या it 11 if the mechanism is given, then using Newton's posterior formula for the derivative Lind P(0.9) × 0 0.2 0.4 0.6 0.8 1 f 0 0.12 0.48 1.1 2 3.2
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- The following equations were estimated using the data in ECONMATH, with standard errors reported under coefficients. The average class score, measured as a percentage, is about 72.2; exactly 50% of the students are male; and the average of colgpa (grade point average at the start of the term) is about 2.81. score = 32.31 + 14.32 colgpa (2.00) (0.70) n = 856, R² = .329, R = .328. 29.66 + 3.83 male + 14.57 colgpa score = (2.04) (0.74) (0.69) n = 856, R? = .349, R = .348.(1 point) Let Y be a Binomial variable counting the number of successes in 70 independent trials where the probability of success at each trial is 0.57; that is, Y - Bin(70, 0.57). Part a) Use the pbinom function in R to find P(35 0.25.Don't do the cross(x) part of the question do the rest g, a and b
- 8https://ezto.mheducation.com/ext/map/index.html?_con=con&external_browser=D0&launchUrl=https%253A%252F%252Fnet omework: Chapter 8 (Sections 8.1 through 8.5) G Saved 0 Calculate the standard error. May normality be assumed? (Round your answers to 4 decimal places.) Standard Error Normality (a) n 27, T = 0.32 %3D ts (b) n= 58, 7 = 0.45 n = 119 , TT = 0.39 Skipped (c) n 359, T = 0.004 (d) eBook Ask Print References Mc Graw HillThe National Vaccine Information Center estimates that 90% ofAmericans have had chickenpox by the time they reach adulthood. We now consider a random sampleof 120 American adults. We want to find out the probability that 110 or more people in this samplehave had chickenpox in their childhood use normal approximation to approximate the probability that 110 or more people in this samplehave had chickenpox in their childhood. Do not use continuity correction.Dave is driving on an American Interstate highway which has a speed limit of 55 mph. At 2 pm he is at milepost 110 and at 5 pm he is at milepost 290. Is this enough evidence to prove that Dave was speeding? Prove using the Mean Value Theorem.
- before every flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the aircraft. The aircraft can carry 36 passengers, and a flight has fuel and baggage that allows for a total passenger load of 6 comma 012lb. The pilot sees that the plane is full and all passengers are men. The aircraft will be overloaded if the mean weight of the passengers is greater than StartFraction 6 comma 012 lb Over 36 EndFraction equals 167 lb. What is the probability that the aircraft is overloaded? Should the pilot take any action to correct for an overloadedaircraft? Assume that weights of men are normally distributed with a mean of 172.2 lb and a standard deviation of 38.2 a. The probability is approximately (Round to four decimal places as needed.)Select the appropriate null and alternative hypothesis for the following research question: Do people who live in a urban areas prefer to stream their tv/movies more than people who live in rural areas? phat1 = proportion of people who live in urban areas that prefer to stream tv/movies phat2 = proportion of people who live in rural areas that prefer to stream tv/movies O Null Hypothesis: People who live in urban areas prefer to stream their tv/movies less than people who live in rural areas i.e. phat1 = phat2 O Null Hypothesis: People who live in urban areas prefer to stream their tv/movies more than or equal to people who live in rural areas i.e. phat1 >= phat2 Alternative Hypothesis: People who live in urban areas prefer to stream their tv/movies less than people who live in rural areas i.e. phat1 < phat2Larry is a 62% free-throw shooter, that is to say that anytime Larry attempts a free-throw, there is a 62% chance he will make it. Larry will attempt 70 free throws. Assume each attempt is independent of every other attempt. Let X be the number of free throws Larry makes out of 70 and let P^P^ be the proportion of the 70 attempts Larry makes. What is the mean of X?
- Which distribution's height begins low, increases until the middle, and then decreases such that it has a steep side and a shallow sideThe National Vaccine Information Center estimates that 90% ofAmericans have had chickenpox by the time they reach adulthood. We now consider a random sampleof 120 American adults. We want to find out the probability that 110 or more people in this samplehave had chickenpox in their childhood. Use normal approximation with continuity correction to approximate the probability that 110or more people in this sample have had chickenpox in their childhoodIf P(A) = 0.5, P(B) = 0.4, and P(A^ B) = 0.25, then P(AUB) = 0.35 0.15 0.65 0.9
