Chapter 12, Problem 12.33P

Interpretation Introduction

Interpretation:

The required mass (milligram) of   ${\text{CaCO}}_{\text{3}}$ to react with  $\text{1}\text{.00}\text{mL}$ of this $\text{EDTA}$ solution should be determined.

Concept introduction:

Mole:

The number of the solute that present in taken mass of sample is given by mole of the sample.

The molar mass of the sample contains $\text{6}\text{.023}\times {\text{10}}^{23}$ number of units, therefore $\text{6}\text{.023}\times {\text{10}}^{23}$ units is known as 1 mole.

Mole of the solute in solution is calculated by the product of concentration of the solution with volume of the solution.

$\text{Mole}\text{=}\text{Concentration}\text{(molarity)×}\text{Volume}\text{(liter)}$