Chapter 12.3, Problem 6OE

To determine

To read: the equation $y^2=6y-7$ in standard form and tell what the values of a, b and c are.

Answer to Problem 6OE

The required answer is: the values are a = 1, b = - 6 and c = 7

Explanation of Solution

Given information:

The given equation: $y^2=6y-7$

Calculation:

The standard form of a quadratic equation is given by:

  $a{x}^2+bx+c=0$

  $\begin{array}{l}{y}^2=6y-7\\ y^2-6y=6y-7-6y\end{array}$

(Subtract 6y from both sides)

  $\begin{array}{l}{y}^2-6y=-7\\ y^2-6y+7=-7+7\end{array}$

(Add 7 to both sides)

  $y^2-6y+7=0$

(Simplify)

The equation is in standard form.

Hence, the values of a, b and c are:

  $\begin{array}{l}a=1\\ b=-6\\ c=7\end{array}$