Explanation Given Information: The number of firms with 1 to 4 employees had 2734133 and with 5 to 9 employees had 1025497 . Formula used: Five steps to solve a problem. Step 1: Identify what information is provided. Step 2: Identify what needs to find. Step 3: Solution plan. Step 4: Perform the required operation. Step 5: Conclusion. Calculation: Consider the statement. To find the solution simply subtract the bigger number from the smaller number as shown below: 2734133 − 1025497 = 1708636 The number of more 1 to 4 employees are 1708636

11th Edition

ISBN: 9780134496436

Author: Cheryl Cleaves, Margie Hobbs, Jeffrey Noble

Publisher: PEARSON

See similar textbooks

Concept explainers

Inverse Normal Distribution

The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of tw…

Mean, Median, Mode

It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency o…

Z-Scores

A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow compar…

Videos

Question

Chapter 1.2, Problem 1-12SC

To determine

To calculate: The number of more firms had 1 to 4 employees if the number of firms with the 1 to 4 employees was 2734133 and the number of firms with the 5 to 9 employees was 1025497.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 1.2, Problem 1-11SC

Chapter 1.2, Problem 2-1SC

Students have asked these similar questions

Solve the following systems using Gauss Seidal and Jacobi iteration methods for n=8 and initial values Xº=(000). - 3x1 + 2x2 x3 = 4 - 2x1 x2+2x3 = 10 x13x24x3 = 4

A gardener has ten different potted plants, and they are spraying the plants with doses offertilizers. Plants can receive zero or more doses in a session. In the following, we count eachpossible number of doses the ten plants can receive (the order of spraying in a session doesnot matter). How many ways are there to do two sessions of spraying, where each plant receives atmost two doses total?

Q/Consider the set 8 e' = { x = (x\ 1 X 2 1 X3, ...) € (°: { \x;k< ∞ } Show that M & XII, Ixil = にし i= 1 defines a norm on

Chapter 1 Solutions

Business Math (11th Edition)

Ch. 1.1 - Prob. 1-1SC Ch. 1.1 - Prob. 1-2SC Ch. 1.1 - Prob. 1-3SC Ch. 1.1 - Prob. 1-4SC Ch. 1.1 - Prob. 2-1SC Ch. 1.1 - Prob. 2-2SC Ch. 1.1 - Prob. 2-3SC Ch. 1.1 - Prob. 2-4SC Ch. 1.1 - Prob. 3-1SC Ch. 1.1 - Prob. 3-2SC

