
Concept explainers
Repeat Exercise 2 in Chapter 7, but use an instance of ArrayList instead of an array. Do not read the number of values, but continue to read values until the user enters a negative value.

Explanation of Solution
Program Plan:
- Import required package.
- Define “CountFamiles”class.
- Define main function.
- Create object for scanner class.
- Create array “incomeArr” by using “ArrayList”.
- Display the prompt statement.
- Assign “additionalValues” to “true”.
- Initializes required variable.
- Read input of income from user up to the value of “additionalValues” is “false”.
- Display prompt statement for each family.
- Read each family income from user and store it to “incomeValues”.
- If “incomeValues” is less than “0”, then set “additionalValues” to “false”.
- Otherwise, add the “incomeValues” to array “incomeArr”.
- Increment the index.
- Compute maximum income using “for” loop.
- If “incomeArr.get(i)” is greater than maximum income, then assign maximum income to “incomeArr.get(i)”.
- Display maximum income.
- Display “10” percent of maximum income by “0.1 * maximumIncome”.
- Initializes the count value to “0”.
- Compute the count of families with incomes less than “10” percentage of maximum income using “for” loop.
- Check condition. If value of “incomeArr.get(i)” is less than “0.1 * maximumIncome”, then increment count value and display the family income with less than “10” percentage of income by family wise.
- Finally display the count of families.
- Define main function.
Program:
The below java program is used to counts the number of families with less than “10” percent of maximum income using array.
“CountFamiles.java”
//Import required package
import java.util.*;
//Define "CountFamiles" class
public class CountFamiles
{
//Define main function
public static void main(String[] args)
{
//Create object for scanner class
Scanner input = new Scanner(System.in);
/* Create array "incomeArr" by using "ArrayList" */
ArrayList<Double> incomeArr = new ArrayList<Double>();
//Display the prompt statement
System.out.println("Enter the income for each family. Use a negative value to indicate the end ");
//Assign "additionalValues" to "true"
boolean additionalValues = true;
//Initializes required variable
int i = 0;
/* Read input of income from user upto the value of "additionalValues" is "false" */
while(additionalValues)
{
//Display prompt statement for each family
System.out.print("Enter Income for family " + (i +1) + ": ");
/* Read each family income from user and store it to "incomeValues" */
double incomeValues = input.nextDouble();
/* If "incomeValues" is less than "0", then */
if(incomeValues < 0)
/* Set "additionalValues" to "false" */
additionalValues = false;
/* Otherwise */
else
/* Add the "incomeValues" to array "incomeArr" */
incomeArr.add(incomeValues);
//Increment the index
i++;
}
//Compute maximum income using "for" loop
double maximumIncome = incomeArr.get(0);
for(i = 0; i < incomeArr.size(); i ++)
{
/* If incomeArr.get[i] is greater than maximum income, then */
if(incomeArr.get(i) > maximumIncome)
//Assign maximum income to "incomeArr.get(i)"
maximumIncome = incomeArr.get(i);
}
//Display maximum income
System.out.println("The maximum income is: " + maximumIncome);
//Display 10 percent of maximum income
System.out.println("10% of maximum income is: " + (0.1 * maximumIncome));
//Display prompt statement
System.out.println("\nDisplaying all families with incomes less than 10% of the maximum income income");
//Initializes the count value to "0"
int countValue = 0;
//Compute the count of families with incomes less than 10% of maximum income
for( i=0; i<incomeArr.size(); i++)
{
//Check condition
if(incomeArr.get(i) < (0.1 * maximumIncome))
{
//Increment count value
countValue++;
/* Display the family income with less than 10 percentage of income by family wise */
System.out.println("Family " + (i+1) + " had income " + incomeArr.get(i));
}
}
//Display count of families
System.out.println("Count of families with 10% of maximum income is: " + countValue);
}
}
Output:
Enter the income for each family. Use a negative value to indicate the end
Enter Income for family 1: 10000
Enter Income for family 2: 48000
Enter Income for family 3: 20000
Enter Income for family 4: 12000
Enter Income for family 5: 300000
Enter Income for family 6: 40000
Enter Income for family 7: -1
The maximum income is: 300000.0
10% of maximum income is: 30000.0
Displaying all families with incomes less than 10% of the maximum income
Family 1 had income 10000.0
Family 3 had income 20000.0
Family 4 had income 12000.0
Count of families with 10% of maximum income is: 3
Want to see more full solutions like this?
