13 - Prob. 13.50PCh. 13 - Problems 13.43 through 13.54 require parameter...Ch. 13 - Prob. 13.52PCh. 13 - The following expressions have been reported for...Ch. 13 - Possible correlating equations for In 1 in a...Ch. 13 - Prob. 13.57PCh. 13 - Binary VLE data are commonly measured at constant...Ch. 13 - Consider the following model for GE/RT of a binary...Ch. 13 - A breathalyzer measures volume-% ethanol in gases...Ch. 13 - Table 13.10 gives values of parameters for the...Ch. 13 - Prob. 13.62PCh. 13 - A single P-x1- y1data point is available for a...Ch. 13 - A single P- x1, data point is available for a...Ch. 13 - The excess Gibbs energy for the system...Ch. 13 - Prob. 13.66PCh. 13 - A system formed of methane(l) and a light oil(2)...Ch. 13 - Use Eq. (13.13) to reduce one of the following...Ch. 13 - For one of the following substances, determine...Ch. 13 - Departures from Raoult's law are primarily from...Ch. 13 - The relative volatility a12is commonly used in...Ch. 13 - Prob. 13.74PCh. 13 - Prob. 13.75PCh. 13 - Prob. 13.76P
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- give me solution math not explinarrow_forwardExample (6): An evaporator is concentrating F kg/h at 311K of a 20wt% solution of NaOH to 50wt %. The saturated steam used for heating is at 399.3K. The pressure in the vapor space of the evaporator is 13.3 KPa abs. The 5:48 O Transcribed Image Text: Example (7): Determine thearrow_forward14.9. A forward feed double-effect vertical evaporator, with equal heating areas in each effect, is fed with 5 kg/s of a liquor of specific heat capacity of 4.18 kJ/kg K. and with no boiling point rise, so that 50 per cent of the feed liquor is evaporated. The overall heat transfer coefficient in the second effect is 75 per cent of that in the first effect. Steam is fed at 395 K and the boiling point in the second effect is 373 K. The feed is heated by an external heater to the boiling point in the first effect. It is decided to bleed off 0.25 kg/s of vapour from the vapour line to the second effect for use in another process. If the feed is still heated to the boiling point of the first effect by external means, what will be the change in steam consumption of the evaporator unit? For the purpose of calculation, the latent heat of the vapours and of the steam may both be taken as 2230 kJ/kgarrow_forward
- Example(3): It is desired to design a double effect evaporator for concentrating a certain caustic soda solution from 12.5wt% to 40wt%. The feed at 50°C enters the first evaporator at a rate of 2500kg/h. Steam at atmospheric pressure is being used for the said purpose. The second effect is operated under 600mmHg vacuum. If the overall heat transfer coefficients of the two stages are 1952 and 1220kcal/ m2.h.°C. respectively, determine the heat transfer area of each effect. The BPR will be considered and present for the both effect 5:49arrow_forwardالعنوان ose only Q Example (7): Determine the heating surface area 개 required for the production of 2.5kg/s of 50wt% NaOH solution from 15 wt% NaOH feed solution which entering at 100 oC to a single effect evaporator. The steam is available as saturated at 451.5K and the boiling point rise (boiling point evaluation) of 50wt% solution is 35K. the overall heat transfer coefficient is 2000 w/m²K. The pressure in the vapor space of the evaporator at atmospheric pressure. The solution has a specific heat of 4.18kJ/ kg.K. The enthalpy of vaporization under these condition is 2257kJ/kg Example (6): 5:48 An evaporator is concentrating F kg/h at 311K of a 20wt% solution of NaOH to 50wt %. The saturated steam used for heating is at 399.3K. The pressure in the vapor space of the evaporator is 13.3 KPa abs. The 5:48 1 J ۲/۱ ostrarrow_forwardExample 8: 900 Kg dry solid per hour is dried in a counter current continues dryer from 0.4 to 0.04 Kg H20/Kg wet solid moisture content. The wet solid enters the dryer at 25 °C and leaves at 55 °C. Fresh air at 25 °C and 0.01Kg vapor/Kg dry air is mixed with a part of the moist air leaving the dryer and heated to a temperature of 130 °C in a finned air heater and enters the dryer with 0.025 Kg/Kg alry air. Air leaving the dryer at 85 °C and have a humidity 0.055 Kg vaper/Kg dry air. At equilibrium the wet solid weight is 908 Kg solid per hour. *=0.0088 Calculate:- Heat loss from the dryer and the rate of fresh air. Take the specific heat of the solid and moisture are 980 and 4.18J/Kg.K respectively, A. =2500 KJ/Kg. Humid heat at 0.01 Kg vap/Kg dry=1.0238 KJ/Kg. "C. Humid heat at 0.055 Kg/Kg 1.1084 KJ/Kg. "C 5:42 Oarrow_forward
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