EBK CHEMISTRY FOR CHANGING TIMES
14th Edition
ISBN: 8220100663482
Author: MCCREARY
Publisher: PEARSON
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Question
Chapter 12, Problem 55P
Interpretation Introduction
Interpretation:
Chemical reasons that a responsible for the uniqueness of katana must be explained
Concept Introduction:
- Metals are extracted from ores which either contain the pure metal or metals with other elements.
- An alloy is usually a mixture of two or more metals or a mixture of metals with non-metals.
- Alloys tend to be stronger and more resistant to damages than pure metals.
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3. Consider the compounds below and determine if they are aromatic, antiaromatic, or
non-aromatic. In case of aromatic or anti-aromatic, please indicate number of I
electrons in the respective systems. (Hint: 1. Not all lone pair electrons were explicitly
drawn and you should be able to tell that the bonding electrons and lone pair electrons
should reside in which hybridized atomic orbital 2. You should consider ring strain-
flexibility and steric repulsion that facilitates adoption of aromaticity or avoidance of anti-
aromaticity)
H H
N
N:
NH2
N
Aromaticity
(Circle)
Aromatic Aromatic Aromatic Aromatic Aromatic
Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic
nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic
aromatic TT
electrons
Me
H
Me
Aromaticity
(Circle)
Aromatic Aromatic Aromatic
Aromatic Aromatic
Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic
nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic
aromatic πT
electrons
H
HH…
A chemistry graduate student is studying the rate of this reaction:
2 HI (g) →H2(g) +12(g)
She fills a reaction vessel with HI and measures its concentration as the reaction proceeds:
time
(minutes)
[IH]
0
0.800M
1.0
0.301 M
2.0
0.185 M
3.0
0.134M
4.0
0.105 M
Use this data to answer the following questions.
Write the rate law for this reaction.
rate
= 0
Calculate the value of the rate constant k.
k =
Round your answer to 2 significant digits. Also be
sure your answer has the correct unit symbol.
Chapter 12 Solutions
EBK CHEMISTRY FOR CHANGING TIMES
Ch. 12 - Prob. 1RQCh. 12 - Prob. 2RQCh. 12 - Prob. 3RQCh. 12 - Prob. 4RQCh. 12 - Prob. 5RQCh. 12 - Prob. 6RQCh. 12 - Prob. 7RQCh. 12 - Prob. 8RQCh. 12 - Prob. 9RQCh. 12 - Prob. 10RQ
Ch. 12 - Prob. 11RQCh. 12 - Prob. 12RQCh. 12 - Prob. 13RQCh. 12 - Prob. 14PCh. 12 - Prob. 15PCh. 12 - Prob. 16PCh. 12 - Prob. 17PCh. 12 - Prob. 18PCh. 12 - Prob. 19PCh. 12 - Prob. 20PCh. 12 - Prob. 21PCh. 12 - Prob. 22PCh. 12 - Prob. 23PCh. 12 - Prob. 24PCh. 12 - Prob. 25PCh. 12 - Prob. 26PCh. 12 - Prob. 27PCh. 12 - Prob. 28PCh. 12 - Prob. 29PCh. 12 - Prob. 30PCh. 12 - Prob. 31PCh. 12 - Prob. 32PCh. 12 - Prob. 33PCh. 12 - Prob. 34PCh. 12 - Prob. 35PCh. 12 - Prob. 36PCh. 12 - Prob. 37PCh. 12 - Prob. 38PCh. 12 - Prob. 39PCh. 12 - Prob. 40PCh. 12 - Prob. 41PCh. 12 - Prob. 42PCh. 12 - Prob. 43PCh. 12 - Prob. 44PCh. 12 - Prob. 45PCh. 12 - Prob. 46PCh. 12 - Prob. 47PCh. 12 - Prob. 48PCh. 12 - Prob. 49PCh. 12 - Prob. 50PCh. 12 - Prob. 51PCh. 12 - Prob. 52PCh. 12 - Prob. 53PCh. 12 - Prob. 54PCh. 12 - Prob. 55PCh. 12 - Prob. 56PCh. 12 - Prob. 57PCh. 12 - Prob. 58PCh. 12 - Prob. 59PCh. 12 - Prob. 60PCh. 12 - Prob. 61PCh. 12 - 62. An aluminum plant produces 72 million kg of...Ch. 12 - Prob. 63APCh. 12 - Prob. 64APCh. 12 - Prob. 65APCh. 12 - Prob. 66APCh. 12 - Prob. 67APCh. 12 - Prob. 68APCh. 12 - Prob. 69APCh. 12 - Prob. 70APCh. 12 - Prob. 71APCh. 12 - Prob. 72APCh. 12 - Prob. 73APCh. 12 - Prob. 74APCh. 12 - Prob. 75APCh. 12 - Prob. 12.1CTECh. 12 - Prob. 12.2CTECh. 12 - Prob. 12.3CTECh. 12 - Prob. 12.4CTECh. 12 - Prob. 12.5CTECh. 12 - Prob. 12.6CTECh. 12 - Prob. 1CGPCh. 12 - Prob. 2CGPCh. 12 - Prepare a PowerPoint, poster, or other p1esentabon...Ch. 12 - Prob. 4CGPCh. 12 - Prob. 5CGPCh. 12 - Prob. 6CGPCh. 12 - Prob. 1CHQCh. 12 - Prob. 2CHQCh. 12 - Prob. 3CHQCh. 12 - Prob. 4CHQ
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- 1. For the four structures provided, Please answer the following questions in the table below. a. Please draw π molecular orbital diagram (use the polygon-and-circle method if appropriate) and fill electrons in each molecular orbital b. Please indicate the number of π electrons c. Please indicate if each molecule provided is anti-aromatic, aromatic, or non- aromatic TT MO diagram Number of π e- Aromaticity Evaluation (X choose one) Non-aromatic Aromatic Anti-aromatic || ||| + IVarrow_forward1.3 grams of pottasium iodide is placed in 100 mL of o.11 mol/L lead nitrate solution. At room temperature, lead iodide has a Ksp of 4.4x10^-9. How many moles of precipitate will form?arrow_forwardQ3: Circle the molecules that are optically active: ДДДДarrow_forward
- 6. How many peaks would be observed for each of the circled protons in the compounds below? 8 pts CH3 CH3 ΤΙ A. H3C-C-C-CH3 I (₁₁ +1)= 7 H CI B. H3C-C-CI H (3+1)=4 H LIH)=2 C. (CH3CH2-C-OH H D. CH3arrow_forwardNonearrow_forwardQ1: Draw the most stable and the least stable Newman projections about the C2-C3 bond for each of the following isomers (A-C). Are the barriers to rotation identical for enantiomers A and B? How about the diastereomers (A versus C or B versus C)? H Br H Br (S) CH3 (R) CH3 H3C (S) H3C H Br Br H A C enantiomers H Br H Br (R) CH3 H3C (R) (S) CH3 H3C H Br Br H B D identicalarrow_forward
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