Organic Chemistry: Principles and Mechanisms (Second Edition)
Organic Chemistry: Principles and Mechanisms (Second Edition)
2nd Edition
ISBN: 9780393663556
Author: Joel Karty
Publisher: W. W. Norton & Company
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 12, Problem 12.56P
Interpretation Introduction

(a)

Interpretation:

The mechanism that accounts for the formation of the mixture of the products in a given reaction is to be drawn.

Concept introduction:

Electrophilic addition of the molecular chlorine into but-2-ene gives anti-addition of the molecular chlorine via the formation of the chloronium ion as an intermediate. Under similar conditions, molecular chlorine undergoes both syn and anti-addition to (E)-1-phenylprop-1-ene that produces the isomer plus enantiomers. In order to show both syn and anti-addition, the carbocation like intermediate must be generated. Hence, this electrophilic addition proceeds via formation of stable benzylic carbocation intermediate instead of the formation of chloronium ion. As this reaction leads to formation of two different benzylic carbocation intermediates, the reaction yields four different products which consists of two pairs of enantiomers.

Interpretation Introduction

(b)

Interpretation:

The mechanism for the electrophilic addition of the molecular chlorine to the 1-phenylprop-1-ene is different from the one for but-2-ene is to be explained.

Concept introduction:

Electrophilic addition of the molecular chlorine into but-2-ene gives anti-addition of the molecular chlorine via the formation of the chloronium ion as an intermediate. Under similar conditions, molecular chlorine undergoes both syn and anti-addition to (E)-1-phenylprop-1-ene that produces the isomer plus enantiomers. In order to show both syn and anti-addition, the carbocation like intermediate must be generated. Hence, this electrophilic addition proceeds via formation of stable benzylic carbocation intermediate instead of the formation of chloronium ion. As this reaction leads to formation of two different benzylic carbocation intermediates, the reaction yields four different products which consists of two pairs of enantiomers.

Blurred answer
Students have asked these similar questions
(EXM 2, PRBLM 3) Here is this problem, can you explain it to me and show how its done. Thank you I need to see the work for like prbl solving.
can someone draw out the reaction mechanism for this reaction showing all bonds, intermediates and side products Comment on the general features of the 1H-NMR spectrum of isoamyl ester provided below
What would be the best choices for the missing reagents 1 and 3 in this synthesis? 1. PPh3 3 2. n-BuLi • Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. • Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Click and drag to start drawing a structure.

Chapter 12 Solutions

Organic Chemistry: Principles and Mechanisms (Second Edition)

Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
  • Text book image
    Organic Chemistry
    Chemistry
    ISBN:9781305580350
    Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
    Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
Alcohols, Ethers, and Epoxides: Crash Course Organic Chemistry #24; Author: Crash Course;https://www.youtube.com/watch?v=j04zMFwDeDU;License: Standard YouTube License, CC-BY