Chapter 12.6, Problem 1.1E

To determine

To find: the volume of the gas.

Answer to Problem 1.1E

The volume of the gas is $360c{m}^3$ .

Explanation of Solution

Given information:

The volume of gas $420c{m}^3$ at pressure $720mm$ and then pressure is increased to $840mm$ .

Formula:

The pressure volume of a gas is $p_1{v}_1=p_2{v}_2$ .

Calculation:

Consider the volume be $xc{m}^3$ when pressure is at $840mm$ .

Recall that the pressure volume of a gas is as mentioned below.

  $p_1{v}_1=p_2{v}_2$ where $p_1=720mm,v_1=420c{m}^3,p_2=840mm,v_2=xc{m}^3.$

Therefore $720*420=840*x\Rightarrow x=\frac{720*420}{840}=360c{m}^3$ .

Therefore volume of the gas at a pressure $840mm$ is $360c{m}^3$ .