Robert stands on the topmost tier of seats in a baseball stadium and throws a ball out onto the field with a vertical upward velocity of 42 ft/s. The ball is 49 feet above the ground the moment he releases the ball. Projectile Motion Formula: h = + vot + ho g = 32 ft/s? (acceleration due to gravity) initial velocity initial height ho h = final height time

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MATH 1314 Project Spring 2022
Robert stands on the topmost tier of seats in a baseball stadium and throws a ball out onto the field
with a vertical upward velocity of 42 ft/s. The ball is 49 feet above the ground the moment he
releases the ball.
Projectile Motion Formula: h = –
gt².
+ vot + ho
g = 32 ft/s (acceleration due to gravity)
initial velocity
Vo
ho = initial height
h = final height
time
Transcribed Image Text:ckboardcdn.com blackboarda.learn.xythos.prod/584b28d6741a7/43844307X-Blackboard-Expiration=1548620000 1 / 1 + | 回の 100% | MATH 1314 Project Spring 2022 Robert stands on the topmost tier of seats in a baseball stadium and throws a ball out onto the field with a vertical upward velocity of 42 ft/s. The ball is 49 feet above the ground the moment he releases the ball. Projectile Motion Formula: h = – gt². + vot + ho g = 32 ft/s (acceleration due to gravity) initial velocity Vo ho = initial height h = final height time
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