Chapter 11.9, Problem 6OE

To determine

To find: Conjugate of given binomial.

Answer to Problem 6OE

The conjugate of $-7-3\sqrt{11}$ is $-7+3\sqrt{11}$.

Explanation of Solution

Given information:

The binomial $-7-3\sqrt{11}$ .

Formula used:

A math conjugate is formed by changing the sign between two terms in a binomial. For instance, the conjugate of $x+y$ is $x-y$ .

  $-7-3\sqrt{11}$

Recall that a conjugate is formed by changing the sign between two terms in a binomial. For instance, the conjugate of $x+y$ is $x-y$ .

So, changing the sign between both of the terms in $-7-3\sqrt{11}$ .

The conjugate of $-7-3\sqrt{11}$ is $-7+3\sqrt{11}$