Chapter 12, Problem 47CLR

To determine

To find: The factor of the given polynomial and if it cannot be factorized than write prime.

Answer to Problem 47CLR

The factorized form of the polynomial is ${\left(c-4\right)}^2$ .

Explanation of Solution

Given:

The given polynomial is $-10p^2+27p+28$ .

Calculation:

Consider the given polynomial is,

  $c^2-8c+16$

Then, the solution is,

  $c^2-8c+16$

The first term and the last term of the above expression is the perfect square and the factored form of the polynomial is,

  $\begin{array}{c}{c}^2-8c+16=c^2-4c-4c+16\\ =c\left(c-4\right)-4\left(c-4\right)\\ =\left(c-4\right)\left(c-4\right)\\ ={\left(c-4\right)}^2\end{array}$