Chapter 12, Problem 12.36P

Interpretation Introduction

Interpretation:

The concentrations of ${\text{Cs}}^{\text{+}}$ in given unknown sample should be calculated.

Concept introduction:

Back titration:

Back titration is a one of the titration method, which is find amount of metal present in the sample by treating excess of $\text{EDTA}$ then the un reacted $\text{EDTA}$ in a solution is titrate with known second metal solution, From the result of this to determine the amount of metal in the original solution.

Mole:

The number of the solute that present in taken mass of sample is given by mole of the sample.

The molar mass of the sample contains $\text{6}\text{.023}\times {\text{10}}^{23}$ number of units, therefore $\text{6}\text{.023}\times {\text{10}}^{23}$ units is known as 1 mole.

Mole of the solute in solution is calculated by the product of concentration of the solution with volume of the solution.

$\text{Mole}\text{=}\text{Concentration}\text{(molarity)×}\text{Volume}\text{(liter)}$