Discovering Computers ©2018: Digital Technology, Data, and Devices
1st Edition
ISBN: 9781337285100
Author: Misty E. Vermaat, Susan L. Sebok, Steven M. Freund, Jennifer T. Campbell, Mark Frydenberg
Publisher: Cengage Learning
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Expert Solution & Answer
Chapter 12, Problem 22SG
Explanation of Solution
Role of corporate trainer:
- The individuals with good knowledge are used for educating the users about required technology.
- Similarly, corporate trainer will train the employees about the technology...
Expert Solution & Answer
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Students have asked these similar questions
Transform the TM below that accepts words over the alphabet Σ= {a, b} with an even number of
a's and b's in order that the output tape head is positioned over the first letter of the input, if the
word is accepted, and all letters a should be replaced by the letter x.
For example, for the input aabbaa the tape and head at the end should be:
[x]xbbxx
z/z,R
b/b,R
F
①
a/a,R
b/b,R
a/a, R
a/a,R
b/b.R
K
a/a,R
L
b/b,R
Given the C++ code below, create a TM that performs the same operation, i.e., given an input
over the alphabet Σ= {a, b} it prints the number of letters b in binary.
1 #include
2 #include
3
4- int main() {
std::cout > str;
for (char c : str) {
if (c == 'b')
count++;
5
std::string str;
6
int count = 0;
7
char buffer [1000];
8
9
10
11-
12
13
14
}
15
16-
17
18
19
}
20
21
22}
std::string binary
while (count > 0) {
binary = std::to_string(count % 2) + binary;
count /= 2;
std::cout << binary << std::endl;
return 0;
Considering the CFG described below, answer the following questions.
Σ = {a, b}
• NT = {S}
Productions:
P1 S⇒aSa
P2
P3
SbSb
S⇒ a
P4 S⇒ b
A. List one sequence of productions that can accept the word abaaaba;
B. Give three 5-letter words that can be accepted by this CFG;
C. Create a Pushdown automaton capable of accepting the language accepted by this CFG.
Chapter 12 Solutions
Discovering Computers ©2018: Digital Technology, Data, and Devices
Ch. 12 - Prob. 1SGCh. 12 - Prob. 2SGCh. 12 - Prob. 3SGCh. 12 - Prob. 4SGCh. 12 - Prob. 5SGCh. 12 - Prob. 6SGCh. 12 - Prob. 7SGCh. 12 - Prob. 8SGCh. 12 - Prob. 9SGCh. 12 - Prob. 10SG
Ch. 12 - Prob. 11SGCh. 12 - Prob. 12SGCh. 12 - Prob. 13SGCh. 12 - Prob. 14SGCh. 12 - Prob. 15SGCh. 12 - Prob. 16SGCh. 12 - Prob. 17SGCh. 12 - Prob. 18SGCh. 12 - Prob. 19SGCh. 12 - Prob. 20SGCh. 12 - Prob. 21SGCh. 12 - Prob. 22SGCh. 12 - Prob. 23SGCh. 12 - Prob. 24SGCh. 12 - Prob. 25SGCh. 12 - Prob. 26SGCh. 12 - Prob. 27SGCh. 12 - Prob. 28SGCh. 12 - Prob. 29SGCh. 12 - Prob. 30SGCh. 12 - Prob. 31SGCh. 12 - Prob. 32SGCh. 12 - Prob. 33SGCh. 12 - Prob. 34SGCh. 12 - Prob. 35SGCh. 12 - Prob. 36SGCh. 12 - Prob. 37SGCh. 12 - Prob. 38SGCh. 12 - Prob. 39SGCh. 12 - Prob. 40SGCh. 12 - Prob. 41SGCh. 12 - Prob. 42SGCh. 12 - Prob. 43SGCh. 12 - Prob. 44SGCh. 12 - Prob. 45SGCh. 12 - Prob. 1TFCh. 12 - Prob. 2TFCh. 12 - Prob. 3TFCh. 12 - Prob. 4TFCh. 12 - Prob. 5TFCh. 12 - Prob. 6TFCh. 12 - Prob. 7TFCh. 12 - Prob. 8TFCh. 12 - Prob. 9TFCh. 12 - Prob. 10TFCh. 12 - Prob. 11TFCh. 12 - Prob. 12TFCh. 12 - Prob. 1MCCh. 12 - Prob. 2MCCh. 12 - Prob. 3MCCh. 12 - A(n) _____ report consolidates data usually with...Ch. 12 - Prob. 5MCCh. 12 - Prob. 6MCCh. 12 - Prob. 7MCCh. 12 - Prob. 8MCCh. 12 - Prob. 1MCh. 12 - Prob. 2MCh. 12 - Prob. 3MCh. 12 - Prob. 4MCh. 12 - Prob. 5MCh. 12 - Prob. 6MCh. 12 - Prob. 7MCh. 12 - Prob. 8MCh. 12 - Prob. 9MCh. 12 - Prob. 10MCh. 12 - Prob. 2CTCh. 12 - Prob. 3CTCh. 12 - Prob. 4CTCh. 12 - Prob. 5CTCh. 12 - Prob. 6CTCh. 12 - Prob. 7CTCh. 12 - Prob. 8CTCh. 12 - Prob. 9CTCh. 12 - Prob. 10CTCh. 12 - Prob. 11CTCh. 12 - Prob. 12CTCh. 12 - Prob. 13CTCh. 12 - Prob. 14CTCh. 12 - Prob. 15CTCh. 12 - Prob. 16CTCh. 12 - Prob. 17CTCh. 12 - Prob. 18CTCh. 12 - Prob. 19CTCh. 12 - Prob. 20CTCh. 12 - Prob. 21CTCh. 12 - Prob. 22CTCh. 12 - Prob. 23CTCh. 12 - Prob. 24CTCh. 12 - Prob. 25CTCh. 12 - Prob. 26CTCh. 12 - Prob. 27CTCh. 12 - Prob. 28CTCh. 12 - Prob. 29CTCh. 12 - Prob. 1PSCh. 12 - Prob. 2PSCh. 12 - Prob. 3PSCh. 12 - Prob. 4PSCh. 12 - Prob. 5PSCh. 12 - Prob. 6PSCh. 12 - Prob. 7PSCh. 12 - Prob. 8PSCh. 12 - Prob. 9PSCh. 12 - Prob. 10PSCh. 12 - Prob. 11PSCh. 12 - Prob. 1.1ECh. 12 - Prob. 1.2ECh. 12 - Prob. 1.3ECh. 12 - Prob. 2.1ECh. 12 - Prob. 2.2ECh. 12 - Prob. 3.1ECh. 12 - Prob. 3.2ECh. 12 - Prob. 1IRCh. 12 - Prob. 2IRCh. 12 - Prob. 4IRCh. 12 - Prob. 5IRCh. 12 - Prob. 1CTQCh. 12 - Prob. 3CTQCh. 12 - Prob. 4CTQ
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