Business Math (11th Edition)
11th Edition
ISBN: 9780134496436
Author: Cheryl Cleaves, Margie Hobbs, Jeffrey Noble
Publisher: PEARSON
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Chapter 1, Problem 15PT
To determine
To calculate: The estimated product rounding each number to the first digit and then find the exact product of
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1 No.
2
3
4
Binomial Prob.
X
n
P
Answer
5
6 4
7
8
9
10
12345678
8
3
4
2
2552
10
0.7
0.233
0.3
0.132
7
0.6
0.290
20
0.02
0.053
150
1000
0.15
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0.383
11
9
3
5
0.3
0.132
12
10
4
7
0.6
0.290
13
Poisson Probability
14
X
lambda
Answer
18 4
19
20
21
22
23 9
15
16
17 3
1234567829
3
2
0.180
2
1.5
0.251
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10
0.095
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step by step on Microssoft on how to put this in excel and the answers please
Find binomial probability if:
x = 8, n = 10, p = 0.7
x= 3, n=5, p = 0.3
x = 4, n=7, p = 0.6
Quality Control: A factory produces light bulbs with a 2% defect rate. If a random sample of 20 bulbs is tested, what is the probability that exactly 2 bulbs are defective? (hint: p=2% or 0.02; x =2, n=20; use the same logic for the following problems)
Marketing Campaign: A marketing company sends out 1,000 promotional emails. The probability of any email being opened is 0.15. What is the probability that exactly 150 emails will be opened? (hint: total emails or n=1000, x =150)
Customer Satisfaction: A survey shows that 70% of customers are satisfied with a new product. Out of 10 randomly selected customers, what is the probability that at least 8 are satisfied? (hint: One of the keyword in this question is “at least 8”, it is not “exactly 8”, the correct formula for this should be = 1- (binom.dist(7, 10, 0.7,…
Quality Control: A factory produces light bulbs with a 2% defect rate. If a random sample of 20 bulbs is tested, what is the probability that exactly 2 bulbs are defective? (hint: p=2% or 0.02; x =2, n=20; use the same logic for the following problems)
Marketing Campaign: A marketing company sends out 1,000 promotional emails. The probability of any email being opened is 0.15. What is the probability that exactly 150 emails will be opened? (hint: total emails or n=1000, x =150)
Customer Satisfaction: A survey shows that 70% of customers are satisfied with a new product. Out of 10 randomly selected customers, what is the probability that at least 8 are satisfied? (hint: One of the keyword in this question is “at least 8”, it is not “exactly 8”, the correct formula for this should be = 1- (binom.dist(7, 10, 0.7, TRUE)). The part in the princess will give you the probability of seven and less than seven. When you subtract it from 1, that will give you the probability of at least eight,…
