Display student class details “HashMap” and “ArrayList” Program Plan: Import required package. Define “StudentIDsListTest” class. Define main function. Create hashmap for student ID and course number. Create an object for scanner class. Declare required variables. Display prompt statement. Performs “do-while” loop. This loop will execute until “studID” is not equal to “-1”. Read student ID from user. If student ID is not equal to “-1”, then read course number from user. If the student ID is contains in “students” list, then Create array list named “class_List”. Add the course number to “class_List” using “add” method. Map the student ID to course number using “put” method. Otherwise, Create array list named “class_List”. If the course number is not in the class list, then add the given course number to “class_List” using “add” method. Display all the classes for each student using “for” loop. Create array list named “stud_List”. Display course number for corresponding student ID.

Question

(1 point) By dragging statements from the left column to the right column below, give a proof by induction of the following statement: an = = 9" - 1 is a solution to the recurrence relation an = 9an-18 with ao = : 0. The correct proof will use 8 of the statements below. Statements to choose from: Note that a₁ = 9a0 + 8. Now assume that P(n) is true for all n ≥ 0. Your Proof: Put chosen statements in order in this column and press the Submit Answers button. Let P(n) be the predicate, "a = 9″ – 1". απ = 90 − 1 = Note that Let P(n) be the predicate, "an 9" - 1 is a solution to the recurrence relation an = 9an-1 +8 with ao = 0." - Now assume that P(k + 1) is true. Thus P(k) is true for all k. Thus P(k+1) is true. Then ak+1 = 9ak +8, so P(k + 1) is true. = 1 − 1 = 0, as required. Then = 9k — 1. ak Now assume that P(k) is true for an arbitrary integer k ≥ 1. By the recurrence relation, we have ak+1 = ak+1 = = 9ak + 8 = 9(9k − 1) + 8 This simplifies to 9k+19+8 = 9k+1 − 1 Then 9k+1 − 1 = 9(9*…

Answer 1

Question

Chapter 12, Problem 15PP

Program Plan Intro

Display student class details “HashMap” and “ArrayList”

Program Plan:

Import required package.

Define “StudentIDsListTest” class.

Define main function.

Create hashmap for student ID and course number.

Create an object for scanner class.

Declare required variables.

Display prompt statement.

Performs “do-while” loop. This loop will execute until “studID” is not equal to “-1”.

Read student ID from user.

If student ID is not equal to “-1”, then read course number from user.

If the student ID is contains in “students” list, then

Create array list named “class_List”.

Add the course number to “class_List” using “add” method.

Map the student ID to course number using “put” method.

Otherwise,

Create array list named “class_List”.

If the course number is not in the class list, then add the given course number to “class_List” using “add” method.

Display all the classes for each student using “for” loop.

Create array list named “stud_List”.

Display course number for corresponding student ID.

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(1 point) By dragging statements from the left column to the right column below, give a proof by induction of the following statement: an = = 9" - 1 is a solution to the recurrence relation an = 9an-18 with ao = : 0. The correct proof will use 8 of the statements below. Statements to choose from: Note that a₁ = 9a0 + 8. Now assume that P(n) is true for all n ≥ 0. Your Proof: Put chosen statements in order in this column and press the Submit Answers button. Let P(n) be the predicate, "a = 9″ – 1". απ = 90 − 1 = Note that Let P(n) be the predicate, "an 9" - 1 is a solution to the recurrence relation an = 9an-1 +8 with ao = 0." - Now assume that P(k + 1) is true. Thus P(k) is true for all k. Thus P(k+1) is true. Then ak+1 = 9ak +8, so P(k + 1) is true. = 1 − 1 = 0, as required. Then = 9k — 1. ak Now assume that P(k) is true for an arbitrary integer k ≥ 1. By the recurrence relation, we have ak+1 = ak+1 = = 9ak + 8 = 9(9k − 1) + 8 This simplifies to 9k+19+8 = 9k+1 − 1 Then 9k+1 − 1 = 9(9*…

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