Ch. 1.1 - Prob. 3-3SC Ch. 1.1 - Prob. 3-4SC Ch. 1.1 - Prob. 3-5SC Ch. 1.1 - Prob. 3-6SC Ch. 1.1 - Prob. 4-1SC Ch. 1.1 - Prob. 4-2SC Ch. 1.1 - Prob. 4-3SC Ch. 1.1 - Prob. 4-4SC Ch. 1.1 - Prob. 1SE Ch. 1.1 - Prob. 2SE Ch. 1.1 - Prob. 3SE Ch. 1.1 - Prob. 4SE Ch. 1.1 - Prob. 5SE Ch. 1.1 - Prob. 6SE Ch. 1.1 - Prob. 7SE Ch. 1.1 - Prob. 8SE Ch. 1.1 - Prob. 9SE Ch. 1.1 - Prob. 10SE Ch. 1.1 - Prob. 11SE Ch. 1.1 - Prob. 12SE Ch. 1.1 - Prob. 13SE Ch. 1.1 - Prob. 14SE Ch. 1.1 - Prob. 15SE Ch. 1.1 - Prob. 16SE Ch. 1.1 - Prob. 17SE Ch. 1.1 - Prob. 18SE Ch. 1.1 - Prob. 19SE Ch. 1.1 - Prob. 20SE Ch. 1.1 - Prob. 21SE Ch. 1.1 - Prob. 22SE Ch. 1.1 - Prob. 23SE Ch. 1.1 - Prob. 24SE Ch. 1.1 - Prob. 25SE Ch. 1.1 - Prob. 26SE Ch. 1.2 - Prob. 1-1SC Ch. 1.2 - Prob. 1-2SC Ch. 1.2 - Prob. 1-3SC Ch. 1.2 - Prob. 1-4SC Ch. 1.2 - Prob. 1-5SC Ch. 1.2 - Prob. 1-6SC Ch. 1.2 - Prob. 1-7SC Ch. 1.2 - Prob. 1-8SC Ch. 1.2 - Prob. 1-9SC Ch. 1.2 - Prob. 1-10SC Ch. 1.2 - Prob. 1-11SC Ch. 1.2 - Prob. 1-12SC Ch. 1.2 - Prob. 2-1SC Ch. 1.2 - Prob. 2-2SC Ch. 1.2 - Prob. 2-3SC Ch. 1.2 - Prob. 2-4SC Ch. 1.2 - Prob. 2-5SC Ch. 1.2 - Prob. 2-6SC Ch. 1.2 - Prob. 3-1SC Ch. 1.2 - Prob. 3-2SC Ch. 1.2 - Prob. 3-3SC Ch. 1.2 - Prob. 3-4SC Ch. 1.2 - Prob. 3-5SC Ch. 1.2 - Prob. 3-6SC Ch. 1.2 - Prob. 3-7SC Ch. 1.2 - Prob. 3-8SC Ch. 1.2 - Prob. 3-9SC Ch. 1.2 - Prob. 3-10SC Ch. 1.2 - Prob. 4-1SC Ch. 1.2 - Prob. 4-2SC Ch. 1.2 - Prob. 4-3SC Ch. 1.2 - Prob. 4-4SC Ch. 1.2 - Prob. 4-5SC Ch. 1.2 - Prob. 4-6SC Ch. 1.2 - Prob. 4-7SC Ch. 1.2 - Prob. 4-8SC Ch. 1.2 - Prob. 4-9SC Ch. 1.2 - Prob. 4-10SC Ch. 1.2 - Prob. 5-1SC Ch. 1.2 - Prob. 5-2SC Ch. 1.2 - Prob. 5-3SC Ch. 1.2 - Prob. 5-4SC Ch. 1.2 - Prob. 1SE Ch. 1.2 - Prob. 2SE Ch. 1.2 - Prob. 3SE Ch. 1.2 - Prob. 4SE Ch. 1.2 - Prob. 5SE Ch. 1.2 - Prob. 6SE Ch. 1.2 - Prob. 7SE Ch. 1.2 - Prob. 8SE Ch. 1.2 - Prob. 9SE Ch. 1.2 - Prob. 10SE Ch. 1.2 - Prob. 11SE Ch. 1.2 - Prob. 12SE Ch. 1.2 - Prob. 13SE Ch. 1.2 - Prob. 14SE Ch. 1.2 - Prob. 15SE Ch. 1.2 - Prob. 16SE Ch. 1.2 - Prob. 17SE Ch. 1.2 - Prob. 18SE Ch. 1.2 - Prob. 19SE Ch. 1.2 - Prob. 20SE Ch. 1.2 - Prob. 21SE Ch. 1.2 - Prob. 22SE Ch. 1.2 - Prob. 23SE Ch. 1.2 - Prob. 24SE Ch. 1.2 - Prob. 25SE Ch. 1.2 - Prob. 26SE Ch. 1.2 - Prob. 27SE Ch. 1.2 - Prob. 28SE Ch. 1.2 - Prob. 29SE Ch. 1.2 - Prob. 30SE Ch. 1.2 - Prob. 31SE Ch. 1.2 - Prob. 32SE Ch. 1.2 - Prob. 33SE Ch. 1.2 - Prob. 34SE Ch. 1.2 - Prob. 35SE Ch. 1.2 - Prob. 36SE Ch. 1.2 - Prob. 37SE Ch. 1.2 - Prob. 38SE Ch. 1.2 - Prob. 39SE Ch. 1.2 - Prob. 40SE Ch. 1.2 - Prob. 41SE Ch. 1.2 - Prob. 42SE Ch. 1.2 - Prob. 43SE Ch. 1.2 - Prob. 44SE Ch. 1.2 - Prob. 45SE Ch. 1.2 - Prob. 46SE Ch. 1.2 - Prob. 47SE Ch. 1.2 - Prob. 48SE Ch. 1.2 - Prob. 49SE Ch. 1.2 - Prob. 50SE Ch. 1.2 - Prob. 51SE Ch. 1.2 - Prob. 52SE Ch. 1.2 - Prob. 53SE Ch. 1.2 - Prob. 54SE Ch. 1.2 - Prob. 55SE Ch. 1.2 - Prob. 56SE Ch. 1 - Prob. 1ES Ch. 1 - Prob. 2ES Ch. 1 - Prob. 3ES Ch. 1 - Prob. 4ES Ch. 1 - Prob. 5ES Ch. 1 - Prob. 6ES Ch. 1 - Prob. 7ES Ch. 1 - Prob. 8ES Ch. 1 - Prob. 9ES Ch. 1 - Prob. 10ES Ch. 1 - Prob. 11ES Ch. 1 - Prob. 12ES Ch. 1 - Prob. 13ES Ch. 1 - Prob. 14ES Ch. 1 - Prob. 15ES Ch. 1 - Prob. 