Chapter 12.5, Problem 2CK

To determine

Tofind:The reason for $\Delta EDB\sim \Delta VOB$ .

Answer to Problem 2CK

Both the triangles $\Delta EDB$ and $\Delta VOB$ are similar as all the angles of the triangles are equal.

Explanation of Solution

Given information:The figure is shown below:

  

Calculation:

In $\Delta EDB$ and $\Delta VOB$ , $\angle \text{B}$ is common in both triangles. So, their measure will be the same.

The measure of $\angle VOB$ and $\angle EDB$ is $90°$ . Let the angle be $c$ . It is known that the sum of interior angles of triangle is $180°$ .

The third angle of $\Delta VOB$ is:

  $180°-90°-c=90°-c$

The third angle of $\Delta EDB$ is:

  $180°-90°-c=90°-c$

As all the three angles of $\Delta EDB$ and $\Delta VOB$ are equal.

Hence, the given triangles $\Delta EDB$ and $\Delta VOB$ are similar.