Chapter 12.4, Problem 3CE

To determine

To complete: Copy and complete the table for sphere.

Answer to Problem 3CE

Area will be $36\pi t^2$ and volume $36\pi t^3$ .

Explanation of Solution

Given information:

The given radius is $3t$ .

Calculation:

The Area of sphere is given by

  $A=4\pi r^2$ and

The Volume is given by

  $V=\frac{4}{3}\pi r^3$ .

Here $r=3t$ . Therefore,

Area

  $\begin{array}{l}A=4\pi {\left(3t\right)}^2\\ A=4\pi \times 9t^2\\ A=36\pi t^2\end{array}$ and

Volume

  $\begin{array}{l}V=\frac{4}{3}\pi {\left(3t\right)}^3\\ V=\frac{4}{3}\pi \times 27t^3\\ V=36\pi t^3\end{array}$

Hence,

Area will be $36\pi t^2$ and volume $36\pi t^3$ .