Solution Manual for Quantitative Chemical Analysis
Solution Manual for Quantitative Chemical Analysis
9th Edition
ISBN: 9781464175633
Author: Daniel Harris
Publisher: Palgrave Macmillan Higher Ed
Question
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Chapter 12, Problem 12.3P

(a)

Interpretation Introduction

Interpretation:

At 9.0pH , the conditional formation constant for Mg(EDTA)2- should be calculated.

Concept Information:

Conditional Formation Constant:

In the reaction of metal with ligand, the equilibrium constant is called as formation constant or the stability constant.

MYn4-MYn++Y4-

The formation constant for above complex reaction is,

Kf=[MYn-4][Mn+][Y4-]

Where,

Kf is formation constant

[M+] is concentration of metal ion

[Y4-] is concentration of ligand

[MYn4-] is concentration of the acid

Degree of dissociation:

The ratio of mole of reactant that underwent to dissociating to mole of initial reactant is known as degree of dissociation.

In EDTA the degree of dissociation is,

αY4-=[Y4-][H6Y2+]+[H5Y+]+[H4Y]+[H3Y-]+[H2Y2-]+[H3Y3-]+[Y4-]=[Y4-][EDTA]

If pH is fixed, the αY4- is constant and Kf will be Kf'

The formation constantKf'=αY4-Kf=[MYn-4][Mn+][EDTA]

Where,

Kf' is the conditional formation constant

(b)

Interpretation Introduction

Interpretation:

At 9.0pH , the concentration of Mg2+ ion should be calculated.

Concept Information:

Conditional Formation Constant:

In the reaction of metal with ligand, the equilibrium constant is called as formation constant or the stability constant.

MYn4-MYn++Y4-

The formation constant for above complex reaction is,

Kf=[MYn-4][Mn+][Y4-]

Where,

Kf is formation constant

[M+] is concentration of metal ion

[Y4-] is concentration of ligand

[MYn4-] is concentration of the acid

Degree of dissociation:

The ratio of mole of reactant that underwent to dissociating to mole of initial reactant is known as degree of dissociation.

In EDTA the degree of dissociation is,

αY4-=[Y4-][H6Y2+]+[H5Y+]+[H4Y]+[H3Y-]+[H2Y2-]+[H3Y3-]+[Y4-]=[Y4-][EDTA]

If pH is fixed, the αY4- is constant and Kf will be Kf'

The formation constantKf'=αY4-Kf=[MYn-4][Mn+][EDTA]

Where,

Kf' is the conditional formation constant

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6. Consider the following exothermic reaction below. 2Cu2+(aq) +41 (aq)2Cul(s) + 12(aq) a. If Cul is added, there will be a shift left/shift right/no shift (circle one). b. If Cu2+ is added, there will be a shift left/shift right/no shift (circle one). c. If a solution of AgNO3 is added, there will be a shift left/shift right/no shift (circle one). d. If the solvent hexane (C6H14) is added, there will be a shift left/shift right/no shift (circle one). Hint: one of the reaction species is more soluble in hexane than in water. e. If the reaction is cooled, there will be a shift left/shift right/no shift (circle one). f. Which of the changes above will change the equilibrium constant, K?
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