Chapter 13, Problem 11CT

To determine

To find: The possibility of different plates.

Answer to Problem 11CT

The possibility of different plates $155480000$ .

Explanation of Solution

Given information: 4 digits $\left(0-9\right)$

Calculation: Let, us assume that there are p experiments.

If the experiment $1$ can be performed $p_1$ ways

And experiment $2$ , can be performed in $p_2$ ways

  $\begin{array}{l}\text{'}\\ \text{'}\\ \text{'}\\ \text{'}\end{array}$

So on

There are $p_1.p_2.p_3\mathrm{..........}{p}_n$ ways of performing the $p$ experiments together.

Then,

  $\begin{array}{l}26\times 26\times 23\times 10\times 10\times 10\times 10\\ ={26}^2\times {10}^4\times 23\\ =155480000\end{array}$

Hence, The possibility of different plates $155480000$ .