Starting Out with Python (4th Edition)
4th Edition
ISBN: 9780134444321
Author: Tony Gaddis
Publisher: PEARSON
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Textbook Question
Chapter 12, Problem 4TF
In the base case, a recursive method calls itself with a smaller version of the original problem.
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Add a timer in the following code.
public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; private Timer timer; private long elapsedTime;
public GameGUI(Labyrinth labyrinth, Player player, Dragon dragon) { this.labyrinth = labyrinth; this.player = player; this.dragon = dragon; String playerName = JOptionPane.showInputDialog("Enter your name:"); player.setName(playerName); elapsedTime = 0; timer = new Timer(1000, e -> { elapsedTime++; repaint(); }); timer.start();
}
@Override protected void paintComponent(Graphics g) { super.paintComponent(g); int cellSize = Math.min(getWidth() / labyrinth.getSize(), getHeight() / labyrinth.getSize());}
Change the following code so that when player wins the game, the game continues by creating new GameGUI with the same player. However the player's starting position is same, everything else should be reseted.
public static void main(String[] args) { Labyrinth labyrinth = new Labyrinth(10); Player player = new Player(9, 0); Random rand = new Random(); Dragon dragon = new Dragon(rand.nextInt(10), 9); JFrame frame = new JFrame("Labyrinth Game"); GameGUI gui = new GameGUI(labyrinth, player, dragon);
frame.setLayout(new BorderLayout()); frame.setSize(600, 600); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.add(gui, BorderLayout.CENTER); frame.pack(); frame.setResizable(false); frame.setVisible(true); }
public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; private Timer timer; private long…
Create a menu item which restarts the game. Also add a timer, which counts the elapsed time since the start of the game level.
When the restart is pressed, the restarted game should ask the player' name (in the GameGUI constructor) and set the score of player to 0 (player.setScore(0)), and the timer should restart again. And create a logic so that if the player loses his life (checkGame if the condition is false), then save this number together with his name into two variables. And display two buttons where one quits the game altogether (System.exit(0)) and the other restarts the game.
public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon;
private final ImageIcon playerIcon = new ImageIcon("data/images/player.png"); private final ImageIcon dragonIcon = new ImageIcon("data/images/dragon.png"); private final ImageIcon wallIcon = new ImageIcon("data/images/wall.png"); private final ImageIcon…
Chapter 12 Solutions
Starting Out with Python (4th Edition)
Ch. 12.2 - It is said that a recursive algorithm has more...Ch. 12.2 - Prob. 2CPCh. 12.2 - What is a recursive case?Ch. 12.2 - What causes a recursive algorithm to stop calling...Ch. 12.2 - What is direct recursion? What is indirect...Ch. 12 - Prob. 1MCCh. 12 - A function is called once from a program's main...Ch. 12 - Prob. 3MCCh. 12 - Prob. 4MCCh. 12 - Prob. 5MC
Ch. 12 - Prob. 6MCCh. 12 - Any problem that can be solved recursively can...Ch. 12 - Actions taken by the computer when a function is...Ch. 12 - A recursive algorithm must _______ in the...Ch. 12 - A recursive algorithm must ______ in the base...Ch. 12 - An algorithm that uses a loop will usually run...Ch. 12 - Some problems can be solved through recursion...Ch. 12 - It is not necessary to have a base case in all...Ch. 12 - In the base case, a recursive method calls itself...Ch. 12 - In Program 12-2 , presented earlier in this...Ch. 12 - In this chapter, the rules given for calculating...Ch. 12 - Is recursion ever required to solve a problem?...Ch. 12 - When recursion is used to solve a problem, why...Ch. 12 - How is a problem usually reduced with a recursive...Ch. 12 - What will the following program display? def...Ch. 12 - Prob. 2AWCh. 12 - The following function uses a loop. Rewrite it as...Ch. 12 - Prob. 1PECh. 12 - Prob. 2PECh. 12 - Prob. 3PECh. 12 - Largest List Item Design a function that accepts a...Ch. 12 - Recursive List Sum Design a function that accepts...Ch. 12 - Prob. 6PECh. 12 - Prob. 7PECh. 12 - Ackermann's Function Ackermann's Function is a...
