Chapter 12.3, Problem 8OE

To determine

To read: the equation $6-q^2=4q$ in standard form and tell what the values of a, b and c are.

Answer to Problem 8OE

The required answer is: the values are a = - 1, b = - 4 and c = 6

Explanation of Solution

Given information:

The given equation: $6-q^2=4q$

Calculation:

The standard form of a quadratic equation is given by:

  $a{x}^2+bx+c=0$

  $\begin{array}{l}6-q^2=4q\\ 6-q^2-4q=4q-4q\end{array}$

(Subtract 4q from both sides)

  $\begin{array}{l}6-q^2-4q=0\\ -q^2-4q+6=0\end{array}$

(Simplify)

The equation is in standard form.

Hence, the values of a, b and c are:

  $\begin{array}{l}a=-1\\ b=-4\\ c=6\end{array}$