Explanation Given Information: The provided number is, 587 , 213 Formula used: The procedure used to round a whole number to a specified period is: 1: Identify the digit in the specified period. 2: Find the next digit to the right of the specified period. If this next digit is smaller than 5 , replace the digit and all the digits with zeros to the right. If this next digit is 5 or greater, then the digit in the specified period is added with 1 and all the digits to the right are replaced with zeros. Calculation: Consider the provided number. 587 , 213 The problem requires the provided number to be rounded to the first digit which is the hundred-thousand place

11th Edition

ISBN: 9780134496436

Author: Cheryl Cleaves, Margie Hobbs, Jeffrey Noble

Publisher: PEARSON

See similar textbooks

Concept explainers

Addition Rule of Probability

It simply refers to the likelihood of an event taking place whenever the occurrence of an event is uncertain. The probability of a single event can be calculated by dividing the number of successful trials of that event by the total number of trials.

Expected Value

When a large number of trials are performed for any random variable ‘X’, the predicted result is most likely the mean of all the outcomes for the random variable and it is known as expected value also known as expectation. The expected value, also known …

Probability Distributions

Understanding probability is necessary to know the probability distributions. In statistics, probability is how the uncertainty of an event is measured. This event can be anything. The most common examples include tossing a coin, rolling a die, or choosi…

Basic Probability

The simple definition of probability it is a chance of the occurrence of an event. It is defined in numerical form and the probability value is between 0 to 1. The probability value 0 indicates that there is no chance of that event occurring and the prob…

Videos

Question

Chapter 1, Problem 4PT

To determine

To calculate: The round to the first digit of the number 587,213.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 1, Problem 3PT

Chapter 1, Problem 5PT

Students have asked these similar questions

Blue Ridge Hot Tubs manufactures and sells two models of hot tubs: the Aqua-Spa and the Hydro-Lux. Howie Jones, the owner and manager of the company, needs to decide how many of each type of hot tub to produce during his next production cycle. Howie buys prefabricated fiberglass hot tub shells from a local supplier and adds the pump and tubing to the shells to create his hot tubs. (This supplier has the capacity to deliver as many hot tub shells as Howie needs.) Howie installs the same type of pump into both hot tubs. He will have only 200 pumps available during his next production cycle. From a manufacturing standpoint, the main difference between the two models of hot tubs is the amount of tubing and labor required. Each Aqua-Spa requires 9 hours of labor and 12 feet of tubing. Each Hydro-Lux requires 6 hours of labor and 16 feet of tubing. Howie expects to have 1,566 production labor hours and 2,880 feet of tubing available during the next production cycle. Howie earns a profit of…

7. From a point 20 m away on a level ground, the angle of elevation to the bottom of a the top of the window is 32°. Calculate the window is 27° and the angle of elevatim height of the window. (3 marks) 32 SOUCAHTOA Rom Coso-Adj opponite 1270 H X Hyp Tant=OPP Adj 20 # Zom Adjacent CoS2E 20 XHX Tanz 20 20 K -0.0445503261 -1.764201788 0-044550326 60044550320 (1 mark) 3960 8. All odd numbers from 1 to 10 are arranged in descending order to form a number. (i) Write the number. 35798. 97531 31 (ii) Write the total value of the second digit of the number formed in (a) (i) FA 7X1000-7000 이 (1 mark) 9. A cylinder has a diameter of 28 cm and the height is 18 cm. Calculate its volume. 2 22 × 14 × 14 × 18 -110880m 3 (3 marks) 10. The figure below shows a right pyramid with AB = 3 cm, BC = 5 cm, and AV VC = VD = 4 cm. Draw its net. V 3+ 12 7/18 (2/20 2105 SSS 20

No chatgpt pls will upvote

Chapter 1 Solutions

Business Math (11th Edition)

Ch. 1.1 - Prob. 1-1SC Ch. 1.1 - Prob. 1-2SC Ch. 1.1 - Prob. 1-3SC Ch. 1.1 - Prob. 1-4SC Ch. 1.1 - Prob. 2-1SC Ch. 1.1 - Prob. 2-2SC Ch. 1.1 - Prob. 2-3SC Ch. 1.1 - Prob. 2-4SC Ch. 1.1 - Prob. 3-1SC Ch. 1.1 - Prob. 3-2SC