16ES Ch. 1 - Prob. 17ES Ch. 1 - Prob. 18ES Ch. 1 - Prob. 19ES Ch. 1 - Prob. 20ES Ch. 1 - Prob. 21ES Ch. 1 - Prob. 22ES Ch. 1 - Prob. 23ES Ch. 1 - Prob. 24ES Ch. 1 - Prob. 25ES Ch. 1 - Prob. 26ES Ch. 1 - Prob. 27ES Ch. 1 - Prob. 28ES Ch. 1 - Prob. 29ES Ch. 1 - Prob. 30ES Ch. 1 - Prob. 31ES Ch. 1 - Prob. 32ES Ch. 1 - Prob. 33ES Ch. 1 - Prob. 34ES Ch. 1 - Prob. 35ES Ch. 1 - Prob. 36ES Ch. 1 - Prob. 37ES Ch. 1 - Prob. 38ES Ch. 1 - Prob. 39ES Ch. 1 - Prob. 40ES Ch. 1 - Prob. 41ES Ch. 1 - Prob. 42ES Ch. 1 - Prob. 43ES Ch. 1 - Prob. 44ES Ch. 1 - Prob. 45ES Ch. 1 - Prob. 46ES Ch. 1 - Prob. 47ES Ch. 1 - Prob. 48ES Ch. 1 - Prob. 49ES Ch. 1 - Prob. 50ES Ch. 1 - Prob. 51ES Ch. 1 - Prob. 52ES Ch. 1 - Prob. 53ES Ch. 1 - Prob. 54ES Ch. 1 - Prob. 55ES Ch. 1 - Prob. 56ES Ch. 1 - Prob. 57ES Ch. 1 - Prob. 58ES Ch. 1 - Prob. 59ES Ch. 1 - Prob. 60ES Ch. 1 - Prob. 61ES Ch. 1 - Prob. 62ES Ch. 1 - Prob. 63ES Ch. 1 - Prob. 64ES Ch. 1 - Prob. 65ES Ch. 1 - Prob. 66ES Ch. 1 - Prob. 67ES Ch. 1 - Prob. 68ES Ch. 1 - Prob. 69ES Ch. 1 - Prob. 70ES Ch. 1 - Prob. 71ES Ch. 1 - Prob. 72ES Ch. 1 - Prob. 73ES Ch. 1 - Prob. 74ES Ch. 1 - Prob. 75ES Ch. 1 - Prob. 76ES Ch. 1 - Prob. 77ES Ch. 1 - Prob. 78ES Ch. 1 - Prob. 79ES Ch. 1 - Prob. 80ES Ch. 1 - Prob. 81ES Ch. 1 - Prob. 82ES Ch. 1 - Prob. 83ES Ch. 1 - Prob. 84ES Ch. 1 - Prob. 85ES Ch. 1 - Prob. 86ES Ch. 1 - Prob. 87ES Ch. 1 - Prob. 88ES Ch. 1 - Prob. 89ES Ch. 1 - Prob. 1PT Ch. 1 - Prob. 2PT Ch. 1 - Prob. 3PT Ch. 1 - Prob. 4PT Ch. 1 - Prob. 5PT Ch. 1 - Prob. 6PT Ch. 1 - Prob. 7PT Ch. 1 - Prob. 8PT Ch. 1 - Prob. 9PT Ch. 1 - Prob. 10PT Ch. 1 - Prob. 11PT Ch. 1 - Prob. 12PT Ch. 1 - Prob. 13PT Ch. 1 - Prob. 14PT Ch. 1 - Prob. 15PT Ch. 1 - Prob. 16PT Ch. 1 - Prob. 17PT Ch. 1 - Prob. 18PT Ch. 1 - Prob. 19PT Ch. 1 - Prob. 20PT Ch. 1 - Prob. 21PT Ch. 1 - Prob. 22PT Ch. 1 - Prob. 23PT Ch. 1 - Prob. 24PT Ch. 1 - Prob. 25PT Ch. 1 - Prob. 26PT Ch. 1 - Prob. 27PT Ch. 1 - Prob. 28PT Ch. 1 - Prob. 29PT Ch. 1 - Prob. 30PT Ch. 1 - Prob. 31PT Ch. 1 - Prob. 32PT Ch. 1 - Prob. 1CT Ch. 1 - Prob. 2CT Ch. 1 - Prob. 3CT Ch. 1 - Prob. 4CT Ch. 1 - Prob. 5CT Ch. 1 - Prob. 6CT Ch. 1 - Prob. 7CT Ch. 1 - Prob. 8CT Ch. 1 - Prob. 9CT Ch. 1 - Prob. 10CT Ch. 1 - Prob. 11CT Ch. 1 - Prob. 12CT Ch. 1 - Prob. 1CP Ch. 1 - Prob. 2CP Ch. 1 - Prob. 1CS1 Ch. 1 - Prob. 2CS1 Ch. 1 - Prob. 3CS1 Ch. 1 - Prob. 1CS2 Ch. 1 - Prob. 2CS2 Ch. 1 - Prob. 3CS2 Ch. 1 - Prob. 1CS3 Ch. 1 - Prob. 2CS3 Ch. 1 - Prob. 3CS3 Ch. 1 - Prob. 4CS3 Ch. 1 - Prob. 5CS3

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.

The number of more firms had 1 to 4 employees if the number of firms with the 1 to 4 employees was 2734133 and the number of firms with the 5 to 9 employees was 1025497 .

Solution Summary: The author calculates that the number of firms with 1 to 4 employees is 1708636. The formula uses five steps to solve a problem.

Concept explainers

Videos

To calculate: The number of more firms had 1 to 4 employees if the number of firms with the 1 to 4 employees was 2734133 and the number of firms with the 5 to 9 employees was 1025497.

Want to see the full answer?

Chapter 1 Solutions