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−By · (1 ft) + Cz · (1 ft) = 0 -200(2) B(1) + Cx (3) + C₂ (2) + 30 cos 45° = 0 - — By · (2 ft) – Cx · (1 ft) + 30 lb ft. sin 45° = 0 - • B₂+C₁ = 0 Ay + By = 0 Az - 200 lb + C₂ = 0

−By · (1 ft) + Cz · (1 ft) = 0 -200(2) B(1) + Cx (3) + C₂ (2) + 30 cos 45° = 0 - — By · (2 ft) – Cx · (1 ft) + 30 lb ft. sin 45° = 0 - • B₂+C₁ = 0 Ay + By = 0 Az - 200 lb + C₂ = 0

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.2: Trigonometric Functions Of Angles
Problem 32E
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solve the system of equations

−By · (1 ft) + Cz · (1 ft) = 0 -200(2) B(1) + Cx (3) + C₂ (2) + 30 cos 45° = 0 - — By · (2 ft) – Cx · (1 ft) + 30 lb ft. sin 45° = 0 - • B₂+C₁ = 0 Ay + By = 0 Az - 200 lb + C₂ = 0
Transcribed Image Text:−By · (1 ft) + Cz · (1 ft) = 0 -200(2) B(1) + Cx (3) + C₂ (2) + 30 cos 45° = 0 - — By · (2 ft) – Cx · (1 ft) + 30 lb ft. sin 45° = 0 - • B₂+C₁ = 0 Ay + By = 0 Az - 200 lb + C₂ = 0
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