Chapter 1 Solutions
Business Math (11th Edition)
Ch. 1.1 - Prob. 1-1SCCh. 1.1 - Prob. 1-2SCCh. 1.1 - Prob. 1-3SCCh. 1.1 - Prob. 1-4SCCh. 1.1 - Prob. 2-1SCCh. 1.1 - Prob. 2-2SCCh. 1.1 - Prob. 2-3SCCh. 1.1 - Prob. 2-4SCCh. 1.1 - Prob. 3-1SCCh. 1.1 - Prob. 3-2SC
Ch. 1.1 - Prob. 3-3SCCh. 1.1 - Prob. 3-4SCCh. 1.1 - Prob. 3-5SCCh. 1.1 - Prob. 3-6SCCh. 1.1 - Prob. 4-1SCCh. 1.1 - Prob. 4-2SCCh. 1.1 - Prob. 4-3SCCh. 1.1 - Prob. 4-4SCCh. 1.1 - Prob. 1SECh. 1.1 - Prob. 2SECh. 1.1 - Prob. 3SECh. 1.1 - Prob. 4SECh. 1.1 - Prob. 5SECh. 1.1 - Prob. 6SECh. 1.1 - Prob. 7SECh. 1.1 - Prob. 8SECh. 1.1 - Prob. 9SECh. 1.1 - Prob. 10SECh. 1.1 - Prob. 11SECh. 1.1 - Prob. 12SECh. 1.1 - Prob. 13SECh. 1.1 - Prob. 14SECh. 1.1 - Prob. 15SECh. 1.1 - Prob. 16SECh. 1.1 - Prob. 17SECh. 1.1 - Prob. 18SECh. 1.1 - Prob. 19SECh. 1.1 - Prob. 20SECh. 1.1 - Prob. 21SECh. 1.1 - Prob. 22SECh. 1.1 - Prob. 23SECh. 1.1 - Prob. 24SECh. 1.1 - Prob. 25SECh. 1.1 - Prob. 26SECh. 1.2 - Prob. 1-1SCCh. 1.2 - Prob. 1-2SCCh. 1.2 - Prob. 1-3SCCh. 1.2 - Prob. 1-4SCCh. 1.2 - Prob. 1-5SCCh. 1.2 - Prob. 1-6SCCh. 1.2 - Prob. 1-7SCCh. 1.2 - Prob. 1-8SCCh. 1.2 - Prob. 1-9SCCh. 1.2 - Prob. 1-10SCCh. 1.2 - Prob. 1-11SCCh. 1.2 - Prob. 1-12SCCh. 1.2 - Prob. 2-1SCCh. 1.2 - Prob. 2-2SCCh. 1.2 - Prob. 2-3SCCh. 1.2 - Prob. 2-4SCCh. 1.2 - Prob. 2-5SCCh. 1.2 - Prob. 2-6SCCh. 1.2 - Prob. 3-1SCCh. 1.2 - Prob. 3-2SCCh. 1.2 - Prob. 3-3SCCh. 1.2 - Prob. 3-4SCCh. 1.2 - Prob. 3-5SCCh. 1.2 - Prob. 3-6SCCh. 1.2 - Prob. 3-7SCCh. 1.2 - Prob. 3-8SCCh. 1.2 - Prob. 3-9SCCh. 1.2 - Prob. 3-10SCCh. 1.2 - Prob. 4-1SCCh. 1.2 - Prob. 4-2SCCh. 1.2 - Prob. 4-3SCCh. 1.2 - Prob. 4-4SCCh. 1.2 - Prob. 4-5SCCh. 1.2 - Prob. 4-6SCCh. 1.2 - Prob. 4-7SCCh. 1.2 - Prob. 4-8SCCh. 1.2 - Prob. 4-9SCCh. 1.2 - Prob. 4-10SCCh. 1.2 - Prob. 5-1SCCh. 1.2 - Prob. 5-2SCCh. 1.2 - Prob. 5-3SCCh. 1.2 - Prob. 5-4SCCh. 1.2 - Prob. 1SECh. 1.2 - Prob. 2SECh. 1.2 - Prob. 3SECh. 1.2 - Prob. 4SECh. 1.2 - Prob. 5SECh. 1.2 - Prob. 6SECh. 1.2 - Prob. 7SECh. 1.2 - Prob. 8SECh. 1.2 - Prob. 9SECh. 1.2 - Prob. 10SECh. 1.2 - Prob. 11SECh. 1.2 - Prob. 12SECh. 1.2 - Prob. 13SECh. 1.2 - Prob. 14SECh. 1.2 - Prob. 15SECh. 1.2 - Prob. 16SECh. 1.2 - Prob. 17SECh. 1.2 - Prob. 18SECh. 1.2 - Prob. 19SECh. 1.2 - Prob. 20SECh. 1.2 - Prob. 21SECh. 1.2 - Prob. 22SECh. 1.2 - Prob. 23SECh. 1.2 - Prob. 24SECh. 1.2 - Prob. 25SECh. 1.2 - Prob. 26SECh. 1.2 - Prob. 27SECh. 1.2 - Prob. 28SECh. 1.2 - Prob. 29SECh. 1.2 - Prob. 30SECh. 1.2 - Prob. 31SECh. 1.2 - Prob. 32SECh. 1.2 - Prob. 33SECh. 1.2 - Prob. 34SECh. 1.2 - Prob. 35SECh. 1.2 - Prob. 36SECh. 1.2 - Prob. 37SECh. 1.2 - Prob. 38SECh. 1.2 - Prob. 39SECh. 1.2 - Prob. 40SECh. 1.2 - Prob. 41SECh. 1.2 - Prob. 42SECh. 1.2 - Prob. 43SECh. 1.2 - Prob. 44SECh. 1.2 - Prob. 45SECh. 1.2 - Prob. 46SECh. 1.2 - Prob. 47SECh. 1.2 - Prob. 48SECh. 