(a)
Interpretation:
By using
Concept Introduction:
Heat treatment is the metalworking process used to change the physical properties as well as chemical properties of the material that treatment is commonly used in metallurgical for the manufacturing of glass. Heat treatment uses heating on chilling to the extreme temperature to achieve desired properties such as hardening or softening of a material. Under heat treatment various technique uses such as annealing case precipitation, hardening, strengthening, tempering & carburizing quenching.
(b)
Interpretation:
The yield & tensile strength of
Concept Introduction:
Heat treatment is the metalworking process used to change the physical properties as well as chemical properties of the material that treatment is commonly used in metallurgical for the manufacturing of glass. Heat treatment uses heating on chilling to the extreme temperature to achieve desired properties such as hardening or softening of a material. Under heat treatment various technique uses such as annealing case precipitation, hardening, strengthening, tempering & carburizing quenching.
(c)
Interpretation:
The yield strength tensile strength & % elongation of the
Concept Introduction:
Heat treatment is the metalworking process used to change the physical properties as well as chemical properties of the material that treatment is commonly used in metallurgical for the manufacturing of glass. Heat treatment uses heating on chilling to the extreme temperature to achieve desired properties such as hardening or softening of a material. Under heat treatment various technique uses such as annealing case precipitation, hardening, strengthening, tempering & carburizing quenching.
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Chapter 13 Solutions
Essentials of Materials Science and Engineering, SI Edition
- pls match the ans key, someone gave me a wrong ans.arrow_forwardDraw the network diagram of the following Table using PERT and determine Te, Sd, V, ES, LF, Ts and C. P. Find the probability P if D =27 weeks. Activities Prec. by To Tm Tp Te SD V ES LF Ts C.P A -- HW2 11 22U118243 10 10 1985762323443 26624452-2232 B A C -- D C E D F D G F H B, E 1 I G, H J B K J L K, I 4654arrow_forwardFor the beam and loading shown, (a) draw the shear and bending moment diagrams, (b) determine the magnitude and location of the maximum absolute value of the bending momentConsider A = 0please show step by step process, i did something wrong with bending moment diagram( length of beam = 2 + 6 + 2)arrow_forward
- I have uploaded the rules, please explain step by step and which rule you have appliedarrow_forwardI have uploaded the rules, please explain step by step and which rule you have appliedarrow_forwardSITUATION 3: A simply-supported steel beam 6 m long carries a uniform load of 25 kN/m and an axial compressive force of 250 kN. Assume both flange and web are compact. The properties of the rolled section are as follows: Show your complete solution and box only the final answer. Flange Width, bf = 210 mm Flange thickness, tf = 24 mm Overall depth, d=225 mm Web thickness, tw 14 mm Yield Strength, Fy=248 Mpa Radius of Gyration, ry = 54.342 mm Cb = 1.136 J = 2,097,256 mm² rts = 62.089 mm 1. Determine the total moment of inertia along x-axis. 2. Determine the total moment of inertia along y-axis 3. What is the allowable axial compressive strength of the beam, in kN? 4. What is the allowable flexural strength of the beam, in kN-m? 1. 108.764 x 106 mm* 2. 37.084 x 106 mm* 3. 982.304 KN 4. 166.723 KN-marrow_forward
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