Biology: The Dynamic Science (MindTap Course List)
4th Edition
ISBN: 9781305389892
Author: Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 12, Problem 9TYK
The ability of humans to taste the bitter chemical phenylthiocarbamide (PTC) is a genetic trait. People with at least one copy of the normal, dominant allele of the PTC gene can taste PTC; those who are homozygous for a mutant, recessive allele cannot taste it. Could two parents able to taste PTC have a nontaster child? Could nontaster parents have a child able to taste PTC? A pair of taster parents, both of whom had one parent able to taste PTC and one nontaster parent, are expecting their first child. What is the chance that the child will be able to taste PTC? Unable to taste PTC? Suppose the first child is a nontaster. What is the chance that their second child will also be unable to taste PTC?
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
At least two pairs of genes control eye color. Both pairs influence the production of the pigment, melanin, but act independently. One pair of alleles is B (Brown color; dominant) and b (blue color); the other pair is A (pigment production; dominant) and a (no pigment production; albino). The gene pair aais epistatic to (masks) B and b and produces the nonpigmented eyes of the albino. What is the typeof gene interaction that exists between the two gene pairs?
Give the genotypes and phenotypes of the possible offspring of the mating bbAa x Bbaa andi ndicate the parental phenotypes. (any method)
Red-green color blindness is inherited as an X-linked recessive (Xc). If a color-blind man marries a woman who is heterozygous for normal vision, what would be the expected phenotypes of their children with reference to this character? In your answer, specify in your phenotype descriptions the gender of the children. (For example, don’t just say 75% of the children would be colorblind – you would instead say 100 % of the daughters would be colorblind and 50% of the sons would be colorblind. Note that this is not a correct answer; it is just to give you an idea of how to explain the correct phenotypes of the cross.)___
In a cross between Aa Bb XCDXCD and Aa Bb XCDY, the A gene
controls earwax- where wet earwax is dominant to dry earwax. The B
gene controls the ability to taste the bitter compound PTC. Tasting is
dominant to non-tasting. A and B are found on different autosomal
chromosomes. The C gene controls color vision- color vision is
dominant to color blindness. And the D gene controls production of
dystrophin, the gene disrupted in Duchene's Muscular Dystrophy.
Individuals who have two copies of the recessive d allele or are
hemizygous for the recessive d allele have muscular dystrophy.
The parents have a child. What is the probability that child has wet
earwax, can taste PTC, can see color, and has DMD?
When the parents have 5 children. What is the probability that 4 of
them are tasters, 1 of them is a non-taster, and all of them have wet
earwax?
Chapter 12 Solutions
Biology: The Dynamic Science (MindTap Course List)
Ch. 12.1 - Two pairs of traits are segregating in a cross....Ch. 12.1 - If, instead, the four phenotypes in question 1...Ch. 12.2 - Palomino horses have a golden coat color, with a...Ch. 12.2 - A true-breeding rabbit with agouti (mottled,...Ch. 12 - The dominant C allele of a gene that controls...Ch. 12 - In peas, the allele Le produces tall plants and...Ch. 12 - Prob. 3TYKCh. 12 - What genotypes, and in what frequencies, will be...Ch. 12 - In addition to the two genes in problem 4, assume...Ch. 12 - Prob. 6TYK
Ch. 12 - In cats, the genotype AA produces tabby fur color;...Ch. 12 - Prob. 8TYKCh. 12 - The ability of humans to taste the bitter chemical...Ch. 12 - A man is homozygous dominant for alleles at 10...Ch. 12 - In guinea pigs, an allele for rough fur (R) is...Ch. 12 - Prob. 12TYKCh. 12 - Some recessive alleles have such a detrimental...Ch. 12 - In chickens, feathered legs are produced by a...Ch. 12 - A mix-up in a hospital ward caused a mother with O...Ch. 12 - Having malformed hands with shortened fingers is a...Ch. 12 - Prob. 17TYKCh. 12 - Design an Experiment Imagine that you are a...Ch. 12 - Prob. 19TYKCh. 12 - Prob. 1ITDCh. 12 - Prob. 2ITDCh. 12 - Half of the worlds population eats rice at least...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- A certain type of deafness in humans is inherited as an X-linked recessive trait. A man with this type of deafness married a normal woman, and they are expecting a child. They find out that they are distantly related. Part of the family tree is shown here.How would you advise the parents about the probability of their child being a deaf boy, a deaf girl, a normal boy, or a normal girl? Be sure to state any assumptions that you make.arrow_forwardThe ability to detect the bitter taste of Phenylthiocarbamide (PTC) is inherited. “Tasting” is controlled by a dominant allele, while “non-tasting” is recessive PTC paper placed in your mouth can determine if you are a “taster” or a “non-taster”? Let's assume that you are a "taster". What possible genotypes could produce your phenotype? If you produced children with a "non-taster", what genotypic and phenotypic ratios would be expected in your offspring?arrow_forwardIn humans, dark hair (D) is dominant over blondness (d), and color blindness (c) is a sex-linked recessive trait. A woman has a blond brother, a blond mother, and a dark-haired father. Her brother and her parents have normal vision. She bears the following three children by her blond, normal-visioned husband: a dark-haired son with normal vision, a dark-haired daughter with normal vision, and a dark-haired color blind son. Make a pedigree of the entire family showing the probable genotypes of all individuals.arrow_forward
