Loose Leaf for Engineering Circuit Analysis Format: Loose-leaf
9th Edition
ISBN: 9781259989452
Author: Hayt
Publisher: Mcgraw Hill Publishers
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Chapter 12, Problem 5E
To determine
The voltages
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1°
⑤
Aa
"Human-written solution required"
2. Using the characteristics of Fig. 6.11, determine ID for the following levels of VGs (with
VDS > VP):
a. VGs = 0V.
b. VGs=-1 V.
c. VGs -1.5 V.
d. VGS
-1.8 V.
e. VGS = -4 V.
f. VGs=-6V.
3. Using the results of problem 2 plot the transfer characteristics of ID vs. VGS-
4. a. Determine Vps for VGs = 0V and Ip = 6 mA using the characteristics of Fig. 6.11.
b. Using the results of part (a), calculate the resistance of the JFET for the region Ip = 0 to
6 mA for VGs =0V.
c. Determine Vps for VGS = -1 V and ID = 3 mA.
d. Using the results of part (c), calculate the resistance of the JFET for the region ID = 0 to
3 mA for VGs -1 V.
e. Determine Vps for VGs = -2 V and ID = 1.5 mA.
f. Using the results of part (e), calculate the resistance of the JFET for the region ID = 0 to
1.5 mA for VGS-2 V.
g. Defining the result of part (b) as ro, determine the resistance for VGs -1 V using
Eq. (6.1) and compare with the results of part (d).
h. Repeat part (g)…
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4. a. Determine VDs for VGS = 0 V and ID = 6 mA using the characteristics of Fig. 6.11.
b. Using the results of part (a), calculate the resistance of the JFET for the region ID = 0 to
6 mA for VGS = 0 V.
c. Determine VDs for VGS = -1 V and ID = 3 mA.
d. Using the results of part (c), calculate the resistance of the JFET for the region ID = 0 to
3 mA for VGS = -1 V.
e. Determine VDs for VGS = -2 V and ID = 1.5 mA.
f. Using the results of part (e), calculate the resistance of the JFET for the region ID = 0 to
1.5 mA for VGS = -2 V.
g. Defining the result of part (b) as ro, determine the resistance for VGS = -1 V using
Eq. (6.1) and compare with the results of part (d).
h. Repeat part (g) for VGS = -2 V using the same equation, and compare the results with part (f).
i. Based on the results of parts (g) and (h), does Eq. (6.1) appear to be a valid approximation?
Chapter 12 Solutions
Loose Leaf for Engineering Circuit Analysis Format: Loose-leaf
Ch. 12.1 - Let and . Find (a) Vad; (b) Vbc; (c) Vcd.Ch. 12.2 - Prob. 2PCh. 12.2 - Modify Fig. 12.9 by adding a 1.5 resistance to...Ch. 12.3 - A balanced three-phase three-wire system has a...Ch. 12.3 - A balanced three-phase three-wire system has a...Ch. 12.3 - Three balanced Y-connected loads are installed on...Ch. 12.4 - Each phase of a balanced three-phase -connected...Ch. 12.4 - Prob. 8PCh. 12.5 - Determine the wattmeter reading in Fig. 12.24,...Ch. 12.5 - Prob. 10P
Ch. 12 - Prob. 1ECh. 12 - Prob. 2ECh. 12 - Prob. 3ECh. 12 - Describe what is meant by a polyphase source,...Ch. 12 - Prob. 5ECh. 12 - Prob. 6ECh. 12 - Prob. 7ECh. 12 - Prob. 8ECh. 12 - Prob. 9ECh. 12 - Prob. 10ECh. 12 - The single-phase three-wire system of Fig. 12.31...Ch. 12 - Prob. 12ECh. 12 - Referring to the balanced load represented in Fig....Ch. 12 - Prob. 14ECh. 12 - Prob. 15ECh. 12 - Consider a simple positive phase sequence,...Ch. 12 - Assume the system shown in Fig. 12.34 is balanced,...Ch. 12 - Repeat Exercise 17 with Rw = 10 , and verify your...Ch. 12 - Prob. 19ECh. 12 - Prob. 20ECh. 12 - Prob. 21ECh. 12 - Prob. 22ECh. 12 - A three-phase system is constructed from a...Ch. 12 - Prob. 24ECh. 12 - Each load in the circuit of Fig. 12.34 is composed...Ch. 12 - Prob. 26ECh. 12 - Prob. 27ECh. 12 - A three-phase load is to be powered by a...Ch. 12 - For the two situations described in Exercise 28,...Ch. 12 - Prob. 30ECh. 12 - Prob. 31ECh. 12 - Prob. 32ECh. 12 - Repeat Exercise 32 if Rw = 1 . Verify your...Ch. 12 - Prob. 34ECh. 12 - Prob. 35ECh. 12 - Prob. 36ECh. 12 - A wattmeter is connected into the circuit of Fig....Ch. 12 - Find the reading of the wattmeter connected in the...Ch. 12 - (a) Find both wattmeter readings in Fig. 12.39 if...Ch. 12 - Circuit values for Fig. 12.40 are , , , , . Find...Ch. 12 - Prob. 41ECh. 12 - Prob. 42ECh. 12 - (a) Is the load represented in Fig. 12.41...Ch. 12 - Prob. 44E
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