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- Please original work Analyze the complexity issues of processing big data What are five complexities and talk about the reasons they make the implementation complex. Please cite in text references and add weblinksarrow_forwardCreate a Database in JAVA Netbeans that saves name of the player and how many labyrinths did the player solve. Record the number of how many labyrinths did the player solve, and if he loses his life, then save this number together with his name into the database. Create a menu item, which displays a highscore table of the players for the 10 best scores public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; private void checkGameState() { if (player.getX() == 0 && player.getY() == labyrinth.getSize() - 1) { JOptionPane.showMessageDialog(this, "You escaped! Congratulations!"); System.exit(0); } if (Math.abs(player.getX() - dragon.getX()) <= 1 && Math.abs(player.getY() - dragon.getY()) <= 1) { JOptionPane.showMessageDialog(this, "The dragon caught you! Game Over."); System.exit(0); } } } public…arrow_forwardCreate a Database in JAVA OOP that saves name of the player and how many labyrinths did the player solve. Record the number of how many labyrinths did the player solve, and if he loses his life, then save this number together with his name into the database. Create a menu item, which displays a highscore table of the players for the 10 best scores. Also, create a menu item which restarts the game. public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; private void checkGameState() { if (player.getX() == 0 && player.getY() == labyrinth.getSize() - 1) { JOptionPane.showMessageDialog(this, "You escaped! Congratulations!"); System.exit(0); } if (Math.abs(player.getX() - dragon.getX()) <= 1 && Math.abs(player.getY() - dragon.getY()) <= 1) { JOptionPane.showMessageDialog(this, "The dragon caught you! Game Over.");…arrow_forward
- Change the following code so that the player can see only the neighboring fields at a distance of 3 units. public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; private final ImageIcon playerIcon = new ImageIcon("data/images/player.png"); private final ImageIcon dragonIcon = new ImageIcon("data/images/dragon.png"); private final ImageIcon wallIcon = new ImageIcon("data/images/wall.png"); private final ImageIcon emptyIcon = new ImageIcon("data/images/empty.png"); public GameGUI(Labyrinth labyrinth, Player player, Dragon dragon) { this.labyrinth = labyrinth; this.player = player; this.dragon = dragon; setFocusable(true); addKeyListener(new KeyAdapter() { @Override public void keyPressed(KeyEvent e) { char move = switch (e.getKeyCode()) { case KeyEvent.VK_W -> 'W'; case…arrow_forwardQ/ Fill in the table below with the correct answers for the network devices and components required, then draw the topology diagram for the network of this three-story building: I want a drawing Cisco Packet tracer Ground Floor: This floor will house the main server room, reception area, and a few conference rooms. The server room should contain the core network devices that will connect the entire building. The reception area and conference rooms need network access require access for mobile devices for visitors and guests with devices. First Floor: This floor is dedicated to offices with workstations, each needing reliable network connectivity for staff computers, IP phones, IP camera, and printers. Second Floor (Education Department): This floor consists of educational spaces requiring controlled internet access. Only the educational website (https://uokerbala.edu.iq) should be accessible, with all other sites restricted.. Device Media type Location floor Type of IP Static/dynamic…arrow_forwardProblem Statement You are working as a Devops Administrator. Y ou’ve been t asked to deploy a multi - tier application on Kubernetes Cluster. The application is a NodeJS application available on Docker Hub with the following name: d evopsedu/emp loyee This Node JS application works with a mongo database. MongoDB image is available on D ockerHub with the following name: m ongo You are required to deploy this application on Kubernetes: • NodeJS is available on port 8888 in the container and will be reaching out to por t 27017 for mongo database connection • MongoDB will be accepting connections on port 27017 You must deploy this application using the CL I . Once your application is up and running, ensure you can add an employee from the NodeJS application and verify by going to Get Employee page and retrieving your input. Hint: Name the Mongo DB Service and deployment, specifically as “mongo”.arrow_forward
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- Change the following code so that there is always at least one way to get from the left corner to the top right, but the labyrinth is still randomized. The player starts at the bottom left corner of the labyrinth. He has to get to the top right corner of the labyrinth as fast he can, avoiding a meeting with the evil dragon. Take care that the player and the dragon cannot start off on walls. Also the dragon starts off from a randomly chosen position public class Labyrinth { private final int size; private final Cell[][] grid; public Labyrinth(int size) { this.size = size; this.grid = new Cell[size][size]; generateLabyrinth(); } private void generateLabyrinth() { Random rand = new Random(); for (int i = 0; i < size; i++) { for (int j = 0; j < size; j++) { // Randomly create walls and paths grid[i][j] = new Cell(rand.nextBoolean()); } } // Ensure start and end are…arrow_forwardChange the following code so that it checks the following 3 conditions: 1. there is no space between each cells (imgs) 2. even if it is resized, the components wouldn't disappear 3. The GameGUI JPanel takes all the JFrame space, so that there shouldn't be extra space appearing in the frame other than the game. Main(): Labyrinth labyrinth = new Labyrinth(10); Player player = new Player(9, 0); Dragon dragon = new Dragon(9, 9); JFrame frame = new JFrame("Labyrinth Game"); GameGUI gui = new GameGUI(labyrinth, player, dragon); frame.add(gui); frame.setSize(600, 600); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setVisible(true); public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; //labyrinth, player, dragon are just public classes private final ImageIcon playerIcon = new ImageIcon("data/images/player.png");…arrow_forwardMake the following game user friendly with GUI, with some simple graphics. The GUI should be in another seperate class, with some ImageIcon, and Game class should be added into the pane. The following code works as this: The objective of the player is to escape from this labyrinth. The player starts at the bottom left corner of the labyrinth. He has to get to the top right corner of the labyrinth as fast he can, avoiding a meeting with the evil dragon. The player can move only in four directions: left, right, up or down. There are several escape paths in all labyrinths. The player’s character should be able to moved with the well known WASD keyboard buttons. If the dragon gets to a neighboring field of the player, then the player dies. Because it is dark in the labyrinth, the player can see only the neighboring fields at a distance of 3 units. Cell Class: public class Cell { private boolean isWall; public Cell(boolean isWall) { this.isWall = isWall; } public boolean isWall() { return…arrow_forward
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