Chapter 13, Problem 10CT

To determine

To find: How many ways could you make an extra bet of 8 horses in a race.

Answer to Problem 10CT

For extra bet it has $56$ ways.

Explanation of Solution

Given:There are8 horses in a race.

Concept used: $\frac{n!}{n_1!n_2!--n_k!}$

Here 8 horses are in a race and extra bet requires the better to pick the first two horses in the extra order.

The first horse can be chosen in 8 ways.

The second horse can be chosen in 7 ways.

Now multiplication counting principle or $\left(P\left(8,2\right)\right)$

  $8.7=56$ .

Hence, for extra bet it has $56$ ways.