Organic Chemistry (6th Edition)
Organic Chemistry (6th Edition)
6th Edition
ISBN: 9781260119107
Author: Janice Gorzynski Smith
Publisher: McGraw Hill Education
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Chapter 12C, Problem 67P

Reaction of ( CH 3 ) 3 CCHO with ( C 6 H 5 ) 3 P = C ( CH 3 ) OCH 3 , followed by treatment with aqueous acid, affords R ( C 7 H 14 O ) . R has a strong absorption in its IR spectrum at 1717 cm 1 and three singlets in its 1 H NMR spectrumat 1 .02 ( 9 H ) , 2 .13 ( 3 H ) , and 2 .33 ( 2 H ) ppm . What is the structure of R? We will learn about this reaction in Chapter 21.

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A compound (C7H14O) has a strong peak in its IR spectrum at 1710 cm–1. Its 1H NMR spectrum consists of three singlets in the ratio 9:3:2 at δ 1.0, 2.1, and 2.3, respectively. Identify the compound.
Three isomeric compounds, A, B, and C, all have molecular formulaC8H11N. The 1H NMR and IR spectral data of A, B, and C are given below.What are their structures?
Reaction of (CH3)3CCHO with (C6H5)3P=C(CH3)OCH3, followed by treatment with aqueous acid, affords R (C7H14O). R has a strong absorption in its IR spectrum at 1717 cm−1 and three singlets in its 1H NMR spectrum at 1.02 (9 H), 2.13 (3 H), and 2.33 (2 H) ppm. What is the structure of R? We will learn about this reaction in Chapter 18.

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Organic Chemistry (6th Edition)

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