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(a)
Interpretation:
By using
Concept Introduction:
Heat treatment is the metalworking process used to change the physical properties as well as chemical properties of the material that treatment is commonly used in metallurgical for the manufacturing of glass. Heat treatment uses heating on chilling to the extreme temperature to achieve desired properties such as hardening or softening of a material. Under heat treatment various technique uses such as annealing case precipitation, hardening, strengthening, tempering & carburizing quenching.
(b)
Interpretation:
The yield & tensile strength of
Concept Introduction:
Heat treatment is the metalworking process used to change the physical properties as well as chemical properties of the material that treatment is commonly used in metallurgical for the manufacturing of glass. Heat treatment uses heating on chilling to the extreme temperature to achieve desired properties such as hardening or softening of a material. Under heat treatment various technique uses such as annealing case precipitation, hardening, strengthening, tempering & carburizing quenching.
(c)
Interpretation:
The yield strength tensile strength & % elongation of the
Concept Introduction:
Heat treatment is the metalworking process used to change the physical properties as well as chemical properties of the material that treatment is commonly used in metallurgical for the manufacturing of glass. Heat treatment uses heating on chilling to the extreme temperature to achieve desired properties such as hardening or softening of a material. Under heat treatment various technique uses such as annealing case precipitation, hardening, strengthening, tempering & carburizing quenching.
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Chapter 13 Solutions
Essentials of Materials Science and Engineering, SI Edition
- Water (at 10° C has n = 1.31 x 106 m²/s) flows from reservoir A (surface elevation 100 m) through a 2.25-m-diameter concrete pipe (e = 0.36 mm; f=0.014) to reservoir B (surface elevation 91.84 m). If the 2 reservoirs are 17 km apart, find the flow velocity V (to 2 decimal places x.xx) ignoring minor losses. 100 m A L = 17 km P₁ h₁ + = + V² 2g D=2.25 m 91.84 m B + h₂ 2g P₂ = =h₂+ + Varrow_forwardDo NOT WANT AI. need diagram fully labeled pleasearrow_forwardThe floor system of an apartment building consists of a 4-inch-thick reinforced concrete slab resting on three steel floor beams, which are in turn supported by two steel girders, as shown below. The areas of cross section of the floor beams and the girders are 18.3 in.2 and 32.7 in.², respectively. Determine the dead load acting on the beam CD. Steel girder (A-32.7 in.2) At I- 25 ft B I Steel column C D Steel floor beam (A =18.3 in.2) I a. 600.0 lb/ft b. 662.3 lb/ft c. 62.3 lb/ft d. 1347.3 lb/ft E 4 in. concrete slab 2 at 12 ft = 24 ftarrow_forward
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- Sketch and describe hatch coamings. Describe structrual requirements to deck plating to compensate discontinuity for corners of a hatch. Show what is done to the deck plating when the decks are cut away and include the supporting members.arrow_forwardAn Inclining experiment done on a ship thats 6500 t, a mass of 30t was moved 6.0 m transvesly causing a 30 cm deflection in a 6m pendulum, calculate the transverse meta centre height.arrow_forwarda ship 150 m long and 20.5 m beam floats at a draught of8 m and displaces 19 500 tonne. The TPC is 26.5 and midshipsection area coefficient 0.94. Calculate the block, prismatic andwaterplane area coefficients.arrow_forward
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