1.2 - Prob. 49SECh. 1.2 - Prob. 50SECh. 1.2 - Prob. 51SECh. 1.2 - Prob. 52SECh. 1.2 - Prob. 53SECh. 1.2 - Prob. 54SECh. 1.2 - Prob. 55SECh. 1.2 - Prob. 56SECh. 1 - Prob. 1ESCh. 1 - Prob. 2ESCh. 1 - Prob. 3ESCh. 1 - Prob. 4ESCh. 1 - Prob. 5ESCh. 1 - Prob. 6ESCh. 1 - Prob. 7ESCh. 1 - Prob. 8ESCh. 1 - Prob. 9ESCh. 1 - Prob. 10ESCh. 1 - Prob. 11ESCh. 1 - Prob. 12ESCh. 1 - Prob. 13ESCh. 1 - Prob. 14ESCh. 1 - Prob. 15ESCh. 1 - Prob. 16ESCh. 1 - Prob. 17ESCh. 1 - Prob. 18ESCh. 1 - Prob. 19ESCh. 1 - Prob. 20ESCh. 1 - Prob. 21ESCh. 1 - Prob. 22ESCh. 1 - Prob. 23ESCh. 1 - Prob. 24ESCh. 1 - Prob. 25ESCh. 1 - Prob. 26ESCh. 1 - Prob. 27ESCh. 1 - Prob. 28ESCh. 1 - Prob. 29ESCh. 1 - Prob. 30ESCh. 1 - Prob. 31ESCh. 1 - Prob. 32ESCh. 1 - Prob. 33ESCh. 1 - Prob. 34ESCh. 1 - Prob. 35ESCh. 1 - Prob. 36ESCh. 1 - Prob. 37ESCh. 1 - Prob. 38ESCh. 1 - Prob. 39ESCh. 1 - Prob. 40ESCh. 1 - Prob. 41ESCh. 1 - Prob. 42ESCh. 1 - Prob. 43ESCh. 1 - Prob. 44ESCh. 1 - Prob. 45ESCh. 1 - Prob. 46ESCh. 1 - Prob. 47ESCh. 1 - Prob. 48ESCh. 1 - Prob. 49ESCh. 1 - Prob. 50ESCh. 1 - Prob. 51ESCh. 1 - Prob. 52ESCh. 1 - Prob. 53ESCh. 1 - Prob. 54ESCh. 1 - Prob. 55ESCh. 1 - Prob. 56ESCh. 1 - Prob. 57ESCh. 1 - Prob. 58ESCh. 1 - Prob. 59ESCh. 1 - Prob. 60ESCh. 1 - Prob. 61ESCh. 1 - Prob. 62ESCh. 1 - Prob. 63ESCh. 1 - Prob. 64ESCh. 1 - Prob. 65ESCh. 1 - Prob. 66ESCh. 1 - Prob. 67ESCh. 1 - Prob. 68ESCh. 1 - Prob. 69ESCh. 1 - Prob. 70ESCh. 1 - Prob. 71ESCh. 1 - Prob. 72ESCh. 1 - Prob. 73ESCh. 1 - Prob. 74ESCh. 1 - Prob. 75ESCh. 1 - Prob. 76ESCh. 1 - Prob. 77ESCh. 1 - Prob. 78ESCh. 1 - Prob. 79ESCh. 1 - Prob. 80ESCh. 1 - Prob. 81ESCh. 1 - Prob. 82ESCh. 1 - Prob. 83ESCh. 1 - Prob. 84ESCh. 1 - Prob. 85ESCh. 1 - Prob. 86ESCh. 1 - Prob. 87ESCh. 1 - Prob. 88ESCh. 1 - Prob. 89ESCh. 1 - Prob. 1PTCh. 1 - Prob. 2PTCh. 1 - Prob. 3PTCh. 1 - Prob. 4PTCh. 1 - Prob. 5PTCh. 1 - Prob. 6PTCh. 1 - Prob. 7PTCh. 1 - Prob. 8PTCh. 1 - Prob. 9PTCh. 1 - Prob. 10PTCh. 1 - Prob. 11PTCh. 1 - Prob. 12PTCh. 1 - Prob. 13PTCh. 1 - Prob. 14PTCh. 1 - Prob. 15PTCh. 1 - Prob. 16PTCh. 1 - Prob. 17PTCh. 1 - Prob. 18PTCh. 1 - Prob. 19PTCh. 1 - Prob. 20PTCh. 1 - Prob. 21PTCh. 1 - Prob. 22PTCh. 1 - Prob. 23PTCh. 1 - Prob. 24PTCh. 1 - Prob. 25PTCh. 1 - Prob. 26PTCh. 1 - Prob. 27PTCh. 1 - Prob. 28PTCh. 1 - Prob. 29PTCh. 1 - Prob. 30PTCh. 1 - Prob. 31PTCh. 1 - Prob. 32PTCh. 1 - Prob. 1CTCh. 1 - Prob. 2CTCh. 1 - Prob. 3CTCh. 1 - Prob. 4CTCh. 1 - Prob. 5CTCh. 1 - Prob. 6CTCh. 1 - Prob. 7CTCh. 1 - Prob. 8CTCh. 1 - Prob. 9CTCh. 1 - Prob. 10CTCh. 1 - Prob. 11CTCh. 1 - Prob. 12CTCh. 1 - Prob. 1CPCh. 1 - Prob. 2CPCh. 1 - Prob. 1CS1Ch. 1 - Prob. 2CS1Ch. 1 - Prob. 3CS1Ch. 1 - Prob. 1CS2Ch. 1 - Prob. 2CS2Ch. 1 - Prob. 3CS2Ch. 1 - Prob. 1CS3Ch. 1 - Prob. 2CS3Ch. 1 - Prob. 3CS3Ch. 1 - Prob. 4CS3Ch. 1 - Prob. 5CS3
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