Chapter 13, Problem 13.114QP

Interpretation Introduction

Interpretation:

The activation energy, frequency factor and rate constant at $\text{45°C}$ has to be calculated.

Concept Introduction:

Arrhenius equation:

Arrhenius equation is used to calculate the rate constant of many reactions. Arrhenius equation takes the form

${\text{k=Ae}}^{{\text{-E}}_{\text{a}}\text{/RT}}$

Where,

k=rate constant

A=frequency factor

e=base of logarithms

${\text{E}}_{\text{a}}$ = energy of activation

T=Temperature

Mathematically, the above equation can be written as,

$\text{ln}\text{k=ln}\text{A-}\frac{{\text{E}}_{\text{a}}}{\text{RT}}$