Ch. 1.1 - Prob. 3-3SC Ch. 1.1 - Prob. 3-4SC Ch. 1.1 - Prob. 3-5SC Ch. 1.1 - Prob. 3-6SC Ch. 1.1 - Prob. 4-1SC Ch. 1.1 - Prob. 4-2SC Ch. 1.1 - Prob. 4-3SC Ch. 1.1 - Prob. 4-4SC Ch. 1.1 - Prob. 1SE Ch. 1.1 - Prob. 2SE Ch. 1.1 - Prob. 3SE Ch. 1.1 - Prob. 4SE Ch. 1.1 - Prob. 5SE Ch. 1.1 - Prob. 6SE Ch. 1.1 - Prob. 7SE Ch. 1.1 - Prob. 8SE Ch. 1.1 - Prob. 9SE Ch. 1.1 - Prob. 10SE Ch. 1.1 - Prob. 11SE Ch. 1.1 - Prob. 12SE Ch. 1.1 - Prob. 13SE Ch. 1.1 - Prob. 14SE Ch. 1.1 - Prob. 15SE Ch. 1.1 - Prob. 16SE Ch. 1.1 - Prob. 17SE Ch. 1.1 - Prob. 18SE Ch. 1.1 - Prob. 19SE Ch. 1.1 - Prob. 20SE Ch. 1.1 - Prob. 21SE Ch. 1.1 - Prob. 22SE Ch. 1.1 - Prob. 23SE Ch. 1.1 - Prob. 24SE Ch. 1.1 - Prob. 25SE Ch. 1.1 - Prob. 26SE Ch. 1.2 - Prob. 1-1SC Ch. 1.2 - Prob. 1-2SC Ch. 1.2 - Prob. 1-3SC Ch. 1.2 - Prob. 1-4SC Ch. 1.2 - Prob. 1-5SC Ch. 1.2 - Prob. 1-6SC Ch. 1.2 - Prob. 1-7SC Ch. 1.2 - Prob. 1-8SC Ch. 1.2 - Prob. 1-9SC Ch. 1.2 - Prob. 1-10SC Ch. 1.2 - Prob. 1-11SC Ch. 1.2 - Prob. 1-12SC Ch. 1.2 - Prob. 2-1SC Ch. 1.2 - Prob. 2-2SC Ch. 1.2 - Prob. 2-3SC Ch. 1.2 - Prob. 2-4SC Ch. 1.2 - Prob. 2-5SC Ch. 1.2 - Prob. 2-6SC Ch. 1.2 - Prob. 3-1SC Ch. 1.2 - Prob. 3-2SC Ch. 1.2 - Prob. 3-3SC Ch. 1.2 - Prob. 3-4SC Ch. 1.2 - Prob. 3-5SC Ch. 1.2 - Prob. 3-6SC Ch. 1.2 - Prob. 3-7SC Ch. 1.2 - Prob. 3-8SC Ch. 1.2 - Prob. 3-9SC Ch. 1.2 - Prob. 3-10SC Ch. 1.2 - Prob. 4-1SC Ch. 1.2 - Prob. 4-2SC Ch. 1.2 - Prob. 4-3SC Ch. 1.2 - Prob. 4-4SC Ch. 1.2 - Prob. 4-5SC Ch. 1.2 - Prob. 4-6SC Ch. 1.2 - Prob. 4-7SC Ch. 1.2 - Prob. 4-8SC Ch. 1.2 - Prob. 4-9SC Ch. 1.2 - Prob. 4-10SC Ch. 1.2 - Prob. 5-1SC Ch. 1.2 - Prob. 5-2SC Ch. 1.2 - Prob. 5-3SC Ch. 1.2 - Prob. 5-4SC Ch. 1.2 - Prob. 1SE Ch. 1.2 - Prob. 2SE Ch. 1.2 - Prob. 3SE Ch. 1.2 - Prob. 4SE Ch. 1.2 - Prob. 5SE Ch. 1.2 - Prob. 6SE Ch. 1.2 - Prob. 7SE Ch. 1.2 - Prob. 8SE Ch. 1.2 - Prob. 9SE Ch. 1.2 - Prob. 10SE Ch. 1.2 - Prob. 11SE Ch. 1.2 - Prob. 12SE Ch. 1.2 - Prob. 13SE Ch. 1.2 - Prob. 14SE Ch. 1.2 - Prob. 15SE Ch. 1.2 - Prob. 16SE