- In humans, dark hair (D) is dominant over blondness (d), and color blindness (c) is a sex-linked recessive trait. A woman has a blond brother, a blond mother, and a dark-haired father. Her brother and her parents have normal vision. She bears the following three children by her blond, normal-visioned husband: a dark-haired son with normal vision, a dark-haired daughter with normal vision, and a dark-haired color blind son. What is the probability that her next (fourth) child will be a colorblind boy.arrow_forwardSickle cell anemia is a blood disorder that is expressed with incomplete dominance. The homozygous recessive phenotype has sickle shaped red blood cells that cause anemia and often death if untreated. If an unaffected father and mother move to the United States from Sub-Saharan Africa and several of their offspring have sickle cell anemia, what do we know about both parents' genotypes? One is homozygous recessive, the other is heterozygous They are both heterozygous They are both homozygous recessive One is homozygous dominant, the other is heterozygousarrow_forwardAs shown in the Punnett square below, one variety of deafness is caused by an autosomal recessive allele. Two parents who do not show any signs of the disease but are carriers could therefore have a child who is deaf, because that child could inherit one recessive deafness-causing gene from each parent. Imagine that a deaf male mates with a hearing female. We know the deaf male must have the genotype dd, but the female could be either Dd or DD. Such a mating is essentially a testcross, like the one shown in Figure 9.10. If the parents’ first child has hearing, can you say with certainty what the mother’s genotype must be? What if the couple has four children (none twins), all with hearing—can you say with certainty the mother’s genotype? What would it take for a definitive genotype to be assigned?arrow_forward
- In Humans, the ability to taste PTC is inherited as a dominant gene (T). In a marriage between 2 heterozygous tasters (Tt): (1) what is the probability of 3 taster children, (2) what is the probability of 3 taster girls, (3) Why is there a difference in the last two answers to this problem?arrow_forwardFor a recessive condition, two normal heterozygous individuals have children. What is the likelihood of their children being affected by this condition? What is the likelihood of their children being carriers without the condition? What is the likelihood of their asymptomatic children being carriers? Suppose that an individual with the condition has children with a heterozygous individual, what is the likelihood of their children being carriers?arrow_forwardAs seen in the photo, Labradors come in three colors-- black, brown and yellow. What is the genetic basis for these different coat colors? One gene produces melanin, a pigment which is deposited in the dog's fur and makes the color dark. With this gene, allele B (black) is dominant to allele b. Only in the case of a recessive homozygote (bb) will the dog's phenotype be brown. The regulatory gene is separate from the melanin gene but it acts as a switch, either turning the melanin gene on or turning it off. Allele E is dominant and allows for the melanin to be deposited in the dog's fur ("on" switch), but if the switch gene is a recessive homozygote, the melanin is blocked ("off" switch) and a yellow dog is the result! 1. Two other Labradors mate and produce puppies. Their genotypes are Bbee and BbEe. What color are each parent and what are the phenotypic rations of their offspring in the F1 Generation? Show your work with a Punnett square.arrow_forward
- Marfan syndrome is a disease caused by a rare dominant allele of the fibrillin-1 gene. Fibrillin-1 is an important component of the extracellular matrix, and people with the disease-causing allele have abnormal connective tissue. An affected mother (Marta) and an unaffected father (Joe) have one unaffected daughter (Luisa - she does not exhibit any traits of the syndrome). If Luisa has a child with Nico (unaffected), what is the probability that her child will inherit Marfan syndrome? Select one: a. 50% b. 25% c. 100% d. 0% e. 75%arrow_forwardHumans who have an abnormally high level of cholesterol are said to suer from familial hypercholesterolemia . The gene for this disorder is dominant (C). A man who is heterozygous for familial hypercholesterolemia marries a woman who is homozygous for the recessive allele. What is the probability that they will have children that suer from this disorder?arrow_forwardThe trait of having short eyelashes is recessive in humans. A male with short eyelashes has two children with a female. One child has short eyelashes and the other has the long eyelash phenotype. What are the genotypes of the two parents?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Human Biology (MindTap Course List)BiologyISBN:9781305112100Author:Cecie Starr, Beverly McMillanPublisher:Cengage Learning
Human Biology (MindTap Course List)
Biology
ISBN:9781305112100
Author:Cecie Starr, Beverly McMillan
Publisher:Cengage Learning
Mitochondrial mutations; Author: Useful Genetics;https://www.youtube.com/watch?v=GvgXe-3RJeU;License: CC-BY