Chapter 12.6, Problem 2P

To determine

To find: length and width of a rectangle.

Answer to Problem 2P

The length of a rectangle is $15m$ and the width of the rectangular park is $5m$ .

Explanation of Solution

Given information:

The length of rectangle is $3$ times of its widthand the area of rectangle is $75m^2$ .

Formula:

Area of rectangle is $length*width$ .

Calculation:

Consider that the length of a rectangle be $l$ and the width be $b$ .

Recall that area of rectangle is $length*width$ .

Since the length of a rectangle is $3$ times of its width.

Therefore $l=3b$ .

Therefore area of rectangle will be $75=l*b\Rightarrow 75=3b*b\Rightarrow 3b^2=75$ .

Therefore on further $\Rightarrow 3b^2=75\Rightarrow b^2=25\Rightarrow b=+5,-5.$

Here we assume width $b=+5$ because length and width cannot be negative value.

Therefore the length of a rectangle is $3b=3*5=15$ .

Therefore the length of a rectangle is $15m$ and the width of the rectangular park is $5m$ .