Ch. 1.2 - Prob. 17SE Ch. 1.2 - Prob. 18SE Ch. 1.2 - Prob. 19SE Ch. 1.2 - Prob. 20SE Ch. 1.2 - Prob. 21SE Ch. 1.2 - Prob. 22SE Ch. 1.2 - Prob. 23SE Ch. 1.2 - Prob. 24SE Ch. 1.2 - Prob. 25SE Ch. 1.2 - Prob. 26SE Ch. 1.2 - Prob. 27SE Ch. 1.2 - Prob. 28SE Ch. 1.2 - Prob. 29SE Ch. 1.2 - Prob. 30SE Ch. 1.2 - Prob. 31SE Ch. 1.2 - Prob. 32SE Ch. 1.2 - Prob. 33SE Ch. 1.2 - Prob. 34SE Ch. 1.2 - Prob. 35SE Ch. 1.2 - Prob. 36SE Ch. 1.2 - Prob. 37SE Ch. 1.2 - Prob. 38SE Ch. 1.2 - Prob. 39SE Ch. 1.2 - Prob. 40SE Ch. 1.2 - Prob. 41SE Ch. 1.2 - Prob. 42SE Ch. 1.2 - Prob. 43SE Ch. 1.2 - Prob. 44SE Ch. 1.2 - Prob. 45SE Ch. 1.2 - Prob. 46SE Ch. 1.2 - Prob. 47SE Ch. 1.2 - Prob. 48SE Ch. 1.2 - Prob. 49SE Ch. 1.2 - Prob. 50SE Ch. 1.2 - Prob. 51SE Ch. 1.2 - Prob. 52SE Ch. 1.2 - Prob. 53SE Ch. 1.2 - Prob. 54SE Ch. 1.2 - Prob. 55SE Ch. 1.2 - Prob. 56SE Ch. 1 - Prob. 1ES Ch. 1 - Prob. 2ES Ch. 1 - Prob. 3ES Ch. 1 - Prob. 4ES Ch. 1 - Prob. 5ES Ch. 1 - Prob. 6ES Ch. 1 - Prob. 7ES Ch. 1 - Prob. 8ES Ch. 1 - Prob. 9ES Ch. 1 - Prob. 10ES Ch. 1 - Prob. 11ES Ch. 1 - Prob. 12ES Ch. 1 - Prob. 13ES Ch. 1 - Prob. 14ES Ch. 1 - Prob. 15ES Ch. 1 - Prob. 16ES Ch. 1 - Prob. 17ES Ch. 1 - Prob. 18ES Ch. 1 - Prob. 19ES Ch. 1 - Prob. 20ES Ch. 1 - Prob. 21ES Ch. 1 - Prob. 22ES Ch. 1 - Prob. 23ES Ch. 1 - Prob. 24ES Ch. 1 - Prob. 25ES Ch. 1 - Prob. 26ES Ch. 1 - Prob. 27ES Ch. 1 - Prob. 28ES Ch. 1 - Prob. 29ES Ch. 1 - Prob. 30ES Ch. 1 - Prob. 31ES Ch. 1 - Prob. 32ES Ch. 1 - Prob. 33ES Ch. 1 - Prob. 34ES Ch. 1 - Prob. 35ES Ch. 1 - Prob. 36ES Ch. 1 - Prob. 37ES Ch. 1 - Prob. 38ES Ch. 1 - Prob. 39ES Ch. 1 - Prob. 40ES Ch. 1 - Prob. 41ES Ch. 1 - Prob. 42ES Ch. 1 - Prob. 43ES Ch. 1 - Prob. 44ES Ch. 1 - Prob. 45ES Ch. 1 - Prob. 46ES Ch. 1 - Prob. 47ES Ch. 1 - Prob. 48ES Ch. 1 - Prob. 49ES Ch. 1 - Prob. 50ES Ch. 1 - Prob. 51ES Ch. 1 - Prob. 52ES Ch. 1 - Prob. 53ES Ch. 1 - Prob. 54ES Ch. 1 - Prob. 55ES Ch. 1 - Prob. 56ES Ch. 1 - Prob. 57ES Ch. 1 - Prob. 58ES Ch. 1 - Prob. 59ES Ch. 1 - Prob. 60ES