The function f(x) = ax² + bx + c doesn't have any roots. Prove that a(2a+3b+6c) > 0
The function f(x) = ax² + bx + c doesn't have any roots. Prove that a(2a+3b+6c) > 0
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.3: Algebraic Expressions
Problem 40E
Related questions
Question
Clarification:
1. f doesn’t have REAL roots
2. f is a quadratic, so a≠0

Transcribed Image Text:The function f(x) = ax² + bx + c
doesn't have any roots. Prove that
a(2a+3b+6c) > 0
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 16 images

Recommended textbooks for you
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage

College Algebra (MindTap Course List)
Algebra
ISBN:
9781305652231
Author:
R. David Gustafson, Jeff Hughes
Publisher:
Cengage Learning
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage

College Algebra (MindTap Course List)
Algebra
ISBN:
9781305652231
Author:
R. David Gustafson, Jeff Hughes
Publisher:
Cengage Learning