Chapter 12 Solutions
Java: An Introduction to Problem Solving and Programming (7th Edition)
Additional Engineering Textbook Solutions
Problem Solving with C++ (10th Edition)
Starting Out With Visual Basic (8th Edition)
Starting Out with Java: From Control Structures through Data Structures (4th Edition) (What's New in Computer Science)
Computer Science: An Overview (13th Edition) (What's New in Computer Science)
SURVEY OF OPERATING SYSTEMS
Starting Out with Java: From Control Structures through Objects (7th Edition) (What's New in Computer Science)
- My code is experincing minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place. My code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2 * pi * f; % Angular frequency % Parameters for the filters - let's adjust these to get more reasonable cutoffs R = 1e3; % Resistance in ohms (1 kΩ) C = 1e-6; % Capacitance in farads (1 μF) % For bandpass, we need appropriate L value for desired cutoffs L = 0.1; % Inductance in henries - adjusted for better bandpass response % Calculate cutoff frequencies first to verify they're in desired range f_cutoff_RC = 1 / (2 * pi * R * C); f_resonance = 1 / (2 * pi * sqrt(L * C)); Q_factor = (1/R) * sqrt(L/C); f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor)); f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor)); % Transfer functions % Low-pass filter (RC) H_low = 1 ./ (1 + 1i * w *…arrow_forwardI would like to know the main features about the following three concepts: 1. Default forwarded 2. WINS Server 3. IP Security (IPSec).arrow_forwardmap the following ER diagram into a relational database schema diagram. you should take into account all the constraints in the ER diagram. Underline the primary key of each relation, and show each foreign key as a directed arrow from the referencing attributes (s) to the referenced relation. NOTE: Need relational database schema diagramarrow_forward
- What is business intelligence? Share the Business intelligence (BI) tools you have used and explain what types of decisions you made.arrow_forwardI need help fixing the minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place. My code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2 * pi * f; % Angular frequency % Parameters for the filters - let's adjust these to get more reasonable cutoffs R = 1e3; % Resistance in ohms (1 kΩ) C = 1e-6; % Capacitance in farads (1 μF) % For bandpass, we need appropriate L value for desired cutoffs L = 0.1; % Inductance in henries - adjusted for better bandpass response % Calculate cutoff frequencies first to verify they're in desired range f_cutoff_RC = 1 / (2 * pi * R * C); f_resonance = 1 / (2 * pi * sqrt(L * C)); Q_factor = (1/R) * sqrt(L/C); f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor)); f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor)); % Transfer functions % Low-pass filter (RC) H_low = 1 ./ (1 + 1i * w *…arrow_forwardTask 3. i) Compare your results from Tasks 1 and 2. j) Repeat Tasks 1 and 2 for 500 and 5,000 elements. k) Summarize run-time results in the following table: Time/size n String StringBuilder 50 500 5,000arrow_forward
- Can you please solve this without AIarrow_forward1. Create a Vehicle.java file. Implement the public Vehicle and Car classes in Vehicle.java, including all the variables and methods in the UMLS. Vehicle - make: String model: String -year: int + Vehicle(String make, String, model, int, year) + getMake(): String + setMake(String make): void + getModel(): String + setModel(String model): void + getYear(): int + set Year(int year): void +toString(): String Car - numDoors: int + numberOfCar: int + Car(String make, String, model, int, year, int numDoors) + getNumDoors(): int + setNumDoors (int num Doors): void + toString(): String 2. Create a CarTest.java file. Implement a public CarTest class with a main method. In the main method, create one Car object and print the object using System.out.println(). Then, print the numberOfCar. Your printing result must follow the example output: make Toyota, model=Camry, year=2022 numDoors=4 1 Hint: You need to modify the toString methods in the Car class and Vehicle class!arrow_forwardCHATGPT GAVE ME WRONG ANSWER PLEASE HELParrow_forward
- HELP CHAT GPT GAVE ME WRONG ANSWER Consider the following implementation of a container that will be used in a concurrent environment. The container is supposed to be used like an indexed array, but provide thread-safe access to elements. struct concurrent_container { // Assume it’s called for any new instance soon before it’s ever used void concurrent_container() { init_mutex(&lock); } ~concurrent_container() { destroy_mutex(&lock); } // Returns element by its index. int get(int index) { lock.acquire(); if (index < 0 || index >= size) { return -1; } int result = data[index]; lock.release(); return result; } // Sets element by its index. void set(int index, int value) { lock.acquire(); if (index < 0 || index >= size) { resize(size); } data[index] = value; lock.release(); } // Extend maximum capacity of the…arrow_forwardWrite a C program using embedded assembler in which you use your own function to multiply by two without using the product. Tip: Just remember that multiplying by two in binary means shifting the number one place to the left. You can use the sample program from the previous exercise as a basis, which increments a variable. Just replace the INC instruction with SHL.arrow_forwardusing r languagearrow_forward
- EBK JAVA PROGRAMMINGComputer ScienceISBN:9781337671385Author:FARRELLPublisher:CENGAGE LEARNING - CONSIGNMENTProgramming Logic & Design ComprehensiveComputer ScienceISBN:9781337669405Author:FARRELLPublisher:CengageC++ Programming: From Problem Analysis to Program...Computer ScienceISBN:9781337102087Author:D. S. MalikPublisher:Cengage Learning
- Microsoft Visual C#Computer ScienceISBN:9781337102100Author:Joyce, Farrell.Publisher:Cengage Learning,Programming with Microsoft Visual Basic 2017Computer ScienceISBN:9781337102124Author:Diane ZakPublisher:Cengage LearningNp Ms Office 365/Excel 2016 I NtermedComputer ScienceISBN:9781337508841Author:CareyPublisher:Cengage



