Concept explainers
(a)
Interpretation: The number of rings and number of pi bonds in A is to be determined. And one possible structure is to be drawn.
Concept introduction: Degree of unsaturation is used to determine the total number of rings and pi bonds present in compound by just looking at the molecular formula. It does not specify the total number of rings and total number of pi bonds individually.
Answer to Problem 12.35P
The number of pi bonds and number of rings in A is one. The possible structure is given in Figure 1.
Explanation of Solution
For compound A:
Before hydrogenation, the molecular formula is
The maximum number of
The maximum number of
The number of
Substitute the values of maximum number of
The degree of unsaturation is calculated by the formula,
Hence, the degree of unsaturation before hydrogenation is two.
After hydrogenation, the molecular formula is
The maximum number of
The maximum number of
The number
Substitute the values of maximum number of
The degree of unsaturation is calculated by the formula,
Hence, the degree of unsaturation after hydrogenation is one.
The number of pi bonds in A is calculated by the formula,
Substitute the values of degree of unsaturation before hydrogenation and degree of unsaturation after hydrogenation in the above formula.
Hence, the number of pi bonds is one.
Number of rings is calculated by the formula,
Substitute the values of degree of unsaturation and number of pi bonds in the above formula.
Hence, the number of rings is one.
The possible structure for A is,
Figure 1
The number of pi bonds and number of rings in A is one. The possible structure is given in Figure 1.
(b)
Interpretation: The number of rings and number of pi bonds in B is to be determined. And one possible structure is to be drawn.
Concept introduction: Degree of unsaturation is used to determine the total number of rings and pi bonds present in compound by just looking at the molecular formula. It does not specify the total number of rings and total number of pi bonds individually.
Answer to Problem 12.35P
The number of pi bonds and number of rings in B is one and two respectively. The possible structure is given in Figure 2.
Explanation of Solution
For compound B:
Before hydrogenation, the molecular formula is
The maximum number of
The maximum number of
The number of
Substitute the values of maximum number of
The degree of unsaturation is calculated by the formula,
Hence, the degree of unsaturation before hydrogenation is three.
After hydrogenation, the molecular formula is
The maximum number of
The maximum number of
The number
Substitute the values of maximum number of
The degree of unsaturation is calculated by the formula,
Hence, the degree of unsaturation after hydrogenation is two.
The number of pi bonds in A is calculated by the formula,
Substitute the values of degree of unsaturation before hydrogenation and degree of unsaturation after hydrogenation in the above formula.
Hence, the number of pi bonds is one.
Number of rings is calculated by the formula,
Substitute the values of degree of unsaturation and number of pi bonds in the above formula.
Hence, the number of rings is two.
The possible structure for B is,
Figure 2
The number of pi bonds and number of rings in B is one and two respectively. The possible structure is given in Figure 2.
(c)
Interpretation: The number of rings and number of pi bonds in B is to be determined. And one possible structure is to be drawn.
Concept introduction: Degree of unsaturation is used to determine the total number of rings and pi bonds present in compound by just looking at the molecular formula. It does not specify the total number of rings and total number of pi bonds individually.
Answer to Problem 12.35P
The number of pi bonds and number of rings in C is four and one respectively. The possible structure is given in Figure 3.
Explanation of Solution
For compound C:
Before hydrogenation, the molecular formula is
The maximum number of
The maximum number of
The number of
Substitute the values of maximum number of
The degree of unsaturation is calculated by the formula,
Hence, the degree of unsaturation before hydrogenation is five.
After hydrogenation, the molecular formula is
The maximum number of
The maximum number of
The number
Substitute the values of maximum number of
The degree of unsaturation is calculated by the formula,
Hence, the degree of unsaturation after hydrogenation is one.
The number of pi bonds in A is calculated by the formula,
Substitute the values of degree of unsaturation before hydrogenation and degree of unsaturation after hydrogenation in the above formula.
Hence, the number of pi bonds is four.
Number of rings is calculated by the formula,
Substitute the values of degree of unsaturation and number of pi bonds in the above formula.
Hence, the number of rings is one.
The possible structure for C is,
Figure 3
The number of pi bonds and number of rings in C is four and one respectively. The possible structure is given in Figure 3.
Want to see more full solutions like this?
Chapter 12 Solutions
Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card
- Identify A–J:arrow_forwardBromo cyclopentadiene reacts to form a Witting Reagent (A), but does not react with aldehydes or ketones to give an alkene. Draw A and explain why it does not react with a carbonyl. Br 1. PPh3 2. Base A R H No Rxarrow_forwardCompound A exhibits a peak in its 1H NMR spectrum at 7.6 ppm, indicating that it is aromatic. (a) How are the carbon atoms of the triple bonds hybridized? (b) In what type of orbitals are the π electrons of the triple bonds contained? (c) How many π electrons are delocalized around the ring in A?arrow_forward
- Q.2 charrow_forward10. Consider the hydrogenation reaction of compound X to Y: H₂, Pt X (C8H14) →Y (C8H16) 25°C One can conclude that X has: A) no rings and no double bonds. B) no rings and one double bond. C) one ring and one double bond. D) two rings and no double bonds. E) one triple bond.arrow_forwardRank the compounds in each group in order of increasing boiling point. a. CH3(CH2)4I, CH3(CH2)sI, CH3(CH)gI b. CH;CH,CH,NH2, (CH3);N, CH3CH2CH,CH3 c. (CHa),COC(CH3)3, CHa(CH2)30(CH)¿CH3, CH3(CH2);OH COH d. HO. Br е. OH f.arrow_forward
- Four isomers A-D with the formula C5H12O exhibit different reactivity patterns as indicated below. Isomer A reacts with PCC and CrO3 to provide identical products. Isomer B reacts with PCC and CrO3 to provide different products. Isomers C and D do not react with either PCC or CrO3. Isomers A, B, and C readily react with NaH but D does not show any reactivity with NaH. The 1H NMR splitting patterns for these isomers are as follows. Isomer A: δ 0.91 (d, 3H), 0.90 (d, 3H), 1.18 (d, 3H), 1.92 (dqq, 1H), 3.38 (dq, 1H), 3.58 (bs, 1H). Isomer B: δ 1.25 (s, 9H), 3.45 (s, 2H), 3.65 (bs, 1H). Isomer C: δ 0.90 (t, 3H), 1.44 (q, 2H), 1.24 (s, 6H), 3.65 (bs, 1H). Isomer D: δ 1.10 (t, 3H), 1.13 (d, 6H), 3.19 (septet, 1H), 3.50 (q, 2H). Based on all of this information, provide the structures of A-D. (Note: If there is a chiral center on any of these molecules, assume the stereochemistry as “R”. dqq=doublet of a quartet of a quartet, bs=broad singlet)arrow_forwardQl- Arrange the following carbonium ion as more stable. Why? Me Me „Me A C Q2- Choose the substituted group that makes the following reaction faster. Why? X- CH2 H X- ососн, OR COOCH} Y= NH2 OR NO2 Q3- Which of the following compounds give the highest yield when reacting with a carbonyl compound. Why? NH 2 NH2 NH2 Me Me Me OR OR NO 2 NO2 NO2arrow_forward9.arrow_forward