Ch. 1 - Prob. 61ES Ch. 1 - Prob. 62ES Ch. 1 - Prob. 63ES Ch. 1 - Prob. 64ES Ch. 1 - Prob. 65ES Ch. 1 - Prob. 66ES Ch. 1 - Prob. 67ES Ch. 1 - Prob. 68ES Ch. 1 - Prob. 69ES Ch. 1 - Prob. 70ES Ch. 1 - Prob. 71ES Ch. 1 - Prob. 72ES Ch. 1 - Prob. 73ES Ch. 1 - Prob. 74ES Ch. 1 - Prob. 75ES Ch. 1 - Prob. 76ES Ch. 1 - Prob. 77ES Ch. 1 - Prob. 78ES Ch. 1 - Prob. 79ES Ch. 1 - Prob. 80ES Ch. 1 - Prob. 81ES Ch. 1 - Prob. 82ES Ch. 1 - Prob. 83ES Ch. 1 - Prob. 84ES Ch. 1 - Prob. 85ES Ch. 1 - Prob. 86ES Ch. 1 - Prob. 87ES Ch. 1 - Prob. 88ES Ch. 1 - Prob. 89ES Ch. 1 - Prob. 1PT Ch. 1 - Prob. 2PT Ch. 1 - Prob. 3PT Ch. 1 - Prob. 4PT Ch. 1 - Prob. 5PT Ch. 1 - Prob. 6PT Ch. 1 - Prob. 7PT Ch. 1 - Prob. 8PT Ch. 1 - Prob. 9PT Ch. 1 - Prob. 10PT Ch. 1 - Prob. 11PT Ch. 1 - Prob. 12PT Ch. 1 - Prob. 13PT Ch. 1 - Prob. 14PT Ch. 1 - Prob. 15PT Ch. 1 - Prob. 16PT Ch. 1 - Prob. 17PT Ch. 1 - Prob. 18PT Ch. 1 - Prob. 19PT Ch. 1 - Prob. 20PT Ch. 1 - Prob. 21PT Ch. 1 - Prob. 22PT Ch. 1 - Prob. 23PT Ch. 1 - Prob. 24PT Ch. 1 - Prob. 25PT Ch. 1 - Prob. 26PT Ch. 1 - Prob. 27PT Ch. 1 - Prob. 28PT Ch. 1 - Prob. 29PT Ch. 1 - Prob. 30PT Ch. 1 - Prob. 31PT Ch. 1 - Prob. 32PT Ch. 1 - Prob. 1CT Ch. 1 - Prob. 2CT Ch. 1 - Prob. 3CT Ch. 1 - Prob. 4CT Ch. 1 - Prob. 5CT Ch. 1 - Prob. 6CT Ch. 1 - Prob. 7CT Ch. 1 - Prob. 8CT Ch. 1 - Prob. 9CT Ch. 1 - Prob. 10CT Ch. 1 - Prob. 11CT Ch. 1 - Prob. 12CT Ch. 1 - Prob. 1CP Ch. 1 - Prob. 2CP Ch. 1 - Prob. 1CS1 Ch. 1 - Prob. 2CS1 Ch. 1 - Prob. 3CS1 Ch. 1 - Prob. 1CS2 Ch. 1 - Prob. 2CS2 Ch. 1 - Prob. 3CS2 Ch. 1 - Prob. 1CS3 Ch. 1 - Prob. 2CS3 Ch. 1 - Prob. 3CS3 Ch. 1 - Prob. 4CS3 Ch. 1 - Prob. 5CS3

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.

The round to the first digit of the number 587 , 213 .

Solution Summary: The author explains how the number 587,213 rounded to the first digit is 600,000.

Concept explainers

Videos

To calculate: The round to the first digit of the number 587,213.

Want to see the full answer?

Chapter 1 Solutions