The general principles which determine the molecular structure (shape) of a molecule are to be stated. Concept Introduction: The geometry of molecule is determined by electron pair present around the central atom. VSEPR theory is an important model that is frequently used in chemistry to decide the shape and geometry of the molecules. VSEPR model is the extension of Lewis model. As the Lewis model is not able to explain the shape of the molecules. The shape in VSEPR model gives specific angles between the bonds for the corresponding shape and these angles are known as bond angles.
The general principles which determine the molecular structure (shape) of a molecule are to be stated. Concept Introduction: The geometry of molecule is determined by electron pair present around the central atom. VSEPR theory is an important model that is frequently used in chemistry to decide the shape and geometry of the molecules. VSEPR model is the extension of Lewis model. As the Lewis model is not able to explain the shape of the molecules. The shape in VSEPR model gives specific angles between the bonds for the corresponding shape and these angles are known as bond angles.
Solution Summary: The author explains the general principles which determine the molecular structure (shape) of a molecule.
The general principles which determine the molecular structure (shape) of a molecule are to be stated.
Concept Introduction:
The geometry of molecule is determined by electron pair present around the central atom. VSEPR theory is an important model that is frequently used in chemistry to decide the shape and geometry of the molecules. VSEPR model is the extension of Lewis model. As the Lewis model is not able to explain the shape of the molecules.
The shape in VSEPR model gives specific angles between the bonds for the corresponding shape and these angles are known as bond angles.
Learning Goal:
This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this:
35 Cl
17
In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is:
It is also correct to write symbols by leaving off the atomic number, as in the following form:
atomic number
mass number Symbol
35 Cl or
mass number Symbol
This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons
are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written.
Watch this video to review the format for written symbols.
In the following table each column…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Chapter 12 Solutions
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