Chapter 11.6, Problem 1ST

To determine

To approximate: the given square root to the nearest tenth.

Answer to Problem 1ST

  $\sqrt{0.81}=0.9$ .

Explanation of Solution

Given:

The given square root is $\sqrt{0.81}$ .

Calculation:

As the given square root is $\sqrt{0.81}$ .

Therefore, the given square root to the nearest tenth is

  $\begin{array}{l}\sqrt{0.81}=\sqrt{0.9\times 0.9}\\ =\sqrt{{0.9}^2}\left\{\text{simplify}\right\}\\ =0.9\{\because \sqrt{a^2}=a\}\\ =0.9\{\because \text{rond up to the nearest tenth}\}\end{array}$

Thus, $\sqrt{0.81}=0.9$

Hence, the value of the given square root to the nearest tenth is $\sqrt{0.81}=0.9$ .