Discovering Computers ©2018: Digital Technology, Data, and Devices
1st Edition
ISBN: 9781337285100
Author: Misty E. Vermaat, Susan L. Sebok, Steven M. Freund, Jennifer T. Campbell, Mark Frydenberg
Publisher: Cengage Learning
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Chapter 12, Problem 12SG
Explanation of Solution
Components of information literacy:
The information literacy includes five different components and they are as follows.
- Digital literacy: It is used for understanding the information related to education and employment.
- Library instruction: In this, the data is stored and organized in various relevant sources...
Explanation of Solution
Steps for effective research and composition:
The steps present in effective research and composition are given below.
- Select the required topic: Search for the topics and select the appropriate one.
- Identify the sources: Acquire the inform...
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1.[30 pts] Computers generate color pictures on a video screen or liquid crystal display by
mixing three different colors of light: red, green, and blue. Imagine a simple scheme, with
three different lights, each of which can be turned on or off, projecting onto a glass screen:
We can create eight different colors based on the absence (0) or presence (1) of light
sources R,G and B:
R
G
B
Color
0
0
0
Black
0
0
1
Blue
0
1
0
Green
0
1
1
Cyan
1
0
0
Red
1
0
1
Magenta
1
1
1
0
Yellow
1
White
1
Each of these colors can be represented as a bit vector of length 3, and we can apply
Boolean operations to them.
a. The complement of a color is formed by turning off the lights that are on and turning
on the lights that are off. What would be the complement of each of the eight colors
listed above?
b. Describe the effect of applying Boolean operations on the following colors:
Λ
1. Red(100) ^ Magenta(101)= Blue(001)
2. Bue(001) | Green(010)=
3. Yellow(100) & Cyan(011)=
2.[30 pts] Perform the following…
D. S. Malik, Data Structures Using C++, 2nd Edition, 2010
Methods (Ch6) - Review
1. (The MyRoot method) Below is a manual implementation of the Math.sqrt() method in Java.
There are two methods, method #1 which calculates the square root for positive integers, and
method #2, which calculates the square root of positive doubles (also works for integers).
public class SquareRoot {
public static void main(String[] args) {
}
// implement a loop of your choice here
// Method that calculates the square root of integer variables
public static double myRoot(int number) {
double root;
root=number/2;
double root old;
do {
root old root;
root (root_old+number/root_old)/2;
} while (Math.abs(root_old-root)>1.8E-6);
return root;
}
// Method that calculates the square root of double variables
public static double myRoot(double number) {
double root;
root number/2;
double root_old;
do {
root old root;
root (root_old+number/root_old)/2;
while (Math.abs (root_old-root)>1.0E-6);
return root;
}
}
Program-it-Yourself: In the main method, create a program that…
Chapter 12 Solutions
Discovering Computers ©2018: Digital Technology, Data, and Devices
Ch. 12 - Prob. 1SGCh. 12 - Prob. 2SGCh. 12 - Prob. 3SGCh. 12 - Prob. 4SGCh. 12 - Prob. 5SGCh. 12 - Prob. 6SGCh. 12 - Prob. 7SGCh. 12 - Prob. 8SGCh. 12 - Prob. 9SGCh. 12 - Prob. 10SG
Ch. 12 - Prob. 11SGCh. 12 - Prob. 12SGCh. 12 - Prob. 13SGCh. 12 - Prob. 14SGCh. 12 - Prob. 15SGCh. 12 - Prob. 16SGCh. 12 - Prob. 17SGCh. 12 - Prob. 18SGCh. 12 - Prob. 19SGCh. 12 - Prob. 20SGCh. 12 - Prob. 21SGCh. 12 - Prob. 22SGCh. 12 - Prob. 23SGCh. 12 - Prob. 24SGCh. 12 - Prob. 25SGCh. 12 - Prob. 26SGCh. 12 - Prob. 27SGCh. 12 - Prob. 28SGCh. 12 - Prob. 29SGCh. 12 - Prob. 30SGCh. 12 - Prob. 31SGCh. 12 - Prob. 32SGCh. 12 - Prob. 33SGCh. 12 - Prob. 34SGCh. 12 - Prob. 35SGCh. 12 - Prob. 36SGCh. 12 - Prob. 37SGCh. 12 - Prob. 38SGCh. 12 - Prob. 39SGCh. 12 - Prob. 40SGCh. 12 - Prob. 41SGCh. 12 - Prob. 42SGCh. 12 - Prob. 43SGCh. 12 - Prob. 44SGCh. 12 - Prob. 45SGCh. 12 - Prob. 1TFCh. 12 - Prob. 2TFCh. 12 - Prob. 3TFCh. 12 - Prob. 4TFCh. 12 - Prob. 5TFCh. 12 - Prob. 6TFCh. 12 - Prob. 7TFCh. 12 - Prob. 8TFCh. 12 - Prob. 9TFCh. 12 - Prob. 10TFCh. 12 - Prob. 11TFCh. 12 - Prob. 12TFCh. 12 - Prob. 1MCCh. 12 - Prob. 2MCCh. 12 - Prob. 3MCCh. 12 - A(n) _____ report consolidates data usually with...Ch. 12 - Prob. 5MCCh. 12 - Prob. 6MCCh. 12 - Prob. 7MCCh. 12 - Prob. 8MCCh. 12 - Prob. 1MCh. 12 - Prob. 2MCh. 12 - Prob. 3MCh. 12 - Prob. 4MCh. 12 - Prob. 5MCh. 12 - Prob. 6MCh. 12 - Prob. 7MCh. 12 - Prob. 8MCh. 12 - Prob. 9MCh. 12 - Prob. 10MCh. 12 - Prob. 2CTCh. 12 - Prob. 3CTCh. 12 - Prob. 4CTCh. 12 - Prob. 5CTCh. 12 - Prob. 6CTCh. 12 - Prob. 7CTCh. 12 - Prob. 8CTCh. 12 - Prob. 9CTCh. 12 - Prob. 10CTCh. 12 - Prob. 11CTCh. 12 - Prob. 12CTCh. 12 - Prob. 13CTCh. 12 - Prob. 14CTCh. 12 - Prob. 15CTCh. 12 - Prob. 16CTCh. 12 - Prob. 17CTCh. 12 - Prob. 18CTCh. 12 - Prob. 19CTCh. 12 - Prob. 20CTCh. 12 - Prob. 21CTCh. 12 - Prob. 22CTCh. 12 - Prob. 23CTCh. 12 - Prob. 24CTCh. 12 - Prob. 25CTCh. 12 - Prob. 26CTCh. 12 - Prob. 27CTCh. 12 - Prob. 28CTCh. 12 - Prob. 29CTCh. 12 - Prob. 1PSCh. 12 - Prob. 2PSCh. 12 - Prob. 3PSCh. 12 - Prob. 4PSCh. 12 - Prob. 5PSCh. 12 - Prob. 6PSCh. 12 - Prob. 7PSCh. 12 - Prob. 8PSCh. 12 - Prob. 9PSCh. 12 - Prob. 10PSCh. 12 - Prob. 11PSCh. 12 - Prob. 1.1ECh. 12 - Prob. 1.2ECh. 12 - Prob. 1.3ECh. 12 - Prob. 2.1ECh. 12 - Prob. 2.2ECh. 12 - Prob. 3.1ECh. 12 - Prob. 3.2ECh. 12 - Prob. 1IRCh. 12 - Prob. 2IRCh. 12 - Prob. 4IRCh. 12 - Prob. 5IRCh. 12 - Prob. 1CTQCh. 12 - Prob. 3CTQCh. 12 - Prob. 4CTQ
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