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Concept explainers
(a)
To find: The ratio of perimeter of
(a)
![Check Mark](/static/check-mark.png)
Answer to Problem 13CE
The ratio of perimeter of
Explanation of Solution
Given information:
The givenfigure is shown below.
Calculation:
Therefore, the ratio of perimeter of
(b)
To find: The ratio of lateral area of the top part of the pyramid to the lateral area of whole pyramid.
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 13CE
The ratio of lateral area of the top part of the pyramid to the lateral area of whole pyramid is
Explanation of Solution
Given information:
The given figure is shown below.
Calculation:
Lateral area of pyramid in terms of base edge and height is
This means lateral area of pyramid is proportional to the base edge and slant height.
Consider the lateral area of cone is
Both the pyramid is similar so, ratio of base edge and slant height would be similar.
The ratio of lateral area of the top part of the pyramid to the lateral area of whole pyramid.
Therefore, the ratio of lateral area of the top part of the pyramid to the lateral area of whole pyramid is
(c)
To find: The ratio of lateral area of the top part of the pyramid to the lateral area of bottom part.
(c)
![Check Mark](/static/check-mark.png)
Answer to Problem 13CE
The ratio of lateral area of the top part of the pyramid to the lateral area of bottom part is
Explanation of Solution
Given information:
The given figure is shown below.
Calculation:
The ratio of lateral area of the top part of the pyramid to the lateral area of bottom part,
Therefore, the ratio of lateral area of the top part of the pyramid to the lateral area of bottom part is
(d)
To find: The ratio of the volume of the top part of the pyramid to the volume of bottom part.
(d)
![Check Mark](/static/check-mark.png)
Answer to Problem 13CE
The ratio of the volume of the top part of the pyramid to the volume of bottom part is
Explanation of Solution
Given information:
The given figure is shown below.
Calculation:
Volume of pyramid in terms of base edge and height is
This means volume of pyramid is proportion to the base are and height.
Both the pyramid is similar.
Consider the volume of cone is
The ratio of the volume of the top part of the pyramid to the volume of bottom part,
Therefore, the ratio of the volume of the top part of the pyramid to the volume of bottom part is
Chapter 12 Solutions
McDougal Littell Jurgensen Geometry: Student Edition Geometry
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- ◆ Switch To Light Mode HOMEWORK: 18, 19, 24, 27, 29 ***Please refer to the HOMEWORK sheet from Thursday, 9/14, for the problems ****Please text or email me if you have any questions 18. Figure 5-35 is a map of downtown Royalton, showing the Royalton River running through the downtown area and the three islands (A, B, and C) connected to each other and both banks by eight bridges. The Down- town Athletic Club wants to design the route for a marathon through the downtown area. Draw a graph that models the layout of Royalton. FIGURE 5-35 North Royalton Royalton River South Royption 19. A night watchman must walk the streets of the Green Hills subdivision shown in Fig. 5-36. The night watch- man needs to walk only once along each block. Draw a graph that models this situation.arrow_forwardSolve this question and check if my answer provided is correctarrow_forwardProof: LN⎯⎯⎯⎯⎯LN¯ divides quadrilateral KLMN into two triangles. The sum of the angle measures in each triangle is ˚, so the sum of the angle measures for both triangles is ˚. So, m∠K+m∠L+m∠M+m∠N=m∠K+m∠L+m∠M+m∠N=˚. Because ∠K≅∠M∠K≅∠M and ∠N≅∠L, m∠K=m∠M∠N≅∠L, m∠K=m∠M and m∠N=m∠Lm∠N=m∠L by the definition of congruence. By the Substitution Property of Equality, m∠K+m∠L+m∠K+m∠L=m∠K+m∠L+m∠K+m∠L=°,°, so (m∠K)+ m∠K+ (m∠L)= m∠L= ˚. Dividing each side by gives m∠K+m∠L=m∠K+m∠L= °.°. The consecutive angles are supplementary, so KN⎯⎯⎯⎯⎯⎯∥LM⎯⎯⎯⎯⎯⎯KN¯∥LM¯ by the Converse of the Consecutive Interior Angles Theorem. Likewise, (m∠K)+m∠K+ (m∠N)=m∠N= ˚, or m∠K+m∠N=m∠K+m∠N= ˚. So these consecutive angles are supplementary and KL⎯⎯⎯⎯⎯∥NM⎯⎯⎯⎯⎯⎯KL¯∥NM¯ by the Converse of the Consecutive Interior Angles Theorem. Opposite sides are parallel, so quadrilateral KLMN is a parallelogram.arrow_forward
- Quadrilateral BCDE is similar to quadrilateral FGHI. Find the measure of side FG. Round your answer to the nearest tenth if necessary. BCDEFGHI2737.55arrow_forwardAn angle measures 70.6° more than the measure of its supplementary angle. What is the measure of each angle?arrow_forwardName: Date: Per: Unit 7: Geometry Homework 4: Parallel Lines & Transversals **This is a 2-page document! ** Directions: Classify each angle pair and indicate whether they are congruent or supplementary. 1 1.23 and 25 2. 24 and 28 3. 22 and 25 4. 22 and 28 5. 21 and 27 6. 22 and 26 Directions: Find each angle measure. 7. Given: wvm25-149 m21- 8. Given: mn: m1=74 mz2- m22- m.23- m23- mz4= V mz4= m25= m26- m26= m27- m27 m28- m48= 9. Given: a || b: m28 125 m2- 10. Given: xy: m22-22 m21- = mz2- m43- m3- mZA m24-> m. 5- m25- m26- m.26=> m2]=> m27= m28- 11. Given: rm2-29: m15-65 m2=> m29-> m3- m. 10- mc4= m25= m212- m.46- m213- mat- m214- m28- & Gina when (N) Things ALICE 2017arrow_forward
- Match each statement to the set of shapes that best describes them. 1. Similar triangles by SSS 2. Similar triangles by SAS 3. Similar triangles by AA 4. The triangles are not similar > U E 35° 89° S F 89° J 35° 94° G 52° 90° E K 52° Iarrow_forwardMatch each transformation series with the diagram that applies to it. 1. (x, y) (x-10, y + 7) scale factor: 2 2. (x, y)(x-8, y+6) scale factor: 4 3. (x, y)(x+1, y - 5) scale factor: 5 D' 104º 6 2 -10 8 -6 F2 4 5 D 2 E -4 -6 100 E 8 10 Farrow_forwardWhich sets of figures below are similar? Select all that apply. 48 yd 48 yd G 48 yd 26 mm 40 m 23 km 25 m 22 mm 37 mm 25 mi 42 yd 48 yd 48 yd 48 yd U 42 yd 25 mm M T 40 mi 20 mm 25 mm 30 mi 48 m K 37 mm 20 mm 48 m S 30 mi 73 km 29 km 29 kmarrow_forward
- Elementary Geometry For College Students, 7eGeometryISBN:9781337614085Author:Alexander, Daniel C.; Koeberlein, Geralyn M.Publisher:Cengage,Elementary Geometry for College StudentsGeometryISBN:9781285195698Author:Daniel C. Alexander, Geralyn M. KoeberleinPublisher:Cengage Learning
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